Chapter 10: Problem 40
Solve the equation. Tell which solution method you used. \(t^{2}-16 t+65=0\)
Short Answer
Expert verified
The solutions to the equation \(t^{2}-16 t+65=0\) are \(8 + i\) and \(8 - i\). The quadratic formula was used to solve for 't'.
Step by step solution
01
Identify the coefficients
In the quadratic equation, the coefficients are as follows: a = 1, b = -16, and c = 65.
02
Apply the Quadratic Formula
The quadratic formula is \(t = [-b \pm sqrt(b^{2} - 4ac)]/2a \). Substitute the coefficients into this formula and solve for 't'.
03
Simplify the Expression Inside the Square Root
Calculate the value inside the square root, which is \(b^{2} - 4ac = (-16)^{2} - 4*1*65 = 256-260 = -4\).
04
Deal with the Negative Inside the Square Root
The value within the square root is negative. We can work with this by identifying it as \(sqrt(-1) * sqrt(4)\), where \(sqrt(-1)\) is represented as imaginary unit 'i' and \(sqrt(4)\) equals 2.
05
Calculate the Roots
Substitute the calculated square root into the quadratic formula. So, \(t = [16 \pm 2i]/2 = 8 \pm i\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool for solving any quadratic equation, which generally takes the form \(ax^2 + bx + c = 0\). It allows us to find the roots, or solutions, of the equation without needing to factor. The formula is:
Once you’ve plugged in your values, the quadratic formula can lead you to two potential types of solutions: real or complex. It all depends on the term under the square root, known as the discriminant \((b^2 - 4ac)\).
In this exercise, after plugging in \(a = 1\), \(b = -16\), and \(c = 65\), the equation becomes \(t = \frac{16 \pm \sqrt{-4}}{2}\), leading to complex solutions due to the negative discriminant.
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
- \(a\), \(b\), and \(c\) are coefficients from the equation.
- The symbol \(\pm\) indicates there will be two solutions: one using addition, and the other, subtraction.
Once you’ve plugged in your values, the quadratic formula can lead you to two potential types of solutions: real or complex. It all depends on the term under the square root, known as the discriminant \((b^2 - 4ac)\).
In this exercise, after plugging in \(a = 1\), \(b = -16\), and \(c = 65\), the equation becomes \(t = \frac{16 \pm \sqrt{-4}}{2}\), leading to complex solutions due to the negative discriminant.
Imaginary Numbers
When we encounter a negative number under a square root, we enter the realm of imaginary numbers, which are necessary for expressions like \(\sqrt{-4}\).
An imaginary number is the square root of a negative number, symbolized by 'i', where \(i = \sqrt{-1}\). It's a concept that is especially useful in complex solutions.
In this equation, \(\sqrt{-4}\) can be expanded to \(\sqrt{4} \cdot \sqrt{-1} = 2i\). Here, \(\sqrt{-1}\) is represented by \(i\).
Imaginary numbers are not "imaginary" in the sense of being fictional; they allow mathematics to deal with real-world problems where complex numbers naturally arise, such as in engineering and physics.
An imaginary number is the square root of a negative number, symbolized by 'i', where \(i = \sqrt{-1}\). It's a concept that is especially useful in complex solutions.
In this equation, \(\sqrt{-4}\) can be expanded to \(\sqrt{4} \cdot \sqrt{-1} = 2i\). Here, \(\sqrt{-1}\) is represented by \(i\).
Imaginary numbers are not "imaginary" in the sense of being fictional; they allow mathematics to deal with real-world problems where complex numbers naturally arise, such as in engineering and physics.
- i is the fundamental imaginary unit.
- It helps in solving equations that don't have real solutions.
- Combines with real numbers to form complex numbers.
Complex Solutions
Complex solutions arise when the solutions to a quadratic equation involve imaginary numbers. A complex number has two parts: a real part and an imaginary part.
For example, using the previous calculation, the roots for the equation \(t^2 - 16t + 65 = 0\) are \(8 + i\) and \(8 - i\), which are complex solutions.
Each solution here comprises:
For example, using the previous calculation, the roots for the equation \(t^2 - 16t + 65 = 0\) are \(8 + i\) and \(8 - i\), which are complex solutions.
Each solution here comprises:
- A real part: 8.
- An imaginary part: \(\pm i\).
- The horizontal axis represents the real part.
- The vertical axis represents the imaginary part.