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For a given confidence level, \(t_{d f}^{\star}\) is larger than \(z^{\star}\). Explain how \(t_{d f}^{*}\) being slightly larger than \(z^{*}\) affects the width of the confidence interval.

Short Answer

Expert verified
A wider interval reflects greater uncertainty in parameter estimation with \(t_{df}^{*}\).

Step by step solution

01

Understand the Confidence Intervals

In statistics, a confidence interval provides a range of values that reliably estimates an unknown parameter, like the population mean. It is constructed using a sample mean and a critical value (either \(z^{*}\) or \(t_{df}^{*}\)), which determines the width of the interval depending on the desired confidence level.
02

Compare Critical Values

The critical values \(z^{*}\) and \(t_{df}^{*}\) are used in constructing confidence intervals. The \(z^{*}\) value is used when the sample size is large (typically \(n > 30\)) or when the population standard deviation is known. In contrast, \(t_{df}^{*}\) is used when the sample size is small (\(n \leq 30\)) or the population standard deviation is unknown. \(t_{df}^{*}\) is slightly larger than \(z^{*}\) because it accounts for additional uncertainty when using a sample standard deviation.
03

Relation to Confidence Interval Width

The width of the confidence interval is directly affected by the critical value. Since \(t_{df}^{*}\) is larger than \(z^{*}\), using \(t_{df}^{*}\) increases the margin of error in the confidence interval formula: \[ CI = \bar{x} \pm (t_{df}^{*} \cdot \frac{s}{\sqrt{n}}) \]This increase in the critical value results in a wider confidence interval, reflecting greater uncertainty when estimating the population parameter.
04

Importance of the Wider Interval

A wider confidence interval means that the estimate of the population parameter is less precise. While it may seem less ideal, it appropriately accounts for the additional uncertainty due to smaller sample sizes and the unknown population standard deviation, providing a more accurate range that likely captures the true population parameter.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Value
The critical value is a vital component when constructing confidence intervals in statistical analysis. It helps determine the extent of variability in data, specifically when estimating population parameters based on sample data. The critical value, denoted as either \(z^{*}\) or \(t_{df}^{*}\), reflects the reliability related to a certain confidence level. Several key factors influence the choice between these two:
  • \(z^{*}\) is used when the population standard deviation is known and the sample size is sufficiently large.
  • \(t_{df}^{*}\) is employed when the sample size is smaller, and the population standard deviation is unknown.
The choice of critical value affects both accuracy and precision in estimating the parameter. The \(t_{df}^{*}\) value is slightly larger than \(z^{*}\) to account for increased variability and uncertainty in smaller samples, hence, reflecting a more conservative approach.
Population Mean
The population mean is a crucial statistical concept, representing the average of a set of values across an entire population. It is a parameter that we often aim to estimate when working with sample data. Since it's impractical to examine every member of a population, statisticians use sample means to make inferences about the population mean. Here are some essential points:
  • Sample mean is denoted as \(\bar{x}\), and it serves as an estimate of the population mean.
  • Confidence intervals are constructed to provide a range of plausible values for the population mean.
The accuracy of this estimate depends on sample size, variability, and the chosen critical value. As sample size increases, the estimate of the population mean becomes more reliable, and this increased reliability is reflected in narrower confidence intervals.
Sample Standard Deviation
The sample standard deviation \(s\) is a measure of the spread or variability of sample data. It plays a pivotal role in calculating confidence intervals for estimating population parameters. Unlike population standard deviation, which requires data from an entire population, the sample standard deviation estimates variability based solely on a sample, hence introducing a component of uncertainty. Here are some key points to note:
  • It reflects how much individual data points typically deviate from the sample mean.
  • The formula used in confidence intervals adjusts for variability captured by the sample standard deviation.
The presence of sample standard deviation in confidence interval calculation makes the intervals wider when the population standard deviation is unknown, accounting for the extra uncertainty inherent in estimating from a sample rather than the entire population.
Margin of Error
The margin of error represents the extent to which the sample statistic, such as the sample mean, can deviate from the actual population parameter. It is an important aspect of confidence intervals, which provide an estimate range for the true value. Essentially, the margin of error combines the critical value and the standard deviation of the sample data to reflect uncertainty:
  • It is calculated as \((\text{critical value} \times \frac{s}{\sqrt{n}})\), affecting the overall width of the confidence interval.
  • A higher margin of error suggests greater uncertainty and results in a wider confidence interval.
With \(t_{df}^{*}\) being larger than \(z^{*}\), the margin of error extends further, emphasizing caution in population estimation when dealing with small samples or unknown population standard deviations.

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Most popular questions from this chapter

In the early 1990's, researchers in the UK collected data on traffic flow, number of shoppers, and traffic accident related emergency room admissions on Friday the \(13^{\text {th }}\) and the previous Friday, Friday the \(6^{\text {th }}\). The histograms below show the distribution of number of cars passing by a specific intersection on Friday the \(6^{\text {th }}\) and Friday the \(13^{\text {th }}\) for many such date pairs. Also given are some sample statistics, where the difference is the number of cars on the 6 th minus the number of cars on the 13 th. \(^{20}\) $$\begin{array}{cccc} \hline & 6^{\text {th }} & 13^{\text {th }} & \text { Diff. } \\ \hline \bar{x} & 128,385 & 126,550 & 1,835 \\ s & 7,259 & 7,664 & 1,176 \\ n & 10 & 10 & 10 \\ \hline \end{array}$$ (a) Are there any underlying structures in these data that should be considered in an analysis? Explain. (b) What are the hypotheses for evaluating whether the number of people out on Friday the \(6^{\text {th }}\) is different than the number out on Friday the \(13^{\text {th }} ?\) (c) Check conditions to carry out the hypothesis test from part (b). (d) Calculate the test statistic and the p-value. (e) What is the conclusion of the hypothesis test? (f) Interpret the p-value in this context. (g) What type of error might have been made in the conclusion of your test? Explain.

A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decrease in the amount of food consumption. To test this hypothesis, they monitored food intake for a group of 44 patients who were randomized into two equal groups. The treatment group ate lunch while playing solitaire, and the control group ate lunch without any added distractions. Patients in the treatment group ate 52.1 grams of biscuits, with a standard deviation of 45.1 grams, and patients in the control group ate 27.1 grams of biscuits, with a standard deviation of 26.4 grams. Do these data provide convincing evidence that the average food intake (measured in amount of biscuits consumed) is different for the patients in the treatment group? Assume that conditions for inference are satisfied. \(^{26}\)

A market researcher wants to evaluate car insurance savings at a competing company. Based on past studies he is assuming that the standard deviation of savings is $$\$ 100$$. He wants to collect data such that he can get a margin of error of no more than $$\$ 10$$ at a \(95 \%\) confidence level. How large of a sample should he collect?

Determine if the following statements are true or false, and explain your reasoning for statements you identify as false. (a) When comparing means of two samples where \(n_{1}=20\) and \(n_{2}=40,\) we can use the normal model for the difference in means since \(n_{2} \geq 30\). (b) As the degrees of freedom increases, the \(t\) -distribution approaches normality. (c) We use a pooled standard error for calculating the standard error of the difference between means when sample sizes of groups are equal to each other.

The distribution of the number of eggs laid by a certain species of hen during their breeding period has a mean of 35 eggs with a standard deviation of \(18.2 .\) Suppose a group of researchers randomly samples 45 hens of this species, counts the number of eggs laid during their breeding period, and records the sample mean. They repeat this 1,000 times, and build a distribution of sample means. (a) What is this distribution called? (b) Would you expect the shape of this distribution to be symmetric, right skewed, or left skewed? Explain your reasoning. (c) Calculate the variability of this distribution and state the appropriate term used to refer to this value. (d) Suppose the researchers' budget is reduced and they are only able to collect random samples of 10 hens. The sample mean of the number of eggs is recorded, and we repeat this 1,000 times, and build a new distribution of sample means. How will the variability of this new distribution compare to the variability of the original distribution?

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