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A survey of 2,254 American adults indicates that \(17 \%\) of cell phone owners browse the internet exclusively on their phone rather than a computer or other device. \(^{59}\) (a) According to an online article, a report from a mobile research company indicates that 38 percent of Chinese mobile web users only access the internet through their cell phones. \(^{60}\) Conduct a hypothesis test to determine if these data provide strong evidence that the proportion of Americans who only use their cell phones to access the internet is different than the Chinese proportion of \(38 \%\). (b) Interpret the p-value in this context. (c) Calculate a \(95 \%\) confidence interval for the proportion of Americans who access the internet on their cell phones, and interpret the interval in this context.

Short Answer

Expert verified
The American proportion is significantly different from 38%, with a confidence interval of (15.5%, 18.5%).

Step by step solution

01

State Hypotheses

We are given that 17% of American cell phone owners access the internet exclusively through their phones, and 38% for Chinese users. We will test if there is a significant difference in these proportions. Set up the null hypothesis as \( H_0: p = 0.38 \) and the alternative hypothesis as \( H_a: p eq 0.38 \), where \( p \) is the proportion of American cell phone owners using their phones exclusively to browse the internet.
02

Determine Test Statistic

The test statistic for a hypothesis test for proportions can be calculated using the standard formula for the z-score: \( z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}} \). Here, \( \hat{p} = 0.17 \), \( p_0 = 0.38 \), and \( n = 2254 \). Substitute these values to find the z-value.
03

Compute Z-Score

Calculate the z-score using the formula: \( z = \frac{0.17 - 0.38}{\sqrt{\frac{0.38 \times (1 - 0.38)}{2254}}} \). This calculation yields \( z \approx -28.23 \).
04

Find P-Value

A z-score of approximately \(-28.23\) is extremely large in magnitude, so the p-value is extremely small, effectively 0 in most practical situations. This indicates a very strong deviation from the null hypothesis.
05

Conclusion for Hypothesis Test

Since the p-value is effectively 0, which is less than any common significance level (e.g., 0.05), we reject the null hypothesis. There is strong evidence that the proportion of Americans who use only their cell phones to access the internet is different from 38%.
06

Interpret the P-Value

The p-value of nearly 0 indicates that the observed difference in internet usage habits between Americans and Chinese is highly unlikely under the null hypothesis. Therefore, it suggests the proportions are significantly different.
07

Confidence Interval Setup

To calculate a 95% confidence interval for the proportion of Americans who exclusively use their cell phones, we use the formula: \( \hat{p} \pm z^* \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} \), where \( \hat{p} = 0.17 \), \( n = 2254 \), and \( z^* \approx 1.96 \) for a 95% confidence level.
08

Calculate Confidence Interval

Substitute the values into the interval formula: \( 0.17 \pm 1.96 \times \sqrt{\frac{0.17 \times 0.83}{2254}} \). This calculation gives the interval approximately \( (0.155, 0.185) \).
09

Interpret Confidence Interval

The 95% confidence interval for the proportion of Americans who use only their phones for internet access is approximately \( (15.5\%, 18.5\%) \). This means we are 95% confident that the true proportion lies within this range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Difference
Understanding the difference between proportions is crucial in hypothesis testing when comparing two groups. In this exercise, we are comparing two proportions: the proportion of American cell phone users who access the internet exclusively on their phones, and the proportion for Chinese users. The former is 17% and the latter is 38%.
When comparing proportions, the null hypothesis typically states that there is no difference between the two groups. This means the null hypothesis would be that both proportions are equal.
  • Null Hypothesis (\( H_0 \)): The proportion of American users (\( p \)) is equal to the proportion of Chinese users (\( p_0 = 0.38 \)).
  • Alternative Hypothesis (\( H_a \)): The proportion of American users is not equal to the proportion of Chinese users.
The next step involves calculating the test statistic, which for proportions, can be done using the z-score formula. This calculation helps us understand how much the observed proportion of American users deviate from what we would expect if the null hypothesis were true. A significantly high or low z-score indicates that the proportion difference is meaningful and not due to random chance.
Confidence Interval
A confidence interval gives us a range of values in which we believe the true proportion of a population parameter lies, based on sample data. In this problem, we aim to estimate the proportion of American cell phone users who exclusively access the internet on their phones. The confidence interval provides insight into the reliability of our sample statistic as an estimate of the true population parameter.Given a sample proportion (\( \hat{p} \)) of 0.17, we can calculate a 95% confidence interval. This involves using the formula:\[\hat{p} \pm z^* \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}\]
  • \(\hat{p} = 0.17\)
  • Sample size (\( n \)) = 2254
  • Z-score for 95% confidence (\( z^*\)) ≈ 1.96
Plug these values into the formula to find the interval, calculating it as approximately (0.155, 0.185). This means that we are 95% confident that the true proportion of American cell phone users who use only their phones to access the internet is between 15.5% and 18.5%.
P-value Interpretation
The p-value is a crucial part of hypothesis testing. It helps us determine the strength of evidence against the null hypothesis. It essentially tells us the probability of the observed data, or something more extreme, occurring under the assumption that the null hypothesis is true.
In this exercise, upon calculating the test statistic for comparing the proportions of American and Chinese users, the resulting p-value was found to be effectively zero.
  • This extremely low p-value suggests that the observed difference in internet browsing habits between Americans and Chinese is highly unlikely to occur by random chance.
  • As the p-value is less than any conventional significance levels (e.g., 0.05), we reject the null hypothesis.
Thus, we conclude that there is statistically significant evidence that the proportion of American and Chinese cell phone users who exclusively surf the internet on their phones is indeed different.

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