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Game of dreidel. A dreidel is a four-sided spinning top with the Hebrew letters nun, gimel, hei, and shin, one on each side. Each side is equally likely to come up in a single spin of the dreidel. Suppose you spin a dreidel three times. Calculate the probability of getting (a) at least one nun? (b) exactly 2 nuns? (c) exactly 1 hei? (d) at most 2 gimels?

Short Answer

Expert verified
(a) \( \frac{37}{64} \), (b) \( \frac{9}{64} \), (c) \( \frac{27}{64} \), (d) \( \frac{63}{64} \).

Step by step solution

01

Understanding the Problem

A dreidel has four sides, each with an equal chance of landing in one of four possible outcomes: nun, gimel, hei, and shin. Each spin of the dreidel is independent of the others. We need to calculate the following probabilities over three spins: (a) at least one nun, (b) exactly two nuns, (c) exactly one hei, (d) at most two gimels.
02

Calculating Probability of At Least One Nun

To find the probability of getting at least one nun in three spins, it's easier to use the complement rule. First, find the probability of getting no nuns in all three spins. The probability of not getting a nun in one spin is \( \frac{3}{4} \) (since there are three other outcomes). Thus, the probability of not getting any nun in three spins is \( \left( \frac{3}{4} \right)^3 = \frac{27}{64} \). Therefore, the probability of getting at least one nun is \( 1 - \frac{27}{64} = \frac{37}{64} \).
03

Calculating Probability of Exactly Two Nuns

For exactly two nuns in three spins, use the binomial probability formula. Let X be the number of nuns spun, which follows a binomial distribution: \( X \sim B(n=3, p=\frac{1}{4}) \). The probability mass function is given by \( P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \), where \( k = 2 \): \[ P(X=2) = \binom{3}{2} \left(\frac{1}{4}\right)^2 \left(\frac{3}{4}\right)^1 = 3 \times \frac{1}{16} \times \frac{3}{4} = \frac{9}{64} \].
04

Calculating Probability of Exactly One Hei

Similar to the previous step, compute the probability of getting exactly one hei. This again uses the binomial distribution with \( n = 3 \) and \( p = \frac{1}{4} \), letting \( X' \, , \) the number of heis be: \[ P(X'=1) = \binom{3}{1} \left(\frac{1}{4}\right)^1 \left(\frac{3}{4}\right)^2 = 3 \times \frac{1}{4} \times \frac{9}{16} = \frac{27}{64} \].
05

Calculating Probability of At Most Two Gimels

Here we must find the probability of getting 0, 1, or 2 gimels. Use the binomial distribution with \(n=3\) and \(p=\frac{1}{4}\) for gimels, summing probabilities for \(X'' = 0\), \(X'' = 1\), and \(X'' = 2\):- \(P(X''=0) = \binom{3}{0} \left(\frac{1}{4}\right)^0 \left(\frac{3}{4}\right)^3 = \frac{27}{64}\)- \(P(X''=1) = \binom{3}{1} \left(\frac{1}{4}\right)^1 \left(\frac{3}{4}\right)^2 = \frac{27}{64}\)- \(P(X''=2) = \binom{3}{2} \left(\frac{1}{4}\right)^2 \left(\frac{3}{4}\right)^1 = \frac{9}{64}\)Summing them gives \(P(0 \leq X'' \leq 2) = \frac{27}{64} + \frac{27}{64} + \frac{9}{64} = \frac{63}{64} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Binomial Distribution
In statistics, the binomial distribution is a common method for analyzing experiments where only two possible outcomes exist, like 'success' or 'failure.' It's great for situations where you repeat an experiment several times. For example, when you spin a dreidel, each side ("nun," "hei," etc.) has an equal chance of showing up, which is a classic case of a binomial distribution. This distribution is characterized by two parameters:
  • "n," which is the number of trials (spins, in this case), and
  • "p," the probability of success on an individual trial.
The random variable "X" represents the number of successes in "n" trials and follows the binomial distribution model. In our dreidel game, calculating the probability of getting exactly 2 "nuns" in 3 spins is modeled as a binomial distribution of \( X \sim B(n=3, p=\frac{1}{4}) \), where "p" represents the probability of a "nun" occurring in a single spin. The probability mass function used for these calculations is \( P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \), allowing us to find the probability of a specific number of successes (e.g., two "nuns") among trials.
Exploring the Complement Rule
The complement rule is a useful tool in probability when calculating the likelihood of an event occurring is tricky. Instead, we can compute the probability of the opposite event (the complement) and subtract it from 1. For instance, if we want to calculate the probability of getting at least one "nun" in three spins, it might seem complex. However, using the complement rule simplifies the process:
  • First, calculate the probability of not spinning "nun" at all in three spins.
  • The probability of not getting a "nun" in one spin is \( \frac{3}{4} \).
  • Thus, the probability of no "nun" in all three trials is \( \left( \frac{3}{4} \right)^3 = \frac{27}{64} \).
After finding out the complement, the desired probability for at least one "nun" is \( 1 - \frac{27}{64} = \frac{37}{64} \). This method not only saves time but also reduces the risk of errors in calculation, making it easier to tackle complex probability problems.
Executing Probability Calculations
Doing probability calculations might initially seem daunting, but breaking it into manageable steps can simplify it significantly. When dealing with small independent events, like spinning a dreidel, each event can be evaluated on its own terms and then combined as needed. Each side of our dreidel is equally likely to appear in a spin.To calculate for multiple events, follow these essential steps:
  • Determine the probability of each individual event; for example, the chance of a side like "hei" appearing in one spin is \( \frac{1}{4} \).
  • When looking for the probability of specific occurrences across trials, apply the binomial distribution properties where appropriate.
  • For example, the probability of spinning exactly one "hei" can be calculated by applying the binomial formula \( P(X'=1) = \binom{3}{1} \left( \frac{1}{4} \right)^1 \left( \frac{3}{4} \right)^2 \), resulting in \( \frac{27}{64} \).
By systematically following these steps, the paths to determining probabilities become clearer and more accessible. Calculations like these allow deeper insight into understanding seemingly random events.

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