/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Sally gets a cup of coffee and a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sally gets a cup of coffee and a muffin every day for breakfast from one of the many coffee shops in her neighborhood. She picks a coffee shop each morning at random and independently of previous days. The average price of a cup of coffee is \(\$ 1.40\) with a standard deviation of \(30 \mathrm{c}(\$ 0.30),\) the average price of a muffin is \(\$ 2.50\) with a standard deviation of \(15 \mathrm{c},\) and the two prices are independent of each other. (a) What is the mean and standard deviation of the amount she spends on breakfast daily? (b) What is the mean and standard deviation of the amount she spends on breakfast weekly ( 7 days)?

Short Answer

Expert verified
Daily mean: $3.90, SD: $0.335; Weekly mean: $27.30, SD: $0.887.

Step by step solution

01

Calculate Daily Mean Cost

To find the mean daily cost of breakfast, sum the average price of a cup of coffee and a muffin. The mean daily cost is calculated by adding the average costs: \[\text{Mean Daily Cost} = \\(1.40 + \\)2.50 = \$3.90\]
02

Calculate Daily Standard Deviation

The standard deviation of the total cost is found by combining the standard deviations of the coffee and muffin, since the prices are independent. Use the formula for the standard deviation of the sum of independent random variables: \[\sigma = \sqrt{\sigma_1^2 + \sigma_2^2}\]Given \(\sigma_1 = 0.30\) and \(\sigma_2 = 0.15\), the daily standard deviation is:\[\sqrt{(0.30)^2 + (0.15)^2} = \sqrt{0.09 + 0.0225} = \sqrt{0.1125} \approx 0.335\]
03

Weekly Mean Cost Calculation

The mean weekly cost is found by multiplying the mean daily cost by the number of days in a week (7):\[\text{Mean Weekly Cost} = 7 \times 3.90 = \$27.30\]
04

Calculate Weekly Standard Deviation

For the week, the standard deviation increases by a factor of the square root of the number of days because the costs are independent:\[\text{Weekly Standard Deviation} = \sqrt{7} \times 0.335 \]Calculate the standard deviation:\[\approx 0.335 \times 2.64575 \approx 0.887\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
Understanding mean calculation is crucial for analyzing daily expenses. In this exercise, we found Sally's mean daily cost for breakfast by adding the average price of her coffee and muffin.
  • The average price of a cup of coffee is \(1.40.
  • The average price of a muffin is \)2.50.
To calculate the mean cost, we simply add these two amounts: \[\text{Mean Daily Cost} = 1.40 + 2.50 = 3.90\] Therefore, Sally spends on average $3.90 each day for her breakfast. It's important to note that the mean gives us a central value around which other values are distributed, making it a helpful summary statistic.
Standard Deviation
Standard deviation tells us how much variation or spread there is in a set of values. A lower standard deviation implies that the values are close to the mean, while a higher standard deviation indicates more variation.
When calculating the standard deviation for the total cost of independent expenses (like Sally's coffee and muffin), we use the formula:\[\sigma = \sqrt{\sigma_1^2 + \sigma_2^2}\]Here, \(\sigma_1 = 0.30\) for the coffee and \(\sigma_2 = 0.15\) for the muffin. Calculating these gives us:\[\sqrt{0.30^2 + 0.15^2} = \sqrt{0.1125} \approx 0.335\]This standard deviation of $0.335 tells us the amount of variation in her daily expense.
Independent Random Variables
Independent random variables are those whose outcomes do not affect each other. In Sally's case, the prices of coffee and muffins are independent.
This means the variation in coffee prices does not influence muffin prices and vice versa. When calculating the standard deviation for the total expense, we leveraged this independence.
  • This property allows us to sum the variances (square of standard deviations) when finding the overall standard deviation.
  • If they were not independent, the calculation would require additional correlation information.
Understanding the concept of independence helps in accurate statistical analysis, especially when combining different random variables.
Cost Analysis
Cost analysis provides insights into spending habits over a defined period. By analyzing both daily and weekly costs, you can identify patterns and budget effectively.
In Sally's case, we found her weekly expected costs by multiplying her daily average by 7 (the number of days in a week):\[\text{Mean Weekly Cost} = 7 \times 3.90 = 27.30\]Similarly, to find her weekly standard deviation, we multiply the daily standard deviation by the square root of 7:\[\text{Weekly Standard Deviation} = \sqrt{7} \times 0.335 \approx 0.887\]This analysis reveals that over a week, Sally's expenses are not just a linear expansion from daily expenses as the variability also increases, reflecting more possible fluctuation in total spending.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

After an introductory statistics course, \(80 \%\) of students can successfully construct box plots. Of those who can construct box plots, \(86 \%\) passed, while only \(65 \%\) of those students who could not construct box plots passed. (a) Construct a tree diagram of this scenario. (b) Calculate the probability that a student is able to construct a box plot if it is known that he passed.

Consider the following card game with a well-shuffled deck of cards. If you draw a red card, you win nothing. If you get a spade, you win \(\$ 5\). For any club, you win \(\$ 10\) plus an extra \(\$ 20\) for the ace of clubs. (a) Create a probability model for the amount you win at this game. Also, find the expected winnings for a single game and the standard deviation of the winnings. (b) What is the maximum amount you would be willing to pay to play this game? Explain your reasoning.

Poverty and language. The American Community Survey is an ongoing survey that provides data every year to give communities the current information they need to plan investments and services. The 2010 American Community Survey estimates that \(14.6 \%\) of Americans live below the poverty line, \(20.7 \%\) speak a language other than English (foreign language) at home, and \(4.2 \%\) fall into both categories. \({ }^{22}\) (a) Are living below the poverty line and speaking a foreign language at home disjoint? (b) Draw a Venn diagram summarizing the variables and their associated probabilities. (c) What percent of Americans live below the poverty line and only speak English at home? (d) What percent of Americans live below the poverty line or speak a foreign language at home? (e) What percent of Americans live above the poverty line and only speak English at home? (f) Is the event that someone lives below the poverty line independent of the event that the person speaks a foreign language at home?

Below are four versions of the same game. Your archnemesis gets to pick the version of the game, and then you get to choose how many times to flip a coin: 10 times or 100 times. Identify how many coin flips you should choose for each version of the game. It costs \(\$ 1\) to play each game. Explain your reasoning. (a) If the proportion of heads is larger than \(0.60,\) you win \(\$ 1\). (b) If the proportion of heads is larger than 0.40 , you win \(\$ 1\). (c) If the proportion of heads is between 0.40 and 0.60 , you win \(\$ 1\). (d) If the proportion of heads is smaller than \(0.30,\) you win \(\$ 1\).

Swaziland has the highest HIV prevalence in the world: \(25.9 \%\) of this country's population is infected with HIV. \(^{88}\) The ELISA test is one of the first and most accurate tests for HIV. For those who carry HIV, the ELISA test is \(99.7 \%\) accurate. For those who do not carry HIV, the test is \(92.6 \%\) accurate. If an individual from Swaziland has tested positive, what is the probability that he carries HIV?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.