Evaluate by the divergence theorem:
a) \(\iint_{S} x d y d z+y d z d x+z d x d y\), where \(S\) is the sphere
\(x^{2}+y^{2}+z^{2}=1\) and \(\mathbf{n}\) is the outer normal;
b) \(\iint_{S} v_{n} d \sigma\), where \(\mathbf{v}=x^{2} \mathbf{i}+y^{2}
\mathbf{j}+z^{2} \mathbf{k}, \mathbf{n}\) is the outer normal and \(S\) is the
surface of the cube \(0 \leq x \leq 1,0 \leq y \leq 1,0 \leq z \leq 1\);
c) \(\iint_{S} e^{y} \cos z d y d z+e^{x} \sin z d z d x+e^{x} \cos y d x d y\),
with \(S\) and \(\mathbf{n}\) as in (a);
d) \(\iint_{S} \nabla F \cdot \mathbf{n} d \sigma\) if \(F=x^{2}+y^{2}+z^{2},
\mathbf{n}\) is the exterior normal, and \(S\) bounds a solid region \(R\);
e) \(\iint_{S} \nabla F \cdot \mathbf{n} d \sigma\) if \(F=2 x^{2}-y^{2}-z^{2}\),
with \(\mathbf{n}\) and \(S\) as in (d);
f) \(\iint_{S} \nabla F \cdot \mathbf{n} d \sigma\) if
\(F=\left[(x-2)^{2}+y^{2}+z^{2}\right]^{-1 / 2}\) and \(S\) and \(\mathbf{n}\) are
as in (a).