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Find \(\mathbf{a} \cdot \mathbf{b}\) if \(|\mathbf{a}|=9,|\mathbf{b}|=10,\) and the angle between \(\mathbf{a}\) and \(\mathbf{b}\) is \(-\frac{\pi}{3}\) radians. \(\mathbf{a} \cdot \mathbf{b}=\)________

Short Answer

Expert verified
The dot product of \(\mathbf{a}\) and \(\mathbf{b}\) is 45.

Step by step solution

01

Write down the given information

We are given the magnitudes of vectors \(\mathbf{a}\) and \(\mathbf{b}\), and the angle between them: - Magnitude of \(\mathbf{a}\): \(|\mathbf{a}| = 9\) - Magnitude of \(\mathbf{b}\): \(|\mathbf{b}| = 10\) - Angle between \(\mathbf{a}\) and \(\mathbf{b}\): \(\theta = -\frac{\pi}{3}\) radians
02

Use the formula for the dot product

Now, we can use the formula for the dot product in terms of magnitudes and angle: \(\mathbf{a} \cdot \mathbf{b} = |\mathbf{a}| |\mathbf{b}| \cos{\theta}\) Substitute the given values into the formula: \(\mathbf{a} \cdot \mathbf{b} = 9 \cdot 10 \cdot \cos{\left(-\frac{\pi}{3}\right)}\)
03

Compute the dot product

Evaluate the expression: \(\mathbf{a} \cdot \mathbf{b} = 90 \cdot \cos{\left(-\frac{\pi}{3}\right)}\) Since \(\cos{(-x)} = \cos{x}\), we can simplify further: \(\mathbf{a} \cdot \mathbf{b} = 90 \cdot \cos{\left(\frac{\pi}{3}\right)}\) We know that \(\cos{\frac{\pi}{3}} = \frac{1}{2}\), so: \(\mathbf{a} \cdot \mathbf{b} = 90 \cdot \frac{1}{2} = 45\) So, the dot product of \(\mathbf{a}\) and \(\mathbf{b}\) is 45.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vectors
Vectors are mathematical entities that have both magnitude and direction. They are commonly used in physics and engineering to represent quantities like force, velocity, and displacement. In mathematical terms, a vector can be visualized as an arrow pointing in a particular direction, with its length representing the magnitude.

Vectors can be denoted by symbols such as \(\mathbf{a}\) and \(\mathbf{b}\), and their magnitudes are represented as \(|\mathbf{a}|\) and \(|\mathbf{b}|\) respectively. In a vector space, vectors can be added, subtracted, and multiplied by a scalar, following specific rules.

An important operation involving vectors is the dot product (also known as scalar product). The dot product is a way to multiply two vectors to obtain a scalar quantity. It is calculated using the magnitudes of the vectors and the cosine of the angle between them. This operation helps in determining the extent to which two vectors align with each other. Understanding vectors and their properties lays the foundation for exploring more complex mathematical and physical phenomena.
Angle Between Vectors
The angle between vectors is a crucial concept in understanding vector relationships. This angle helps determine how two vectors are oriented relative to each other.

To find the angle between two vectors \(\mathbf{a}\) and \(\mathbf{b}\), you can use the dot product formula:\[\mathbf{a} \cdot \mathbf{b} = |\mathbf{a}| |\mathbf{b}| \cos{\theta}\]

Here, \(\theta\) is the angle between the vectors, and \(|\mathbf{a}|\) and \(|\mathbf{b}|\) are their magnitudes. By rearranging this formula, you can solve for \(\theta\) if needed.

The cosine of the angle indicates whether the vectors are pointing in similar or opposite directions:
  • Positive cosine values (greater than zero) imply the vectors are pointing somewhat in the same direction.
  • Zero means they are perpendicular (at a right angle).
  • Negative cosine values suggest they are pointing in opposite directions.
This understanding is essential in various fields, including physics and computer graphics, where it's crucial to know how objects (represented as vectors) interact with each other.
Trigonometry Concepts
Trigonometry is a branch of mathematics dealing with angles and sides of triangles. It is of great importance when dealing with vectors, as it allows for calculating distances and angles between objects in space.

When you use the dot product formula \(\mathbf{a} \cdot \mathbf{b} = |\mathbf{a}| |\mathbf{b}| \cos{\theta}\), you're directly employing trigonometric concepts. Here, \(\cos{\theta}\) is a trigonometric function that gives the cosine of the angle \(\theta\). In context, cosine relates the angle to the adjacent side and hypotenuse of a right-angled triangle.

A few key trigonometric concepts often apply in vector mathematics, including:
  • Sine, Cosine, and Tangent: Fundamental ratios in right triangles.

  • Unit Circle: A circle with a radius of one, used to define trigonometric functions at various angles.

  • Radians: An alternative to degrees for measuring angles, where \(2\pi\) radians equal 360 degrees.

Understanding these concepts allows one to solve problems involving angles and lengths in a wide range of mathematical and real-world problems.

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Most popular questions from this chapter

Molecular geometry is the geometry determined by arrangements of atoms in molecules. Molecular geometry includes measurements like bond angle, bond length, and torsional angles. These attributes influence several properties of molecules, such as reactivity, color, and polarity. As an example of the molecular geometry of a molecule, consider the methane \(\mathrm{CH}_{4}\) molecule, as illustrated in Figure \(9.3 .9 .\) According to the Valence Shell Electron Repulsion (VSEPR) model, atoms that surround single different atoms do so in a way that positions them as far apart as possible. This means that the hydrogen atoms in the methane molecule arrange themselves at the vertices of a regular tetrahedron. The bond angle for methane is the angle determined by two consecutive hydrogen atoms and the central carbon atom. To determine the bond angle for methane, we can place the center carbon atom at the point \(\left(\frac{1}{2}, \frac{1}{2}, \frac{1}{2}\right)\) and the hydrogen atoms at the points \((0,0,0),(1,1,0),(1,0,1),\) and (0,1,1) . Find the bond angle for methane to the nearest tenth of a degree.

Find a vector parametrization of the circle of radius 7 in the xy-plane, centered at the origin, oriented clockwise so that the point (7,0) corresponds to \(t=0\) and the point (0,-7) corresponds to \(t=1\). \(\vec{r}(t)=\)_________

Find the angle in radians between the planes \(4 x+z=1\) and \(5 y+z=1\).

Suppose \(\vec{r}(t)=\cos (\pi t) \boldsymbol{i}+\sin (\pi t) \boldsymbol{j}+3 t \boldsymbol{k}\) represents the position of a particle on a helix, where \(z\) is the height of the particle. (a) What is \(t\) when the particle has height \(6 ?\) t= ______ (b) What is the velocity of the particle when its height is \(6 ?\) \(\vec{v}=\) _______ (c) When the particle has height \(6,\) it leaves the helix and moves along the tangent line at the constant velocity found in part (b). Find a vector parametric equation for the position of the particle (in terms of the original parameter \(t\) ) as it moves along this tangent line. \(L(t)=\) ________

Let \(y=f(x)\) define a curve in the plane. We can consider this curve as a curve in three-space with \(z\) -coordinate \(0 .\) a. Find a parameterization of the form \(\mathbf{r}(t)=\langle x(t), y(t), z(t)\rangle\) of the curve \(y=f(x)\) in three-space. b. Use the formula $$ \kappa=\frac{\left|\mathbf{r}^{\prime}(t) \times \mathbf{r}^{\prime \prime}(t)\right|}{\left|\mathbf{r}^{\prime}(t)\right|^{3}} $$ to show that $$ \kappa=\frac{\left|f^{\prime \prime}(x)\right|}{\left[1+\left(f^{\prime}(x)\right)^{2}\right]^{3 / 2}} $$

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