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The domain of the function \(f(x, y)=\sqrt{x}+\sqrt{y}\) is ________.

Short Answer

Expert verified
The domain of the function \(f(x, y) = \sqrt{x} + \sqrt{y}\) is \([0, +\infty) \times [0, +\infty)\).

Step by step solution

01

Identify the function

We are given the function \(f(x, y) = \sqrt{x} + \sqrt{y}\).
02

Find the restrictions for x and y

Since the function contains square roots, we know that the values inside the square roots must be greater than or equal to 0. So, we have the following restrictions for x and y: 1. \(x \geq 0\) 2. \(y \geq 0\)
03

Determine the domain of the function

Based on the restrictions for x and y, the domain of the function f(x, y) is the set of all points (x, y) such that x and y are both greater than or equal to 0. In interval notation, the domain of the function can be represented as: \[Domain(f(x, y)) = [0, +\infty) \times [0, +\infty)\] So the domain of the function \(f(x, y) = \sqrt{x} + \sqrt{y}\) is \([0, +\infty) \times [0, +\infty)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Domain
When working with functions in multivariable calculus, understanding the concept of the "domain" is crucial. The domain of a function is the set of all possible input values (or combinations of inputs for multivariable functions) that will produce a valid output. For example, if you have the function \(f(x, y) = \sqrt{x} + \sqrt{y}\), the domain encompasses all pairs of \(x\) and \(y\) that can be used within this function without causing any mathematical issues like division by zero or taking the square root of a negative number.

To determine this set, you need to look at the structure of the function. In the example given, the function involves square roots. This informs us that both \(x\) and \(y\) need to be non-negative because the square root is not defined for negative numbers in the real number system. Hence, the domain of \(f(x, y)\) is all points \((x, y)\) such that both \(x\) and \(y\) are greater than or equal to zero. This ensures that each square root component is defined and thus makes the entire expression valid.

In practical problems, clearly identifying the domain helps us understand the limitations of a function's operation and prepares us for further analysis, such as finding and interpreting limits and derivatives.
Square Roots
Square roots are a fundamental mathematical operation, especially important in calculus and solving various functions. The square root of a number \(a\), denoted as \(\sqrt{a}\), is a value that, when multiplied by itself, gives \(a\). For example, \(\sqrt{9} = 3\) because \(3 \times 3 = 9\).

In multivariable calculus, we often deal with square roots involving variables. When examining the domain of functions with square roots, it is important to recognize that the number or expression under the square root must be non-negative. This is because, in real numbers, you cannot take the square root of a negative number without entering the realm of complex numbers.

For instance, if we have \(\sqrt{x}\) as part of a function, \(x\) must be at least zero. Similarly, for the function \(f(x, y) = \sqrt{x} + \sqrt{y}\), both \(x\) and \(y\) must be \(\geq 0\). Starting from this understanding helps in logically determining the domain of such functions, ensuring correctness in analysis and computation.
Interval Notation
Interval notation offers a concise way to describe the set of numbers that form the domain of a function. It allows you to capture ranges of values clearly and efficiently, which is especially useful in calculus where continuous ranges are common.

An interval like \([0, +\infty)\) denotes all numbers from 0 to infinity, inclusive of 0. The square bracket \([\ \) means the endpoint is included in the interval, while the parenthesis \() \) indicates it is not. Therefore, \([0, +\infty)\) includes 0 and all positive numbers indefinitely near infinity.

In multivariable functions such as \(f(x, y) = \sqrt{x} + \sqrt{y}\), the domain in interval notation becomes \([0, +\infty) \times [0, +\infty)\). The multiplication symbol \(\times\) signifies that both intervals apply simultaneously; \(x\) and \(y\) must satisfy \([0, +\infty)\) each independently. So, this notation compactly indicates that both variables can take any non-negative value.

Mastering interval notation helps in communicating and understanding the domains and ranges of functions efficiently, simplifying both problem-solving and discussion.

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Most popular questions from this chapter

A truck is traveling due north at \(40 \mathrm{~km} / \mathrm{hr}\) approaching a crossroad. On a perpendicular road a police car is traveling west toward the intersection at \(35 \mathrm{~km} / \mathrm{hr}\). Both vehicles will reach the crossroad in exactly one hour. Find the vector currently representing the displacement of the truck with respect to the police car. displacement \(\vec{d}=\)_________

Consider the two vector-valued functions given by $$ \mathbf{r}(t)=\left\langle t+1, \cos \left(\frac{\pi}{2} t\right), \frac{1}{1+t}\right\rangle $$ and $$ \mathbf{w}(s)=\left\langle s^{2}, \sin \left(\frac{\pi}{2} s\right), s\right\rangle $$ a. Determine the point of intersection of the curves generated by \(\mathbf{r}(t)\) and \(\mathbf{w}(s) .\) To do so, you will have to find values of \(a\) and \(b\) that result in \(\mathbf{r}(a)\) and \(\mathbf{w}(b)\) being the same vector. b. Use the value of \(a\) you determined in (a) to find a vector form of the tangent line to \(\mathbf{r}(t)\) at the point where \(t=a\) c. Use the value of \(b\) you determined in (a) to find a vector form of the tangent line to \(\mathbf{w}(s)\) at the point where \(s=b\). d. Suppose that \(z=f(x, y)\) is a function that generates a surface in three- dimensional space, and that the curves generated by \(\mathbf{r}(t)\) and \(\mathbf{w}(s)\) both lie on this surface. Note particularly that the point of intersection you found in (a) lies on this surface. In addition, observe that the two tangent lines found in (b) and (c) both lie in the tangent plane to the surface at the point of intersection. Use your preceding work to determine the equation of this tangent plane.

In this problem, we explore how we can use what we know about vectors and projections to find the distance from a point to a plane. Let \(p\) be the plane with equation \(z=-4 x+3 y+4,\) and let \(Q=\) (4,-1,8) a. Show that \(Q\) does not lie in the plane \(p\). b. Find a normal vector \(\mathbf{n}\) to the plane \(p\). c. Find the coordinates of a point \(P\) in \(p\). d. Find the components of \(\overrightarrow{P Q}\). Draw a picture to illustrate the objects found so far. e. Explain why \(\left|\operatorname{comp}_{\mathbf{n}} \overrightarrow{P Q}\right|\) gives the distance from the point \(Q\) to the plane \(p\). Find this distance.

Which is traveling faster, a car whose velocity vector is \(26 \vec{i}+31 \vec{j},\) or a car whose velocity vector is \(40 \vec{i}\), assuming that the units are the same for both directions? \((\square\) the first car \(\square\) the second car) is the faster car. At what speed is the faster car traveling? speed \(=\)_________

For each of the following, perform the indicated operations on the vectors $$ \vec{a}=5 \tilde{j}+\tilde{k}, \vec{b}=\tilde{i}+5 \tilde{j}+\tilde{k}, \vec{z}=\tilde{i}+4 \tilde{j} $$ (a) \(5 \vec{a}+4 \vec{b}=\)_________ (b) \(4 \vec{a}+5 \vec{b}-5 \vec{z}=\)_________

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