/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 If \(\mathbf{a}=\mathbf{i}+\math... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

If \(\mathbf{a}=\mathbf{i}+\mathbf{j}+3 \mathbf{k}\) and \(\mathbf{b}=\mathbf{i}+\mathbf{j}+2 \mathbf{k}\) Compute the cross product \(\mathbf{a} \times \mathbf{b}\). \(\mathbf{a} \times \mathbf{b}=\)_________ \(\mathbf{i}+\)_________\(\mathbf{j}+\) _________\(\mathrm{k}\)

Short Answer

Expert verified
\(-1\mathbf{i}+1\mathbf{j}+0\mathrm{k}\)

Step by step solution

01

Write a and b as components

Given \(\mathbf{a}=\mathbf{i}+\mathbf{j}+3 \mathbf{k}\) and \(\mathbf{b}=\mathbf{i}+\mathbf{j}+2 \mathbf{k}\). We have the components as: \(\mathbf{a} = (1, 1, 3)\) and \(\mathbf{b} = (1, 1, 2)\).
02

Set up a matrix to compute the cross product

We need to compute \(\mathbf{a} \times \mathbf{b} = (\mathbf{i}, \mathbf{j}, \mathbf{k})\times (\mathbf{a}, \mathbf{b})\), where \(\times\) denotes the cross product. We set up the following matrix to compute the cross product: \[\begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 1 & 1 & 3 \\ 1 & 1 & 2 \end{vmatrix}\]
03

Expand the determinant and compute the cross product

The determinant of this matrix can be computed by using the cofactor expansion method: \[\begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 1 & 1 & 3 \\ 1 & 1 & 2 \end{vmatrix} = (\mathbf{i} \begin{vmatrix} 1 & 3 \\ 1 & 2 \end{vmatrix} - \mathbf{j}\begin{vmatrix} 1 & 3 \\ 1 & 2 \end{vmatrix} + \mathbf{k} \begin{vmatrix} 1 & 1 \\ 1 & 1 \end{vmatrix}) \] Calculating each of the determinants, we get: \[\mathbf{i}(1\cdot 2 - 1\cdot 3) - \mathbf{j}(1\cdot 2 - 1\cdot 3) + \mathbf{k}(1\cdot 1 - 1\cdot 1)\] Now, simplifying the expression: \[\mathbf{i}(-1) - \mathbf{j}(-1) + \mathbf{k}(0)\]
04

Write final cross product

The final cross product of the two vectors is: \[\mathbf{a} \times \mathbf{b} = -\mathbf{i} + \mathbf{j} + 0\cdot\mathbf{k}\] So, the answer is: \(\mathbf{a} \times \mathbf{b}=\)\(-1\mathbf{i}+1\mathbf{j}+0\mathrm{k}\)$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross Product
The cross product of two vectors is a fundamental operation in vector calculus, often denoted as \( \mathbf{a} \times \mathbf{b} \). It results in a vector that is perpendicular to the plane containing the original vectors. This makes cross products particularly useful in physics and engineering, where understanding orientations and angles in three dimensions is crucial.

To compute the cross product, you'll often use the determinant of a specific matrix set up. The result of the cross product not only gives us a vector that is orthogonal to the input vectors but also indicates the area of the parallelogram spanned by the vectors. It's important to note that the cross product is defined only in three-dimensional space. In our exercise, the cross product \( \mathbf{a} \times \mathbf{b} \) results in the vector \(-\mathbf{i} + \mathbf{j} + 0\mathbf{k}\). This indicates that the resultant vector is orthogonal to both \( \mathbf{a} \) and \( \mathbf{b} \).
Determinant
In the context of our exercise, to find the cross product, we need to calculate the determinant of a 3x3 matrix. The determinant is a special number that can be calculated from the elements of a square matrix. It provides important information about the matrix properties, like whether the matrix is invertible and the volume scaling factor.

For any 3x3 matrix, the determinant can be calculated using the rule of Sarrus or cofactor expansion. In our case, the matrix:
  • \( \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 1 & 1 & 3 \ 1 & 1 & 2 \end{vmatrix} \)
gives us the structure needed to use cofactor expansion, where the determinant helps find the cross product. Understanding how to compute determinants is essential because they are a stepping stone in many areas of advanced mathematics and applied sciences.
Cofactor Expansion
Cofactor expansion (or Laplace expansion) is a mathematical technique used for calculating determinants of matrices, which is critical in vectors calculus when finding the cross product. To use cofactor expansion to compute the determinant of our 3x3 matrix, we expand along the top row where the standard unit vectors \( \mathbf{i}, \mathbf{j}, \mathbf{k} \) are located.

This involves:
  • For each entry in the row, removing the row and column containing that entry and calculating the determinant of the remaining 2x2 matrix.
  • Multiplying these 2x2 determinants by their respective cofactor, which includes a sign based on its position \((-1)^{i+j}\).
In our solution, the cofactor expansion was used, resulting in the calculated determinants \(: \mathbf{i}(1 \cdot 2 - 1 \cdot 3) - \mathbf{j}(1 \cdot 2 - 1 \cdot 3) + \mathbf{k}(1 \cdot 1 - 1 \cdot 1)\), which then simplifies to \(-\mathbf{i} + \mathbf{j} + 0\mathbf{k}\). This process clearly demonstrates the application of cofactor expansion in vector calculus.
Matrices
Matrices play a critical role in vector calculus, especially when it comes to operations involving multiple dimensions. In our exercise, we constructed a 3x3 matrix with the basis vectors \( \mathbf{i}, \mathbf{j}, \mathbf{k} \) and the components of the vectors \( \mathbf{a} \) and \( \mathbf{b} \). This matrix is crucial for computing the cross product, as it elegantly aligns the elements necessary for the determinant calculation.

A matrix is essentially a rectangular arrangement of numbers in rows and columns, capable of representing linear transformations and systems of linear equations. It is a powerful framework because it can contain the information about entire spaces, transformations, or operations within its structure.

In this exercise, the matrix set up led directly to solving the cross product using determinant and cofactor expansion methods, illustrating the deep interconnectedness of these mathematical concepts. Understanding matrices is vital not just for vector calculus, but also for further exploration in subjects such as linear algebra and differential equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

This exercise explores key relationships between a pair of lines. Consider the following two lines: one with parametric equations \(x(s)=4-2 s\), \(y(s)=-2+s, z(s)=1+3 s,\) and the other being the line through (-4,2,17) in the direction \(\mathbf{v}=\langle-2,1,5\rangle\) a. Find a direction vector for the first line, which is given in parametric form. b. Find parametric equations for the second line, written in terms of the parameter \(t\) c. Show that the two lines intersect at a single point by finding the values of \(s\) and \(t\) that result in the same point. Then find the point of intersection. d. Find the acute angle formed where the two lines intersect, noting that this angle will be given by the acute angle between their respective direction vectors. e. Find an equation for the plane that contains both of the lines described in this problem.

Let \(\mathbf{v}=\langle-2,5\rangle\) in \(\mathbb{R}^{2},\) and let \(\mathbf{y}=\langle 0,3,-2\rangle\) in \(\mathbb{R}^{3}\). a. Is \langle 2,-1\rangle perpendicular to \(\mathbf{v}\) ? Why or why not? b. Find a unit vector \(\mathbf{u}\) in \(\mathbb{R}^{2}\) such that \(\mathbf{u}\) is perpendicular to \(\mathbf{v}\). How many such vectors are there? Justify your answers. c. Is \langle 2,-1,-2\rangle perpendicular to \(\mathbf{y} ?\) Why or why not? d. Find a unit vector \(\mathbf{w}\) in \(\mathbb{R}^{3}\) such that \(\mathbf{w}\) is perpendicular to \(\mathbf{y}\). How many such vectors are there?Justify your answers. e. Let \(\mathbf{z}=\langle 2,1,0\rangle .\) Find a unit vector \(\mathbf{r}\) in \(\mathbb{R}^{3}\) such that \(\mathbf{r}\) is perpendicular to both \(\mathbf{y}\) and \(\mathbf{z}\). How many such vectors are there? Explain your process.

Suppose \(\vec{r}(t)=\cos (\pi t) \boldsymbol{i}+\sin (\pi t) \boldsymbol{j}+3 t \boldsymbol{k}\) represents the position of a particle on a helix, where \(z\) is the height of the particle. (a) What is \(t\) when the particle has height \(6 ?\) t= ______ (b) What is the velocity of the particle when its height is \(6 ?\) \(\vec{v}=\) _______ (c) When the particle has height \(6,\) it leaves the helix and moves along the tangent line at the constant velocity found in part (b). Find a vector parametric equation for the position of the particle (in terms of the original parameter \(t\) ) as it moves along this tangent line. \(L(t)=\) ________

Are the following statements true or false? (a) The line parametrized by \(x=7, y=5 t, z=6+t\) is parallel to the x-axis. (b) A parametrization of the graph of \(y=\ln (x)\) for \(x>0\) is given by \(x=e^{t}, y=t\) for \(-\infty

Find the length of the vectors (a) \(3 \tilde{i}-\tilde{j}-3 \tilde{k}\) : length \(=\)_________ (b) \(-1.6 \tilde{i}+0.4 \tilde{j}-1.2 \tilde{k}:\) length \(=\)_________

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.