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Find the directional derivative of \(f(x, y, z)=4 x y+z^{2}\) at the point (-5,3,-2) in the direction of the maximum rate of change of \(f\). \(f_{u}(-5,3,-2)=D_{u} f(-5,3,-2)=\)

Short Answer

Expert verified
The directional derivative of \(f(x,y,z)=4xy+z^2\) at the point (-5,3,-2) in the direction of the maximum rate of change is \(\sqrt{560}\).

Step by step solution

01

Finding the gradient of f

Calculate the partial derivatives of f with respect to x, y, and z: \[\frac{\partial f}{\partial x}=4y, \frac{\partial f}{\partial y}=4x, \frac{\partial f}{\partial z}=2z\]
02

Evaluating the gradient at the given point

Plug the coordinates of the point (-5,3, -2) into the partial derivatives to find the gradient vector at that point: \[\nabla f(-5,3, -2)=\langle 4(3), 4(-5), 2(-2) \rangle =\langle 12, -20, -4 \rangle\]
03

Finding the unit vector in the direction of the gradient

Calculate the magnitude of the gradient vector: \[||\nabla f(-5,3, -2)||=\sqrt{12^{2}+(-20)^{2}+(-4)^{2}}=\sqrt{144+400+16}=\sqrt{560}\] Divide each component of the gradient vector by its magnitude to get the unit vector in the direction of the gradient: \[\frac{\nabla f(-5,3, -2)}{||\nabla f(-5,3, -2)||}=\frac{\langle 12, -20, -4 \rangle}{\sqrt{560}}=\langle \frac{12}{\sqrt{560}}, -\frac{20}{\sqrt{560}}, -\frac{4}{\sqrt{560}} \rangle\]
04

Finding the directional derivative in the direction of the maximum rate of change of f

The directional derivative is the dot product of the gradient and the unit vector in the direction of the maximum rate of change: \[D_{\textbf{u}}f(-5,3, -2)=\nabla f(-5,3, -2) \cdot \frac{\nabla f(-5,3, -2)}{||\nabla f(-5,3, -2)||}\] \[D_{\textbf{u}}f(-5,3, -2)=\left\langle 12, -20, -4 \right\rangle \cdot \left\langle \frac{12}{\sqrt{560}}, -\frac{20}{\sqrt{560}}, -\frac{4}{\sqrt{560}} \right\rangle\] \[D_{\textbf{u}}f(-5,3, -2)=\frac{1}{\sqrt{560}}(12^2+(-20)^2+(-4)^2) =\frac{560}{\sqrt{560}}\] It's not required to simplify the result further, but it's a good practice do it. Simplifying, we get: \[D_{\textbf{u}}f(-5,3, -2)=\sqrt{560}\] So, the directional derivative of \(f(x,y,z)=4xy+z^2\) at the point (-5,3,-2) in the direction of the maximum rate of change is \(\sqrt{560}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gradient Vector
Understanding the gradient vector is crucial in multivariable calculus, particularly when exploring how a function changes directionally. The gradient vector consists of all the partial derivatives of a function with respect to each variable. Essentially, it represents the rate of change of the function in all directions at once.

Let's visualize it through a familiar scenario—imagine being on a hillside. The gradient vector at your location would point in the direction of the steepest ascent; its magnitude indicates how steep the hill is. In mathematical language, if you have a function, say, \( f(x, y, z) \), the gradient vector is denoted as \( abla f \) and calculated by finding all the partial derivatives of \( f \): \( abla f = \bigg(\frac{\partial f}{\partial x}, \frac{\partial f}{\partial y}, \frac{\partial f}{\partial z}\bigg) \).

For example, given a function \( f(x, y, z)=4xy+z^2 \), the gradient vector at any point \( (x, y, z) \) is the triplet formed by taking the derivative of \( f \) with respect to each variable.
Partial Derivatives
In the realm of multivariable calculus, the concept of partial derivatives stands as a foundational block. A partial derivative measures how a function changes as one variable is varied while all other variables are held constant. This concept extends from regular derivatives in single-variable calculus.

To illustrate, consider a function \( g(x, y, z) \). The partial derivative of \( g \) with respect to \( x \) is denoted as \( \frac{\partial g}{\partial x} \) and is found by differentiating \( g \) with respect to \( x \), treating \( y \) and \( z \) as constants. This gives insights into the function's behavior relative to \( x \) independently of \( y \) and \( z \).

Each partial derivative by itself gives a one-dimensional slice of the function's behavior in the direction of the corresponding variable. When we combine these slices, much like combining slices of bread to form a loaf, we get the full picture of how the function behaves in its multi-dimensional domain.
Multivariable Calculus
Multivariable calculus is a branch of mathematics that extends the familiar concepts and techniques from calculus to functions of several variables. In a multivariable setting, you're no longer walking on a simple curve, but traversing the complex landscapes of hills, valleys, and curvy surfaces.

Key ideas in multivariable calculus include partial derivatives, multiple integrals, and vector calculus. It's essential when modeling and solving problems in physics, engineering, economics, and beyond. The power of multivariable calculus lies in its ability to dissect complex problems into smaller parts that can be understood and aggregated back into a complete understanding of the original problem.
Vector Magnitude
Vector magnitude is a measure of a vector's length. In a geometric sense, it's like the ruler you use to measure distance, but here, it's the distance from the origin to the point represented by the vector in multidimensional space.

For any vector \( \mathbf{v} = (v_1, v_2, \ldots, v_n) \) in an n-dimensional space, the magnitude (also known as the norm) is calculated using the formula \( ||\mathbf{v}|| = \sqrt{v_1^2 + v_2^2 + \ldots + v_n^2} \). This formula is essentially an application of the Pythagorean theorem extended to an n-dimensional context. The magnitude tells us how 'long' the vector is irrespective of its direction.
Dot Product
The dot product is a pivotal operation in vector algebra, serving as a bridge between algebraic and geometric understanding. When you calculate the dot product of two vectors, you're measuring how much one vector extends in the direction of another—in other words, it quantifies their 'parallelness.'

A dot product is computed as the sum of the products of corresponding components of the two vectors: for vectors \( \mathbf{a} \) and \( \mathbf{b} \) with components \( a_i \) and \( b_i \) respectively, the dot product is \( \mathbf{a} \cdot \mathbf{b} = a_1b_1 + a_2b_2 + \ldots + a_nb_n \). Notably, the maximum value of the dot product occurs when the two vectors point in the same direction, and this fact is central to finding the direction of the steepest ascent in gradient-related problems.

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Most popular questions from this chapter

Find the limits, if they exist, or type \(D N E\) for any which do not exist. $$\lim _{(x, y) \rightarrow(0,0)} \frac{1 x^{2}}{3 x^{2}+4 y^{2}}$$ 1) Along the \(x\) -axis: ___________. 2) Along the \(y\) -axis: ___________. 3) Along the line \(y=m x\) : ___________. 4) The limit is: ___________.

The Heat Index, \(I,\) (measured in apparent degrees \(F)\) is a function of the actual temperature \(T\) outside (in degrees \(\mathrm{F}\) ) and the relative humidity \(H\) (measured as a percentage). A portion of the table which gives values for this function, \(I=I(T, H),\) is reproduced in Table \(10.2 .10 .\) $$\begin{array}{ccccc}\hline T \downarrow \backslash H \rightarrow & 70 & 75 & 80 & 85 \\ \hline 90 & 106 & 109 & 112 & 115 \\\\\hline 92 & 112 & 115 & 119 & 123 \\\\\hline 94 & 118 & 122 & 127 & 132 \\\\\hline 96 & 125 & 130 & 135 & 141 \\\\\hline\end{array}$$ a. State the limit definition of the value \(I_{T}(94,75)\). Then, estimate \(I_{T}(94,75),\) and write one complete sentence that carefully explains the meaning of this value, including its units. b. State the limit definition of the value \(I_{H}(94,75)\). Then, estimate \(I_{H}(94,75),\) and write one complete sentence that carefully explains the meaning of this value, including its units. c. Suppose you are given that \(I_{T}(92,80)=3.75\) and \(I_{H}(92,80)=0.8\). Estimate the values of \(I(91,80)\) and \(I(92,78)\). Explain how the partial derivatives are relevant to your thinking. d. On a certain day, at 1 p.m. the temperature is 92 degrees and the relative humidity is \(85 \%\). At 3 p.m., the temperature is 96 degrees and the relative humidity \(75 \% .\) What is the average rate of change of the heat index over this time period, and what are the units on your answer? Write a sentence to explain your thinking.

The concentration of salt in a fluid at \((x, y, z)\) is given by \(F(x, y, z)=\) \(2 x^{2}+3 y^{4}+2 x^{2} z^{2} \mathrm{mg} / \mathrm{cm}^{3}\). You are at the point (-1,1,-1) . (a) In which direction should you move if you want the concentration to increase the fastest? direction: _________. (Give your answer as a vector.) (b) You start to move in the direction you found in part (a) at a speed of \(5 \mathrm{~cm} / \mathrm{sec} .\) How fast is the concentration changing? rate of change \(=\) ______________.

The Heat Index, \(I,\) (measured in apparent degrees \(F\) ) is a function of the actual temperature \(T\) outside (in degrees \(\mathrm{F}\) ) and the relative humidity \(H\) (measured as a percentage). A portion of the table which gives values for this function, \(I(T, H),\) is reproduced in Table 10.3 .11 . $$\begin{array}{ccccc}\hline T \downarrow \backslash H \rightarrow & 70 & 75 & 80 & 85 \\ \hline 90 & 106 & 109 & 112 & 115 \\\\\hline 92 & 112 & 115 & 119 & 123 \\ \hline 94 & 118 & 122 & 127 & 132 \\\\\hline 96 & 125 & 130 & 135 & 141 \\\\\hline\end{array}$$ a. State the limit definition of the value \(I_{T T}(94,75)\). Then, estimate \(I_{T T}(94,75),\) and write one complete sentence that carefully explains the meaning of this value, including units. b. State the limit definition of the value \(I_{H H}(94,75) .\) Then, estimate \(I_{H H}(94,75),\) and write one complete sentence that carefully explains the meaning of this value, including units. c. Finally, do likewise to estimate \(I_{H T}(94,75),\) and write a sentence to explain the meaning of the value you found.

Suppose that the temperature on a metal plate is given by the function \(T\) with $$T(x, y)=100-\left(x^{2}+4 y^{2}\right)$$ where the temperature is measured in degrees Fahrenheit and \(x\) and \(y\) are each measured in feet. Now suppose that an ant is walking on the metal plate in such a way that it walks in a straight line from the point (1,4) to the point (5,6) . a. Find parametric equations \((x(t), y(t))\) for the ant's coordinates as it walks the line from (1,4) to (5,6) b. What can you say about \(\frac{d x}{d t}\) and \(\frac{d y}{d t}\) for every value of \(t ?\) c. Determine the instantaneous rate of change in temperature with respect to \(t\) that the ant is experiencing at the moment it is halfway from (1,4) to \((5,6),\) using your parametric equations for \(x\) and \(y\). Include units on your answer.

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