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There is an important connection between power series and Taylor series. Suppose \(f\) is defined by a power series centered at 0 so that $$ f(x)=\sum_{k=0}^{\infty} a_{k} x^{k} $$ a. Determine the first 4 derivatives of \(f\) evaluated at 0 in terms of the coefficients \(a_{k}\). b. Show that \(f^{(n)}(0)=n ! a_{n}\) for each positive integer \(n\). c. Explain how the result of (b) tells us the following: On its interval of convergence, a power series is the Taylor series of its sum.

Short Answer

Expert verified
The first four derivatives evaluated at 0 yield coefficients. The nth derivative at 0 is generally given by the formula: The result implies that a power series on its interval of convergence is the Taylor series of its sum.:

Step by step solution

01

Find the First Derivative of f

To find the first derivative, differentiate the power series term by term:
02

Find the Second Derivative of f

To find the second derivative, differentiate the first derivative term by term:
03

Find the Third Derivative of f

To find the third derivative, differentiate the second derivative term by term:
04

Find the Fourth Derivative of f

To find the fourth derivative, differentiate the third derivative term by term:
05

Evaluate the Derivatives at x = 0 and Generalize

To find the first four derivatives evaluated at 0, substitute 0 for x in the previously found derivatives. Note the pattern that emerges:
06

Derive the General Formula

Using the pattern from the previous step, show that the nth derivative evaluated at 0 is generally given by:
07

Identify the Taylor Series and Its Interval of Convergence

The result from the previous steps tells us that on its interval of convergence, a power series is the Taylor series of its sum:

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Series
A power series is an infinite sum of terms that involves powers of a variable. The most general form of a power series centered at 0 is: ewline ewline ewline ewline $$f(x) = \textstyle\bold{\f[\frac{a_{0}{k}{\textstyle{n}}{0} - Infinity}\frac{x^{k}}}$$ewline power series is an infinite sum of terms that involve powers of a variable. The most general form of a power series centered at 0 is: ewline A general power series looks like this: Where Each coefficient (a_k) is a constant, and k is a non-negative integer that denotes the position in the series. Power series are useful in mathematics, especially for approximating functions within certain intervals. They are closely related to polynomials but extend beyond polynomial approximations due to their infinite terms. A key aspect of power series is knowing how they behave within their interval of convergence, which is the range of x-values for which the series converges to a finite sum.
Derivatives
Derivatives measure how a function changes as its input changes. When working with power series, we can take derivatives term by term. For a power series function: ewline It’s differentiated like this, ewline So, if we calculate this for the first few derivatives The derivative of any term a_kx^k is ka_kx^{k-1}. This makes finding derivatives straightforward. ewline The first four derivatives of function f(x) = a_0 + a_1x + a_2x^2 + ... are Step 1: The first derivative is: f'(x) = a_1 + 2a_2x + 3a_3x^2 + ... Step 2: The second derivative is: f''(x) = 2a_2 + 6a_3x + 12a_4x^2 + ... Step 3: The third derivative is: f'''(x) = 6a_3 + 24a_4x + ... ewline Step 4: The fourth derivative is: f'''(x) = 24a_4 + ... When evaluated at x = 0, higher power terms go away: ewline Thus, the derivatives evaluated at zero are: f'(0) = a_1, f''(0) = 2a_2, f'''(0) = 6a_3, and f^(4)(0) = 24a_4. Special patterns start to form in these calculations, particularly with the factorials (1!, 2!, 3!, 4!).
Interval of Convergence
The interval of convergence is critical for understanding where a power series converges to a finite value. ewline The Radius of convergence of a power series ewline is found by using the ratio test It determines the values of x for which newline series converges: lim(x → ±∞) = ewline • For |Ratio| < 1, the series converges ewline • Secondly, if |Ratio| > 1 or |Ratio| = Infinity, the series does not converge. Only within this interval does the power series act like a well-behaved function. Knowing the convergence helps us to accurately approximate functions. Additionally, within the interval of convergence, the power series represents the Taylor series of the function, meaning the power series can be seamlessly used to approximate or describe functions.
Factorials
Factorials are a super important concept related to power series and derivatives. The factorial of a non-negative integer n, denoted by n!, is the product of all positive integers less than or equal to n. For example,
  • 0! = 1
  • 1! = 1
  • 2! = 2 * 1 = 2
  • 3! = 3 * 2 * 1 = 6
  • 4! = 4 * 3 * 2 * 1 = 24
Factorials arise very naturally when dealing with derivatives of power series. As seen in the example of the exercise: If f(x) is given as ewline
The nth derivative evaluated at 0 is n!a_n. This means that factorials directly appear in the coefficients of the Taylor series. They help in understanding the pattern and the rate at which the series terms grow.we talk about Taylor Series, factorials show up in the denominators, which helps balance the fast growth of the powers Principle and factorials is Fundamental When grasping derivatives and Taylor series expansions.

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Most popular questions from this chapter

We return to the example begun in Preview Activity 8.1 .1 to see how to derive the formula for the amount of money in an account at a given time. We do this in a general setting. Suppose you invest \(P\) dollars (called the principal) in an account paying \(r \%\) interest compounded monthly. In the first month you will receive \(\frac{r}{12}\) (here \(r\) is in decimal form; e.g., if we have \(8 \%\) interest, we write \(\frac{0.08}{12}\) ) of the principal \(P\) in interest, so you earn $$ P\left(\frac{r}{12}\right) $$ dollars in interest. Assume that you reinvest all interest. Then at the end of the first month your account will contain the original principal \(P\) plus the interest, or a total of $$ P_{1}=P+P\left(\frac{r}{12}\right)=P\left(1+\frac{r}{12}\right) $$ dollars. a. Given that your principal is now \(P_{1}\) dollars, how much interest will you earn in the second month? If \(P_{2}\) is the total amount of money in your account at the end of the second month, explain why $$ P_{2}=P_{1}\left(1+\frac{r}{12}\right)=P\left(1+\frac{r}{12}\right)^{2} $$ b. Find a formula for \(P_{3}\), the total amount of money in the account at the end of the third month in terms of the original investment \(P\). c. There is a pattern to these calculations. Let \(P_{n}\) the total amount of money in the account at the end of the third month in terms of the original investment \(P\). Find a formula for \(P_{n}\)

For the following alternating series, \(\sum_{n=1}^{\infty} a_{n}=1-\frac{1}{10}+\frac{1}{100}-\frac{1}{1000}+\ldots\) how many terms do you have to go for your approximation (your partial sum) to be within 1e-07 from the convergent value of that series?

We can use known Taylor series to obtain other Taylor series, and we explore that idea in this exercise, as a preview of work in the following section. a. Calculate the first four derivatives of \(\sin \left(x^{2}\right)\) and hence find the fourth order Taylor polynomial for \(\sin \left(x^{2}\right)\) centered at \(a=0\) b. Part (a) demonstrates the brute force approach to computing Taylor polynomials and series. Now we find an easier method that utilizes a known Taylor series. Recall that the Taylor series centered at 0 for \(f(x)=\sin (x)\) is $$ \sum_{k=0}^{\infty}(-1)^{k} \frac{x^{2 k+1}}{(2 k+1) !} $$ i. Substitute \(x^{2}\) for \(x\) in the Taylor series \((8.5 .7) .\) Write out the first several terms and compare to your work in part (a). Explain why the substitution in this problem should give the Taylor series for \(\sin \left(x^{2}\right)\) centered at \(0 .\) ii. What should we expect the interval of convergence of the series for \(\sin \left(x^{2}\right)\) to be? Explain in detail.

Consider the series \(\sum_{n=1}^{\infty} \frac{10}{n+2}\). Let \(s_{n}\) be the \(\mathrm{n}\) -th partial sum; that is, $$ s_{n}=\sum_{i=1}^{n} \frac{10}{i+2} . $$ Find \(s_{4}\) and \(s_{8}\)

Sequences have many applications in mathematics and the sciences. In a recent paper \(^{3}\) the authors write The incretin hormone glucagon-like peptide- 1 (GLP-1) is capable of ameliorating glucose-dependent insulin secretion in subjects with diabetes. However, its very short half-life (1.5-5 min) in plasma represents a major limitation for its use in the clinical setting. The half-life of GLP-1 is the time it takes for half of the hormone to decay in its medium. For this exercise, assume the half-life of GLP-1 is 5 minutes. So if \(A\) is the amount of GLP-1 in plasma at some time \(t,\) then only \(\frac{A}{2}\) of the hormone will be present after \(t+5\) minutes. Suppose \(A_{0}=100\) grams of the hormone are initially present in plasma. a. Let \(A_{1}\) be the amount of GLP-1 present after 5 minutes. Find the value of \(A_{1}\). b. Let \(A_{2}\) be the amount of GLP-1 present after 10 minutes. Find the value of \(A_{2}\). c. Let \(A_{3}\) be the amount of GLP-1 present after 15 minutes. Find the value of \(A_{3}\). d. Let \(A_{4}\) be the amount of GLP-1 present after 20 minutes. Find the value of \(A_{4}\). e. Let \(A_{n}\) be the amount of GLP-1 present after \(5 n\) minutes. Find a formula for \(A_{n}\). f. Does the sequence \(\left\\{A_{n}\right\\}\) converge or diverge? If the sequence converges, find its limit and explain why this value makes sense in the context of this problem. g. Determine the number of minutes it takes until the amount of GLP-1 in plasma is 1 gram.

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