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Consider the indefinite integral \(\int \sin ^{3}(x) d x\). a. Explain why the substitution \(u=\sin (x)\) will not work to help evaluate the given integral. b. Recall the Fundamental Trigonometric Identity, which states that \(\sin ^{2}(x)+\cos ^{2}(x)=1\). By observing that \(\sin ^{3}(x)=\sin (x) \cdot \sin ^{2}(x),\) use the Fundamental Trigonometric Identity to rewrite the integrand as the product of \(\sin (x)\) with another function. c. Explain why the substitution \(u=\cos (x)\) now provides a possible way to evaluate the integral in (b). d. Use your work in (a)-(c) to evaluate the indefinite integral \(\int \sin ^{3}(x) d x\). e. Use a similar approach to evaluate \(\int \cos ^{3}(x) d x\).

Short Answer

Expert verified
\int \sin^{3}(x)dx = \frac{\cos^{3}(x)}{3} - \cos(x) + C. \int \cos^{3}(x)dx = \sin(x) - \frac{\sin^{3}}{3}(x) + C

Step by step solution

01

- Substitution of \(u=\sin(x)\)

We first consider the substitution \(u=\sin(x)\). Then, \(du=\cos(x)\,dx\). Substituting, we get the integral \(\int u^{3} \frac{du}{\cos(x)}\). The \(\cos(x)\) term in the denominator is problematic because it introduces a dependency on \(x\) again, which we were trying to remove.
02

- Applying the Fundamental Trigonometric Identity

Recall that \(\sin^{2}(x) + \cos^{2}(x) = 1\). We can rewrite \(\sin^{3}(x)\) as \(\sin(x) \cdot \sin^{2}(x) = \sin(x) \cdot (1 - \cos^{2}(x))\). This simplifies our integrand to the product of \(\sin(x)\) and another function: \(\int \sin(x) \cdot (1 - \cos^{2}(x))\,dx\).
03

- Substitution of \(u=\cos(x)\)

Let's consider the substitution \(u=\cos(x)\). Then, \(du=-\sin(x) \,dx\). This simplifies our integral: \(\int \sin(x) \cdot (1 - u^{2})(-du)\). This simplifies to \(\int (u^{2} - 1)\, du\).
04

- Evaluating the Integral

The integral now becomes \(\int (u^{2} - 1)\, du\). This splits into two integrals: \(\int u^{2} \, du - \int 1\, du\). These integrate to \(\frac{u^{3}}{3} - u + C\). Re-substitute \(u=\cos(x)\) back into the expression to get: \(\frac{\cos^{3}(x)}{3} - \cos(x) + C\).
05

- \(\int\cos^{3}(x)dx\)

Using a similar approach for \(\int \cos^{3}(x)\ dx\), we rewrite \(\cos^{3}(x)\) as \(\cos(x) \cdot (\cos^{2}(x))\) which becomes \(\cos(x) \cdot (1-\sin^{2}(x))\). Then use substitution \(u=\sin(x)\) where \(du=\cos(x)dx\). This simplifies the integral to \(\int (1 - u^2)\ du\) which becomes \(u - \frac{u^3}{3} + C\). Finally re-substitute \(u=\sin(x)\) to get \(\sin(x) - \frac{\sin^{3}}{3}(x) + C\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

substitution method
In calculus, the substitution method is a valuable technique to simplify the process of finding integrals, particularly when the integrand can be transformed into a simpler form. The method revolves around substituting a part of the integral with a new variable, making the integral more manageable.
However, in some cases, it's essential to identify the correct substitution to avoid awkward or unsolvable integrals.
For example, in the given problem, substituting  \(u = \sin(x)\) doesn't work because it introduces a dependency on \(x\) again in the denominator \(\cos(x)\). This defeats the purpose of substitution, which aims to replace complex expressions of one variable with simpler ones of another variable. Therefore, choosing the correct substitution is crucial for successful integration.
trigonometric identities
Trigonometric identities are equations that are true for all values of the variables involved, and they are fundamental in simplifying complex trigonometric expressions.
In this exercise, the Fundamental Trigonometric Identity, \(\sin^{2}(x) + \cos^{2}(x) = 1\), plays a crucial role.
By recognizing that \(\sin^{3}(x) = \sin(x) \cdot \sin^{2}(x)\), we can use the identity to rewrite \(\sin^{2}(x)\) as \(1 - \cos^{2}(x)\).
This simplification transforms the original integral into an expression involving \(\cos(x)\), which makes it easier to integrate by eliminating more complex trigonometric functions. Understanding and utilizing these identities is essential in solving trigonometric integrals effectively.
indefinite integrals
Indefinite integrals represent the general form of an antiderivative of a function, including an arbitrary constant denoted as \(C\).
It is essential to remember that integrating a function provides a family of functions differing only by a constant.
Our goal in integrating \(\sin^{3}(x)\) was to find an antiderivative that, when differentiated, returns to the original function.
The final expression for the indefinite integral of \(\sin^{3}(x)\) was \(\frac{\cos^{3}(x)}{3} - \cos(x) + C\). This highlights the importance of following each step correctly to determine the complete solution.
Similarly, when integrating \(\cos^{3}(x)\), the result was \(\sin(x) - \frac{\sin^{3}(x)}{3} + C\). Correctly substituting back and simplifying ensure a clear representation of these indefinite integrals.
integration of trigonometric functions
Integrating trigonometric functions often requires special techniques such as substitutions and the use of trigonometric identities.
With our integral \(\int \sin^{3}(x) \, dx\), we utilized the identity \(\sin^{2}(x) + \cos^{2}(x) = 1\) to rewrite the integrand, followed by substitution \(u = \cos(x)\). This made the expression simpler and easier to integrate.
By writing \(\sin^{3}(x)\) as \(\sin(x) \cdot (1 - \cos^{2}(x))\), the integrand becomes manageable. The substitution \(u = \cos(x)\) further reduces complexity, converting the integral into a polynomial form \(\int (u^{2} - 1)\, du \), which is easily integrable.
This strategy showcases the necessity of combining different techniques to handle integrals involving trigonometric functions effectively.

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For each of the following indefinite integrals, determine whether you would use \(u\) -substitution, integration by parts, neither*, or both to evaluate the integral. In each case, write one sentence to explain your reasoning, and include a statement of any substitutions used. (That is, if you decide in a problem to let \(u=e^{3 x}\), you should state that, as well as that \(\left.d u=3 e^{3 x} d x .\right)\) Finally, use your chosen approach to evaluate each integral. (* one of the following problems does not have an elementary antiderivative and you are not expected to actually evaluate this integral; this will correspond with a choice of "neither" among those given.) a. \(\int x^{2} \cos \left(x^{3}\right) d x\) b. \(\int x^{5} \cos \left(x^{3}\right) d x\left(\right.\) Hint: \(\left.x^{5}=x^{2} \cdot x^{3}\right)\) c. \(\int x \ln \left(x^{2}\right) d x\) d. \(\int \sin \left(x^{4}\right) d x\) e. \(\int x^{3} \sin \left(x^{4}\right) d x\) f. \(\int x^{7} \sin \left(x^{4}\right) d x\)

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