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On a sketch of \(y=e^{x},\) represent the left Riemann sum with \(n=2\) approximating \(\int_{2}^{3} e^{x} d x\). Write out the terms of the sum, but do not evaluate it: Sum \(=\) ___________________ + ___________________ On another sketch, represent the right Riemann sum with \(n=2\) approximating \(\int_{2}^{3} e^{x} d x\). Write out the terms of the sum, but do not evaluate it: Sum \(=\) ___________________ + ___________________ Which sum is an overestimate? Which sum is an underestimate?

Short Answer

Expert verified
Left Riemann sum: \(e^{2} \times 0.5 + e^{2.5} \times 0.5\). Right Riemann sum: \(e^{2.5} \times 0.5 + e^{3} \times 0.5\). Left sum is an underestimate. Right sum is an overestimate.

Step by step solution

01

Understand the interval and number of rectangles

The interval of integration is from 2 to 3 and we are to use 2 rectangles (n=2).
02

Determine the width of each rectangle

Calculate the width of each rectangle \(\text{width} = \frac{b-a}{n}\) where \(a=2\), \(b=3\), and \(n=2\). The width \( \text{width} = \frac{3-2}{2} = 0.5 \)
03

Set up the left Riemann sum

The left Riemann sum uses function values at the left endpoints of the subintervals. The left endpoints are \( x_0 = 2 \) and \( x_1 = 2 + 0.5 = 2.5 \). Therefore, the sum is \(\text{sum} = f(x_0)\text{width} + f(x_1)\text{width} = e^{2} \times 0.5 + e^{2.5} \times 0.5 \)
04

Set up the right Riemann sum

The right Riemann sum uses function values at the right endpoints of the subintervals. The right endpoints are \( x_1 = 2.5 \) and \( x_2 = 2.5 + 0.5 = 3 \). Therefore, the sum is \(\text{sum} = f(x_1)\text{width} + f(x_2)\text{width} = e^{2.5} \times 0.5 + e^{3} \times 0.5 \)
05

Determine which sum is an overestimate and which is an underestimate

The function \(y=e^x\) is increasing. The left Riemann sum underestimates the integral, while the right Riemann sum overestimates the integral.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Left Riemann Sum
The left Riemann sum is a method to approximate the value of an integral by using the function values at the left endpoints of subintervals. This method is particularly useful when you need a quick estimation of the integral, especially if you don't have access to the tools needed for more precise calculations.

For the given problem, we divide the interval \( [2, 3] \) into \( n = 2 \) subintervals. The width of each subinterval is: \[ \text{width} = \frac{3-2}{2} = 0.5 \]

Since we use the left endpoints for our calculations: \[ x_0 = 2, \ x_1 = 2 + 0.5 = 2.5 \]

The left Riemann sum is then: \[ \text{sum} = f(x_0) \times \text{width} + f(x_1) \times \text{width} = e^2 \times 0.5 + e^{2.5} \times 0.5 \]

This approach will give an underestimate of the actual integral because the function \( y = e^x \) is increasing throughout the interval. The rectangles formed will always lie below the curve.
Right Riemann Sum
The right Riemann sum offers another method for approximating the value of an integral, differing from the left Riemann sum by using the function values at the right endpoints of subintervals. In situations involving increasing functions, this method typically provides an overestimate of the integral.

For the same interval \( [2, 3] \) divided into \( n = 2 \) subintervals, the right endpoints are: \[ x_1 = 2.5, \ x_2 = 2.5 + 0.5 = 3 \]

The right Riemann sum is calculated as: \[ \text{sum} = f(x_1) \times \text{width} + f(x_2) \times \text{width} = e^{2.5} \times 0.5 + e^{3} \times 0.5 \]

This method generally results in an overestimate of the integral because the rectangles will extend above the curve for an increasing function like \( y = e^x \).
Integration Approximation
The methods of left Riemann sum and right Riemann sum fall under the broader category of integration approximation. These techniques provide valuable ways to estimate the value of definite integrals, and are especially helpful when dealing with complicated functions or when exact integration is difficult.

There are several key points to remember about these methods:
  • Both left and right Riemann sums rely on dividing the interval of integration into smaller subintervals (rectangles).
  • The width of each subinterval is calculated as: \[ \text{width} = \frac{b-a}{n}, \ \text{where } a \text{ and } b \text{ are the limits of integration and } n \text{ is the number of subintervals.} \]
  • For the left Riemann sum, the function value at the left endpoint of each subinterval is used.
    For the right Riemann sum, the function value at the right endpoint of each subinterval is used.
  • When dealing with an increasing function like \( y = e^x \), the left Riemann sum provides an underestimate, while the right Riemann sum provides an overestimate of the actual integral.


These methods are foundational in calculus and serve as stepping stones to more accurate techniques such as Simpson's Rule and the Trapezoidal Rule. Whether you are estimating an integral by hand or using software, understanding these basic concepts is essential for more advanced studies.

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Most popular questions from this chapter

When an aircraft attempts to climb as rapidly as possible, its climb rate (in feet per minute) decreases as altitude increases, because the air is less dense at higher altitudes. Given below is a table showing performance data for a certain single engine aircraft, giving its climb rate at various altitudes, where \(c(h)\) denotes the climb rate of the airplane at an altitude \(h\). $$ \begin{array}{lllllllllll} \hline h \text { (feet) } & 0 & 1000 & 2000 & 3000 & 4000 & 5000 & 6000 & 7000 & 8000 & 9000 & 10,000 \\ \hline c(\mathrm{ft} / \mathrm{min}) & 925 & 875 & 830 & 780 & 730 & 685 & 635 & 585 & 535 & 490 & 440 \\ \hline \end{array} $$ Let a new function called \(m(h)\) measure the number of minutes required for a plane at altitude \(h\) to climb the next foot of altitude. a. Determine a similar table of values for \(m(h)\) and explain how it is related to the table above. Be sure to explain the units. b. Give a careful interpretation of a function whose derivative is \(m(h)\). Describe what the input is and what the output is. Also, explain in plain English what the function tells us. c. Determine a definite integral whose value tells us exactly the number of minutes required for the airplane to ascend to 10,000 feet of altitude. Clearly explain why the value of this integral has the required meaning. d. Use the Riemann sum \(M_{5}\) to estimate the value of the integral you found in (c). Include units on your result.

Your task is to estimate how far an object traveled during the time interval \(0 \leq t \leq 8\), but you only have the following data about the velocity of the object. $$ \begin{array}{|l|l|l|l|l|l|l|l|l|l|} \hline \text { time (sec) } & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline \text { velocity (feet/sec) } & -3 & -2 & -3 & -1 & -2 & -1 & 4 & 1 & 2 \\\ \hline \end{array} $$ To get an idea of what the velocity function might look like, you pick up a black pen, plot the data points, and connect them by curves. Your sketch looks something like the black curve in the graph below. You decide to use a left endpoint Riemann sum to estimate the total displacement. So, you pick up a blue pen and draw rectangles whose height is determined by the velocity measurement at the left endpoint of each one-second interval. By using the left endpoint Riemann sum as an approximation, you are assuming that the actual velocity is approximately constant on each one-second interval (or, equivalently, that the actual acceleration is approximately zero on each one- second interval), and that the velocity and acceleration have discontinuous jumps every second. This assumption is probably incorrect because it is likely that the velocity and acceleration change continuously over time. However, you decide to use this approximation anyway since it seems like a reasonable approximation to the actual velocity given the limited amount of data. (A) Using the left endpoint Riemann sum, find approximately how far the object traveled. Your answers must include the correct units. Total displacement \(=\) ___________________ Total distance traveled \(=\) _________________ Using the same data, you also decide to estimate how far the object traveled using a right endpoint Riemann sum. So, you sketch the curve again with a black pen, and draw rectangles whose height is determined by the velocity measurement at the right endpoint of each one-second interval. (B) Using the right endpoint Riemann sum, find approximately how far the object traveled. Your answers must include the correct units. Total displacement \(=\) ________________ Total distance traveled \(=\) ______________

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The velocity function is \(v(t)=t^{2}-6 t+8\) for a particle moving along a line. Find the displacement (net distance covered) of the particle during the time interval [-2,5] displacement \(=\) ______________

Suppose that an accelerating car goes from 0 mph to 66.8 mph in five seconds. Its velocity is given in the following table, converted from miles per hour to feet per second, so that all time measurements are in seconds. (Note: \(1 \mathrm{mph}\) is \(22 / 15\) feet per sec \(=22 / 15 \mathrm{ft} / \mathrm{s}\).) Find the average acceleration of the car over each of the first two seconds. $$ \begin{array}{|l|l|l|l|l|l|l|} \hline t & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline v(t) & 0.00 & 33.41 & 57.91 & 75.73 & 89.09 & 98.00 \\ \hline \end{array} $$ average acceleration over the first second \(=\) ______________ (include units) average aceleration over the second second = _______________ (include units)

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