/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 For the following questions, cho... [FREE SOLUTION] | 91Ó°ÊÓ

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For the following questions, choose the correct answers from the codes \((a),(b),(c)\) and (d) defined as follows: (a) Statement I is true, Statement II is also true, Statement II is the correct explanation of Statement I. (b) Statement I is true, Statement II is also true, Statement II is not the correct explanation of Statement I. (c) Statement I is true, Statement II is false. (d) Statement I is false, Statement II is true. Statement I The equation \(3 x^{2}+4 a x+b=0\) has atleast one root in \((0,1)\), if \(3+4 a=0\). Statement II \(f(x)=3 x^{2}+4 x+b\) is continuous and differentiable in \((0,1)\).

Short Answer

Expert verified
(d) Statement I is false, Statement II is true.

Step by step solution

01

Assess Statement I

Statement I implies that the quadratic equation \(3x^2 + 4ax + b = 0\) has at least one root in the interval \((0,1)\) given the condition \(3 + 4a = 0\). Solving for \(a\), we find \(a = -\frac{3}{4}\). Substitute \(a = -\frac{3}{4}\) into the equation to get \(3x^2 - 3x + b = 0\). To ensure at least one root in \((0,1)\), the roots must be real, requiring the discriminant \(\Delta = (-3)^2 - 4 \cdot 3 \cdot b = 9 - 12b\) to be non-negative. Hence, it does not guarantee a root within \((0,1)\) without further information on \(b\). Therefore, Statement I is false.
02

Assess Statement II

The function \(f(x) = 3x^2 + 4x + b\) is a polynomial. Polynomials are continuous and differentiable everywhere on the real line, including the interval \((0,1)\). Therefore, Statement II is true.
03

Compare Statements and Choose the Correct Code

Statement I is false, and Statement II is true. According to the given coding system, this corresponds to code \((d)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
Quadratic equations are equations of the form \(ax^2 + bx + c = 0\). They are called quadratic because the highest degree of the variable \(x\) is 2. The solutions to these equations are known as the roots, and they tell us where the graph of the equation crosses the x-axis.
To find the roots of a quadratic equation, you can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]This formula relies on the discriminant \(b^2 - 4ac\) to determine the nature of the roots:
  • If the discriminant is positive, there are two distinct real roots.
  • If it is zero, there is exactly one real root (a repeated root).
  • If the discriminant is negative, there are no real roots, but there are two complex roots.

In solving quadratic equations, it's important to consider the interval or range in which you need the roots to exist, as demonstrated in the given exercise. This approach helps determine whether a solution fits within certain parameters for practical applications.
Continuity and Differentiability
Continuity and differentiability are fundamental concepts in differential calculus. They help describe the behavior of functions and their graphs.
**Continuity**: A function is said to be continuous at a point if there is no interruption in its graph at that point. For a function \(f(x)\) to be continuous at \(x = c\), three conditions must be satisfied:
  • \(f(c)\) is defined.
  • The limit of \(f(x)\) as \(x\) approaches \(c\) exists.
  • The limit of \(f(x)\) as \(x\) approaches \(c\) is equal to \(f(c)\).

**Differentiability**: If a function is continuous and smooth (no sharp corners or cusps), it is differentiable at that point. Differentiability implies the existence of a derivative, which represents the function's rate of change.
Polynomials, like \(f(x) = 3x^2 + 4x + b\), are both continuous and differentiable everywhere, including within the interval \((0,1)\), as noted in the exercise. This ensures smooth curves without breaks or sharp turns.
Polynomials
Polynomials are expressions consisting of variables and coefficients combined using addition, subtraction, and multiplication. A general polynomial of degree \(n\) can be written as:\[ a_n x^n + a_{n-1} x^{n-1} + \ldots + a_1 x + a_0 \]The degree of the polynomial is the highest power of \(x\) with a non-zero coefficient.
Polynomials have several key characteristics:
  • They are continuous everywhere, meaning their graphs are unbroken curves.
  • They are differentiable, ensuring they have a smooth tangent line at every point.
  • The degree of the polynomial determines the number of roots or intersections with the x-axis.

The behavior of polynomials is predictable, making them essential tools in calculus for modeling and solving real-world problems. In the given exercise, understanding the nature of the polynomial function helps determine its continuity and differentiability, which are crucial for validating statement II.

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Most popular questions from this chapter

Suppose you do not know the function \(f(x)\) however some information about \(f(x)\) is listed below. Read the following carefully before attempting the questions (i) \(f(x)\) is continuous and defined for all real numbers (ii) \(f^{\prime}(-5)=0, f^{\prime}(2)\) is not defined and \(f^{\prime}(4)=0\) (iii) \((-5,12)\) is a point which lies on the graph of \(f(x)\) (iv) \(f^{\prime \prime}(2)\) is undefined, but \(f^{\prime \prime}(x)\) is negative everywhere else (v) The signs of \(f^{\prime}(x)\) is given below From the possible graph of \(y=f(x)\), we can say that (a) there is exactly one point of inflection on the curve. (b) \(f(x)\) increases on \(-54\) and decreases on \(-\infty

\(\operatorname{If} f(x)=\left\\{\begin{array}{ll}2 x^{2}+\frac{2}{x^{2}}, & 0<|x| \leq 2 \\ 3, & x>2\end{array}\right.\), then (a) \(x=1,-1\) are the points of global minima (b) \(x=1,-1\) are the points of local minima (c) \(x=0\) is the points of local minima (d) None of the above

For the following questions, choose the correct answers from the codes \((a),(b),(c)\) and (d) defined as follows: (a) Statement I is true, Statement II is also true, Statement II is the correct explanation of Statement I. (b) Statement I is true, Statement II is also true, Statement II is not the correct explanation of Statement I. (c) Statement I is true, Statement II is false. (d) Statement I is false, Statement II is true. Let \(f(0)=0, f\left(\frac{\pi}{2}\right)=1, f\left(\frac{3 \pi}{2}\right)=-1\) be a continuous and twice differentiable function. Statement I | \(f^{\prime \prime}(x) \mid \leq 1\) for atleast one \(x \in\left(0, \frac{3 \pi}{2}\right)\) because Statement II According to Rolle's theorem, if \(y=g(x)\) is continuous and differentiable \(\forall x \in[a, b]\) and \(g(a)=g(b)\), then there exists atleast one \(c\) such that \(g^{\prime}(c)=0\).

If \(f(x)=a^{\left\\{a^{|x|} \operatorname{sgn} x\right\\}} ; g(x)=a^{\left[\left[a^{|x|} \operatorname{sgn} x\right]\right.}\) for \(a>0, a \neq 1\) and \(x \in R\), where \\{\\} and [] denote the fractional part and integral part functions respectively, then which of the following statements can hold good for the function \(h(x)\), where \((\ln a) h(x)=(\ln f(x)+\ln g(x))\) (a) \(h\) is even and increasing (b) \(h\) is odd and decreasing (c) \(h\) is even and decreasing (d) \(h\) is odd and increasing

Consider the function \(f(x)=\frac{x^{2}}{x^{2}-1}\) \(f\) has (a) local maxima but not local minima (b) local minima but not local maxima (c) both local maxima and local minima (d) neither local maxima nor local minima

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