Chapter 7: Problem 36
For function \(f(x)=\frac{\ln x}{x}\), which of the following statements are true? (a) \(f(x)\) has horizontal tangent at \(x=e\) (b) \(f(x)\) cuts the \(x\)-axis only at one point (c) \(f(x)\) is many-one function (d) \(f(x)\) has one vertical tangent
Short Answer
Expert verified
Statements (a) and (b) are true; statements (c) and (d) are false.
Step by step solution
01
Find the derivative of the function
The function given is \( f(x) = \frac{\ln x}{x} \). To determine properties like horizontal tangents, we first need the derivative. Use the quotient rule: \[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \] Here, \( u = \ln x \) and \( v = x \). So, \( u' = \frac{1}{x} \) and \( v' = 1 \). Thus, the derivative, \( f'(x) = \frac{\left( \frac{1}{x} \right)x - \ln x \cdot 1}{x^2} = \frac{1 - \ln x}{x^2} \).
02
Find where the derivative is zero (horizontal tangent)
A horizontal tangent occurs where the derivative is zero. Set \( f'(x) = 0 \): \[ \frac{1 - \ln x}{x^2} = 0 \] This implies \( 1 - \ln x = 0 \) or \( \ln x = 1 \). Thus, \( x = e \). Therefore, \( f(x) \) has a horizontal tangent at \( x = e \). Statement (a) is true.
03
Determine if \( f(x) \) cuts the x-axis
The function \( f(x) = \frac{\ln x}{x} \) cuts the x-axis where \( f(x) = 0 \). Set \( \ln x = 0 \), which implies \( x = 1 \). Thus, \( f(x) \) cuts the x-axis at \( x = 1 \). Since there are no other points that make \( \ln x = 0 \), it only cuts the x-axis once. Statement (b) is true.
04
Discuss if the function is many-one
A function is many-one if multiple values of \( x \) yield the same value of \( f(x) \). Since \( f(x) = \frac{\ln x}{x} \) is a decreasing function (as the derivative shows a change from positive to negative around \( x = e \)), different \( x \) values will not repeat the same \( f(x) \) value. Thus, \( f(x) \) is not many-one. Statement (c) is false.
05
Check for vertical tangents
Vertical tangents occur when the derivative \( f'(x) \) approaches \( \pm \infty \). Analyze \( f'(x) = \frac{1 - \ln x}{x^2} \). As \( x \to 0^+ \), \( \ln x \to -\infty \) and \( x^2 \to 0^+ \), the derivative goes to \( +\infty \), which is not vertical. As \( x \to \infty \), \( f'(x) \to 0 \). Thus, no vertical tangents exist. Statement (d) is false.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Horizontal Tangents
A horizontal tangent line to a curve occurs when the slope of the tangent is zero. In differential calculus, this corresponds to setting the derivative of a function to zero and solving for the variable. For the given function, \( f(x) = \frac{\ln x}{x} \), to find horizontal tangents, calculate the derivative \( f'(x) = \frac{1 - \ln x}{x^2} \). This derivative represents the slope at any point on the curve.
By solving the equation \( f'(x) = 0 \), you find \( 1 - \ln x = 0 \) which simplifies to \( \ln x = 1 \). The solution to this is \( x = e \), which is approximately 2.718. Thus, the only horizontal tangent for this function occurs precisely at \( x = e \). Here, the curve of the function has a "flat" spot, meaning the slope, both left and right of this point, nearly matches before increasing or decreasing again.
By solving the equation \( f'(x) = 0 \), you find \( 1 - \ln x = 0 \) which simplifies to \( \ln x = 1 \). The solution to this is \( x = e \), which is approximately 2.718. Thus, the only horizontal tangent for this function occurs precisely at \( x = e \). Here, the curve of the function has a "flat" spot, meaning the slope, both left and right of this point, nearly matches before increasing or decreasing again.
Quotient Rule
The quotient rule is a technique for differentiating functions that are in the form of a fraction, \( \frac{u}{v} \). It states:
- Find the derivative of the numerator \( u \), denoted as \( u' \).
- Find the derivative of the denominator \( v \), denoted as \( v' \).
- Apply the formula for the derivative: \[ \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \]
Function Properties
Understanding the properties of functions is crucial in calculus. The function \( f(x) = \frac{\ln x}{x} \) has distinct characteristics that determine various behaviors on its graph.
- **Intersection with the x-axis:**To see where \( f(x) \) crosses the x-axis, set the function equal to zero: \( \frac{\ln x}{x} = 0 \). This simplifies to \( \ln x = 0 \), giving \( x = 1 \). Thus, the function intersects the x-axis only at \( x = 1 \).
- **Is it many-one?**A many-one function can map multiple inputs to the same output. Since the derivative of the function \( f'(x) \) shows a changing sign around \( x = e \) which indicates a decreasing pattern after that point, it's not many-one. Each \( x \) has a unique output.
- **Vertical Tangents:**For vertical tangents, the derivative must approach infinity as the x-value approaches a certain point. Examining \( f'(x) = \frac{1 - \ln x}{x^2} \), as \( x \to 0^+ \), \( \ln x \) tends to \(-\infty \), thus not producing a valid vertical tangent. As \( x \to \infty \), the derivative tends to zero, ensuring no vertical tangents exist for the function.