Chapter 8: Problem 6
Let \(X\) be a continuous random variable with probability density \(f_{X}\) that takes only positive values and let \(Y=1 / X\). a. Determine \(F_{Y}(y)\) and show that $$ f_{Y}(y)=\frac{1}{y^{2}} f_{X}\left(\frac{1}{y}\right) \quad \text { for } y>0 . $$ b. Let \(Z=1 / Y\). Using a, determine the probability density \(f_{Z}\) of \(Z\), in terms of \(f_{X}\).
Short Answer
Step by step solution
Understanding the Problem
Express Cumulative Distribution Function of Y
Find Probability Density of Y
Express Z in Terms of Y and Find fZ(Z)
Differentiate to Find fZ(Z)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuous Random Variable
- It does not give the probability of a specific value because, theoretically, the probability of a continuous random variable taking on any single, exact value is zero.
- Instead, the area under the pdf curve between two values gives the probability that the variable falls within that range.
Cumulative Distribution Function
- At the lower bound (or negative infinity), it starts at 0.
- At the upper bound (or positive infinity), it approaches 1, ensuring cumulative coverage of the sample space.
Transformation of Variables
- Start with expressing the new variable through the old one, for example, \( Y = \frac{1}{X} \).
- Then use calculus-based techniques such as the change of variables in integration or differentiation to derive relationships for the new pdf or CDF.