/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 1 / 3 ... [FREE SOLUTION] | 91Ó°ÊÓ

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Short Answer

Expert verified
0.3333

Step by step solution

01

Identify the Fraction

The given fraction is \(\frac{1}{3}\).
02

Convert to Decimal

To convert the fraction to a decimal, divide the numerator (1) by the denominator (3). This gives \(1 \div 3 = 0.3333\). The decimal representation is an approximation and can be written as 0.3333 or 0.33, depending on the required precision.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Fractions
A fraction represents a part of a whole. It is composed of two main parts: the numerator and the denominator.
The numerator is the number above the line, while the denominator is the number below the line.
For example, in the fraction \( \frac{1}{3} \), 1 is the numerator, and 3 is the denominator.
The numerator indicates how many parts we have, and the denominator shows into how many total parts the whole is divided.
Fractions are a way to express numbers that are not whole, allowing us to represent values between integers.
Decimal Representation of Fractions
When converting fractions to decimals, we are finding an equivalent form of the fraction that is easier to use in calculations.
To convert a fraction to a decimal, you divide the numerator by the denominator.
This division can sometimes result in a repeating decimal, where one or more digits repeat infinitely.
In the case of \( \frac{1}{3} \), dividing 1 by 3 gives 0.3333...
Since the 3 repeats indefinitely, we can write it as \( 0.33\overline{3} \) or simply use a rounded version like 0.33 or 0.3333 depending on the level of precision required.
Decimal representation helps in performing arithmetic operations more conveniently.
Division of Numerator and Denominator
To convert a fraction to a decimal, you perform division.
The numerator (top number) is divided by the denominator (bottom number).
For our fraction \( \frac{1}{3} \), this means calculating \(1 \div 3\).
Here’s how you can think about it step-by-step:
  • Start by seeing how many times the denominator fits into the numerator.
  • If it does not fit evenly, add a decimal point and zeros to the numerator and continue the division.
  • In this case, 3 fits into 1 zero times, so you add a decimal point and a zero to make it 10.
  • Then, 3 fits into 10 three times with a remainder of 1. This remainder keeps the division going, resulting in the repeating decimal 0.3333...
This repeating decimal shows the fractional part of the original division repeated indefinitely.

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Most popular questions from this chapter

Fast Eddie needs to double his money; he can only do so by playing a certain win-lose game, in which the probability of winning is \(p\). However, he can play this game as many or as few times as he wishes, and in a particular game he can bet any desired fraction of his bankroll. The game pays even money (the odds are one-to-one). Assuming he follows an optimal strategy if one is available, what is the probability, as a function of \(p\), that Fast Eddie will succeed in doubling his money?

It is a standard result that the limit of the indeterminate form \(x^x\), as \(x\) approaches zero from above, is 1 . What is the limit of the repeated power \(x^{x^{. ^{. ^{. ^{x }}}}} \) with \(n\) occurrences of \(x\), as \(x\) approaches zero from above?

The proprietor of the Wohascum Puzzle, Game and Computer Den, a small and struggling but interesting enterprise in Wohascum Center, recently was trying to design a novel set of dice. An ordinary die, of course, is cubical, with each face showing one of the numbers \(1,2,3,4,5\), 6. Since each face borders on four other faces, each number is "surrounded" by four of the other numbers. The proprietor's plan was to have each die in the shape of a regular dodecahedron (with twelve pentagonal faces). Each of the numbers \(1,2,3,4,5,6\) would occur on two different faces and be "surrounded" both times by all five other numbers. Is this possible? If so, in how many essentially different ways can it be done? (Two ways are considered essentially the same if one can be obtained from the other by rotating the dodecahedron.)

Define a function \(f\) by \(f(x)=x^{1 / x^{x^{1 / x^{x^{1 / x ^{. ^{. ^{. }}}}}}}} (x>0)\). That is to say, for a fixed \(x\), let $$ a_1=x, \quad a_2=x^{1 / x}, \quad a_3=x^{1 / x^x}=x^{1 / x^{a_1}}, \quad a_4=x^{1 / x^{x^{1 / x}}}=x^{1 / x^{a_2}}, \quad \ldots $$ and, in general, \(a_{n+2}=x^{1 / x^{a_n}}\), and take \(f(x)=\lim _{n \rightarrow \infty} a_n\). a. Assuming that this limit exists, let \(M\) be the maximum value of \(f\) as \(x\) ranges over all positive real numbers. Evaluate \(M^M\). b. Prove that \(f(x)\) is well defined; that is, that the limit exists.

Suppose we are given an \(m\)-gon (polygon with \(m\) sides, and including the interior for our purposes) and an \(n\)-gon in the plane. Consider their intersection; assume this intersection is itself a polygon (other possibilities would include the intersection being empty or consisting of a line segment). a. If the \(m\)-gon and the \(n\)-gon are convex, what is the maximal number of sides their intersection can have? b. Is the result from (a) still correct if only one of the polygons is assumed to be convex? (Note: A subset of the plane is convex if for every two points of the subset, every point of the line segment between them is also in the subset. In particular, a polygon is convex if each of its interior angles is less than \(\left.180^{\circ}.\right)\)

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