/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 The Wohascum County Board of Com... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Wohascum County Board of Commissioners, which has 20 members, recently had to elect a President. There were three candidates \((A, B\), and \(C\) ); on each ballot the three candidates were to be listed in order of preference, with no abstentions. It was found that 11 members, a majority, preferred \(A\) over \(B\) (thus the other 9 preferred \(B\) over \(A\) ). Similarly, it was found that 12 members preferred Given these results, it was suggested that \(B\) should withdraw, to enable a runoff election between \(A\) and \(C\). However, \(B\) protested, and it was then found that 14 members preferred \(B\) over \(C\) ! The Board has not yet recovered from the resulting confusion. Given that every possible order of \(A, B, C\) appeared on at least one ballot, how many board members voted for \(B\) as their first choice?

Short Answer

Expert verified
3 members voted B as their first choice.

Step by step solution

01

- Understand the Preferences

Analyze the given preferences: - 11 members preferred A over B.- 12 members preferred C over A.- 14 members preferred B over C.
02

- Total Preferences

Remember, each member has exactly one vote and there are 20 members in total. Therefore, the sum of those who prefer one candidate over another should add up accordingly.
03

- Define Variables

Let:- x be the number of members who prefer the order A > B > C.- y be the number of members who prefer the order B > C > A.- z be the number of members who prefer the order C > A > B.
04

- Develop Equations

Form the equations based on preferences:1. x + (14 - z) + z = 20 (All voters are accounted for)2. x + z = 11 (Preference A over B)3. z + y = 12 (Preference C over A)4. y + (11 - x) = 14 (Preference B over C)
05

- Solve Equations

Solve the system of equations above:- From equation 3, y = 12 - z.- From equation 2, z = 11 - x.- Substitute these into equation 4: 12 - z + 11 - x = 14 12 - (11 - x) + 11 - x = 14 12 - 11 + x + 11 - x = 14 12 = 14∴ x = 2 ∴ z = 11 - x = 9 ∴ y = 12 - z = 3
06

- Conclusion

Given the candidates in order:- A > B > C = x = 2- B > C > A = y = 3 - C > A > B= z = 9

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

preference order
Preference order is a fundamental concept in voting theory. It describes how voters rank candidates based on their preferences.
In the given exercise, each member of the Wohascum County Board of Commissioners ranked the candidates A, B, and C in a specific order from most to least preferred.
This results in various combinations of ordered preferences.
When analyzing preference orders, it's important to collect all the rankings to understand the overall preference of the voters. In our case, the important preference orders led to the following system of equations during the exercise:
- 11 members preferred A over B.
- 12 members preferred C over A.
- 14 members preferred B over C.

These preferences are decoded into equations that then help in finding how each candidate stands among the voters based on their position in the list.
equations system
Forming an equation system helps solve many problems involving preferences.
In this exercise, three key equations were set up to reflect the given preferences:

- Let: - x be the number of members who prefer the order A > B > C.
- y be the number of members who prefer the order B > C > A.
- z be the number of members who prefer the order C > A > B.

The following equations are derived from the preferences:
1. x + (14 - z) + z = 20 (All voters are accounted for)
2. x + z = 11 (Preference A over B)
3. z + y = 12 (Preference C over A)
4. y + (11 - x) = 14 (Preference B over C)

The goal is to solve these equations to determine the exact numbers of voters that preferred each order.
candidate elimination
Candidate elimination refers to the step in voting where one candidate is removed from consideration to simplify the decision-making process.
In the exercise, it was suggested that candidate B should withdraw, enabling a runoff between A and C.
However, B protested, which led to further analysis, revealing that most members preferred B over C.

By doing this additional analysis with candidate elimination, we see why simply removing a candidate based on partial data can lead to a misrepresentation of the voter's true preferences.
This step highlights the importance of comprehensive data and detailed analysis in determining candidate viability.
ballot analysis
Ballot analysis involves looking deeply into voting data to find patterns and preferences.
In the exercise, the ballots were analyzed to determine the exact number of members supporting particular orders of preference.
Each possible preference was collected and compared:
- The number of members who preferred A over B (11 members)
- The number of members who preferred C over A (12 members)
- The number of members who preferred B over C (14 members)

A step-wise solution involves forming equations and analyzing the votes.
This includes substitution and solving systems of equations. Consequently, the analysis revealed:
- x (A > B > C) = 2 members
- y (B > C > A) = 3 members
- z (C > A > B) = 9 members.
The thorough ballot analysis allowed for a deeper understanding of the preferences and the final distribution of first-choice votes.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Every year, the first warm days of summer tempt Lake Wohascum's citizens to venture out into the local parks; in fact, one day last May, the MAA Student Chapter held an impromptu picnic. A few insects were out as well, and at one point an insect dropped from a tree onto a paper plate (fortunately an empty one) and crawled off. Although this did not rank with Newton's apple as a source of inspiration, it did lead the club to wonder: If an insect starts at a random point inside a circle of radius \(R\) and crawls in a straight line in a random direction until it reaches the edge of the circle, what will be the average distance it travels to the perimeter of the circle? ("Random point" means that given two equal areas within the circle, the insect is equally likely to start in one as in the other; "random direction" means that given two equal angles with vertex at the point, the insect is equally likely to crawl off inside one as the other.)

Note that the three positive integers \(1,24,120\) have the property that the sum of any two of them is a different perfect square. Do there exist four positive integers such that the sum of any two of them is a perfect square and such that the six squares found in this way are all different? If so, exhibit four such positive integers; if not, show why this cannot be done.

Let \(A\) be a set of \(n\) real numbers. Because \(A\) has \(2^n\) subsets, we can get \(2^n\) sums by choosing a subset \(B\) of \(A\) and taking the sum of the numbers in \(B\). (By convention, if \(B\) is the empty set, that sum is 0.) What is the least number of different sums we must get (as a function of \(n\) ) by taking the \(2^n\) possible sums of subsets of a set with \(n\) numbers?

Let \(S(n)\) be the number of solutions of the equation \(e^{\sin x}=\sin \left(e^x\right)\) on the interval \([0,2 n \pi]\). Find \(\lim _{n \rightarrow \infty} \frac{S(n)}{e^{2 n \pi}}\), or show that the limit does not exist.

Note that a triangle \(A B C\) is isosceles, with equal angles at \(A\) and \(B\), if and only if the median from \(C\) and the angle bisector at \(C\) are the same. This suggests a measure of "scalenity": For each vertex of a triangle \(A B C\), measure the distance along the opposite side from the midpoint to the "end" of the angle bisector, as a fraction of the total length of that opposite side. This yields a number between 0 and \(1 / 2\); take the least of the three numbers found in this way. The triangle is isosceles if and only if this least number is zero. What are the possible values of this least number if \(A B C\) can be any triangle in the plane?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.