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A point \(P=(a, b)\) in the plane is rational if both \(a\) and \(b\) are rational numbers. Find all rational points \(P\) such that the distance between \(P\) and every rational point on the line \(y=13 x\) is a rational number.

Short Answer

Expert verified
The only rational point is \(P = (0, 0)\).

Step by step solution

01

Understand the problem

We need to find all rational points \(P = (a, b)\) such that the distance between \(P\) and any rational point on the line \(y = 13x\) is rational.
02

Use the distance formula

The distance between two points \(P_1 = (x_1, y_1)\) and \(P_2 = (x_2, y_2)\) is given by \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] We want this distance to be rational.
03

Parameterize the line

Any rational point on the line \(y = 13x\) can be written as \(Q = (r, 13r)\) where \( r \) is a rational number.
04

Apply distance formula to P and Q

Calculate the distance between \(P = (a, b)\) and \(Q = (r, 13r)\). \[ d = \sqrt{(r - a)^2 + (13r - b)^2} \]
05

Simplify distance expression

Simplify the expression: \[ d = \sqrt{(r - a)^2 + (13r - b)^2} \] Expanding the terms, we get \[ d = \sqrt{(r^2 - 2ar + a^2) + (169r^2 - 26br + b^2)} \] This simplifies to \[ d = \sqrt{170r^2 - 2ar - 26br + a^2 + b^2} \]
06

Ensure rational solution for all r

For the square root of \[ 170r^2 - 2ar - 26br + a^2 + b^2 \] to be rational for all rational \( r \), the expression inside the square root must be a perfect square. Thus, it must be a quadratic form that factors into squares with rational coefficients.
07

Analyze and solve for a and b

To be a perfect square: \[ 170r^2 - 2ar - 26br + a^2 + b^2 = (pr + c)^2 \] Comparing coefficients, we will find that \(a = 0\) and \(b = 0\) leads to the simplification \[d = \sqrt{170r^2} \], which is rational only if both \(a\) and \(b\) are zero.
08

Conclude

Thus, the only rational point \(P = (a, b)\) such that the distance between \(P\) and any rational point on the line \(y = 13x\) is rational is \(P = (0, 0)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

distance formula
To understand this problem, we need to grasp the distance formula. The distance between two points in a plane can be calculated by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] This formula is derived from the Pythagorean theorem and includes differences along the x and y coordinates.
For example, if you want to find the distance between points \( (1, 2) \) and \( (4, 6) \), you substitute their coordinates into the formula: \[ d = \sqrt{(4 - 1)^2 + (6 - 2)^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] The result here is 5, a rational number in this case. In our exercise, you need to ensure that any distance between a point and any point on the line is rational.
rational numbers
A point \( P = (a, b) \) is rational if both coordinates \( a \) and \( b \) are rational numbers. But what are rational numbers? Rational numbers are numbers that can be expressed as a fraction \( \frac{p}{q} \) where \( p \) and \( q \) are integers and \( q \) is not zero.
Examples of rational numbers include: \[ -3, 0, 1.5 \left( = \frac{3}{2} \right), \frac{4}{7} \] Irrational numbers, by contrast, cannot be written as a fraction of two integers. Examples are \( \sqrt{2} \) and \( \pi \). In our context, we look for rational coordinates so that computations remain precise and manageable.
quadratic equations
In the given problem, the expression inside the square root must be a perfect square. Generally, a quadratic equation has the form \[ ax^2 + bx + c = 0 \]. This is essential for finding solutions where the roots can be derived formulaically.
To ensure that the expression we deal with is a quadratic equation that yields rational results, it should be similar to a perfect square, such as \[ (pr + c)^2 \]. When expanded, it should match the structure of the equation in the problem. Identifying and factoring a quadratic equation important because it often simplifies finding rational solutions for variables.
Example: Solving \[ x^2 - 5x + 6 = 0 \], you can factor it as \[ (x - 2)(x - 3) = 0 \]. Thus, \( x \) values are 2 and 3 which are rational.
perfect squares
Finally, let's understand perfect squares. A number is a perfect square if it's an integer squared. For example, \[ 1, 4, 9, 16, 25 \] are perfect squares (having squares \[ 1^2, 2^2, 3^2, 4^2, 5^2 \]). This concept is important as we check if our quadratic term, \[ 170r^2 - 2ar - 26br + a^2 + b^2 \], forms a perfect square.
For a quadratic expression to be a perfect square, it must fit the form \[ (pr + c)^2 \]. When expanded, it should not leave any ambiguous or non-integer components. In our problem, such perfect square properties simplify the rational requirement.
Identifying if the simplified quadratic in distance form equals a perfect square aids in finding rational solutions.

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Most popular questions from this chapter

Let \(f\) be a continuous function on \([0,1]\), which is bounded below by 1 , but is not identically 1 . Let \(R\) be the region in the plane given by \(0 \leq x \leq 1\), \(1 \leq y \leq f(x)\). Let $$ R_1=\\{(x, y) \in R \mid y \leq \bar{y}\\} \quad \text { and } \quad R_2=\\{(x, y) \in R \mid y \geq \bar{y}\\} $$ where \(\bar{y}\) is the \(y\)-coordinate of the centroid of \(R\). Can the volume obtained by rotating \(R_1\) about the \(x\)-axis equal that obtained by rotating \(R_2\) about the \(x\)-axis?

Suppose all the integers have been colored with the three colors red, green and blue such that each integer has exactly one of those colors. Also suppose that the sum of any two (unequal or equal) green integers is blue, the sum of any two blue integers is green, the opposite of any green integer is blue, and the opposite of any blue integer is green. Finally, suppose that 1492 is red and that 2011 is green. Describe precisely which integers are red, which integers are green, and which integers are blue.

For three points \(P, Q\), and \(R\) in \(\mathbb{R}^3\) (or, more generally, in \(\mathbb{R}^n\) ) we say that \(R\) is between \(P\) and \(Q\) if \(R\) is on the line segment connecting \(P\) and \(Q\) ( \(R=P\) and \(R=Q\) are allowed). A subset \(A\) of \(\mathbb{R}^3\) is called convex if for any two points \(P\) and \(Q\) in \(A\), every point \(R\) which is between \(P\) and \(Q\) is also in \(A\). For instance, an ellipsoid is convex, a banana is not. Now for the problem: Suppose \(A\) and \(B\) are convex subsets of \(\mathbb{R}^3\). Let \(C\) be the set of all points \(R\) for which there are points \(P\) in \(A\) and \(Q\) in \(B\) such that \(R\) lies between \(P\) and \(Q\). Does \(C\) have to be convex?

Suppose we have a configuration (set) of finitely many points in the plane which are not all on the same line. We call a point in the plane a center for the configuration if for every line through that point, there is an equal number of points of the configuration on either side of the line. a. Give a necessary and sufficient condition for a configuration of four points to have a center. b. Is it possible for a finite configuration of points (not all on the same line) to have more than one center?

Let \(\alpha=0 . d_1 d_2 d_3 \ldots\) be a decimal representation of a real number between 0 and 1. Let \(r\) be a real number with \(|r|<1\). a. If \(\alpha\) and \(r\) are rational, must \(\sum_{i=1}^{\infty} d_i r^i\) be rational? b. If \(\alpha\) and \(r\) are rational, must \(\sum_{i=1}^{\infty} i d_i r^i\) be rational? c. If \(r\) and \(\sum_{i=1}^{\infty} d_i r^i\) are rational, must \(\alpha\) be rational?

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