Chapter 9: Problem 22
Find the (a) period, (b) phase shift (if any), and (c) range of each function. $$y=-\frac{3}{2} \sec (x-\pi)$$
Short Answer
Expert verified
Period: \(2\pi\), Phase shift: \(\pi\), Range: \((-\infty, -\frac{3}{2}] \cup [\frac{3}{2}, \infty)\).
Step by step solution
01
Understand the Secant Function
The function given is a secant function: \( y=-\frac{3}{2} \sec(x-\pi) \). The basic form of a secant function is \( y = a \sec(bx - c) + d \). In this case, \( a = -\frac{3}{2} \), \( b = 1 \), \( c = \pi \), and \( d = 0 \).
02
Calculate the Period
The period of a secant function is found by the formula \( \frac{2\pi}{b} \). Here, \( b = 1 \), so the period is \( \frac{2\pi}{1} = 2\pi \).
03
Determine the Phase Shift
The phase shift of a function \( y = a \sec(bx - c) + d \) can be found using \( \frac{c}{b} \). In this case, \( c = \pi \) and \( b = 1 \), resulting in a phase shift of \( \frac{\pi}{1} = \pi \).
04
Determine the Range
The secant function has a range of \( (-\infty, -1] \cup [1, \infty) \). Since \( a = -\frac{3}{2} \), the amplitude changes the range to \( (-\infty, -\frac{3}{2}] \cup [\frac{3}{2}, \infty) \). The negative sign in front does not affect the range as the amplitude is symmetric with secant.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Secant Function
The secant function, denoted as \( \sec(x) \), is a trigonometric function that is the reciprocal of the cosine function. In other words, \( \sec(x) = \frac{1}{\cos(x)} \). This means that wherever the cosine function is zero, the secant function is undefined because division by zero is not possible. As a result, the graph of the secant function exhibits vertical asymptotes at points where the cosine function is zero, such as \( x = \frac{\pi}{2} + k\pi \) where \( k \) is an integer.
The general form of a secant function is given by \( y = a \sec(bx - c) + d \), where:
This transformation allows us to study how the secant function's graph is transformed from its basic form.
The general form of a secant function is given by \( y = a \sec(bx - c) + d \), where:
- \( a \) is the amplitude, affecting the vertical stretch or compression
- \( b \) affects the period of the function
- \( c \) influences the phase shift
- \( d \) shifts the graph vertically
This transformation allows us to study how the secant function's graph is transformed from its basic form.
Period of a Function
The period of a trigonometric function is the length of one complete cycle of the wave before it repeats itself. For a basic secant function \( y = \sec(x) \), the period is \( 2\pi \), similar to that of the cosine function.
When we encounter a function of the form \( y = a \sec(bx - c) + d \), the period is altered by the parameter \( b \). The formula to find the period of such a function is \( \frac{2\pi}{b} \).
For instance, in the function \( y=-\frac{3}{2} \sec(x-\pi) \), where \( b = 1 \), the period remains \( 2\pi \). This is because \( \frac{2\pi}{1} = 2\pi \). Understanding the period is crucial as it tells us how frequently the secant function's cycles repeat.
When we encounter a function of the form \( y = a \sec(bx - c) + d \), the period is altered by the parameter \( b \). The formula to find the period of such a function is \( \frac{2\pi}{b} \).
For instance, in the function \( y=-\frac{3}{2} \sec(x-\pi) \), where \( b = 1 \), the period remains \( 2\pi \). This is because \( \frac{2\pi}{1} = 2\pi \). Understanding the period is crucial as it tells us how frequently the secant function's cycles repeat.
Phase Shift
A phase shift in a trigonometric function occurs when the entire graph of the function is shifted horizontally. The phase shift can be calculated from the equation \( y = a \sec(bx - c) + d \) using the expression \( \frac{c}{b} \). The result gives how much the graph of the function is moved along the x-axis.
Taking our example \( y=-\frac{3}{2} \sec(x-\pi) \), the constants are \( c = \pi \) and \( b = 1 \). Thus, the phase shift is \( \frac{\pi}{1} = \pi \). This indicates that the entire secant function is shifted to the right by \( \pi \) units. Phase shifts are important when aligning graphs of trigonometric functions with real-world cyclic phenomena.
Taking our example \( y=-\frac{3}{2} \sec(x-\pi) \), the constants are \( c = \pi \) and \( b = 1 \). Thus, the phase shift is \( \frac{\pi}{1} = \pi \). This indicates that the entire secant function is shifted to the right by \( \pi \) units. Phase shifts are important when aligning graphs of trigonometric functions with real-world cyclic phenomena.
Range of a Function
The range of a function is the set of all possible output values. For the secant function, the typical range is \((-\infty, -1] \cup [1, \infty)\). This is due to the secant function being the reciprocal of the cosine function, which only takes values from -1 to 1.
In transformed secant functions, the parameter \( a \) modifies the range. If we consider the function \( y = -\frac{3}{2} \sec(x-\pi) \), the amplitude \( -\frac{3}{2} \) changes the range to \((-\infty, -\frac{3}{2}] \cup [\frac{3}{2}, \infty)\). The negative sign reflects the secant graph across the x-axis but leaves the range form unaffected, as it is symmetric around the x-axis.
The range is vital to understand because it identifies all the y-values a function can achieve, helping to predict outcomes in mathematical modeling.
In transformed secant functions, the parameter \( a \) modifies the range. If we consider the function \( y = -\frac{3}{2} \sec(x-\pi) \), the amplitude \( -\frac{3}{2} \) changes the range to \((-\infty, -\frac{3}{2}] \cup [\frac{3}{2}, \infty)\). The negative sign reflects the secant graph across the x-axis but leaves the range form unaffected, as it is symmetric around the x-axis.
The range is vital to understand because it identifies all the y-values a function can achieve, helping to predict outcomes in mathematical modeling.