Chapter 8: Problem 95
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$y=-2(x+3)^{2}+2$$
Short Answer
Expert verified
Vertex: (-3, 2), Axis: x = -3, Domain: all real numbers, Range: (-∞, 2].
Step by step solution
01
Identify the Parabola Form
The given equation of the parabola is in vertex form, which is \( y = a(x-h)^2 + k \). Comparing this with the given equation \( y = -2(x+3)^2 + 2 \), we identify \( a = -2 \), \( h = -3 \), and \( k = 2 \).
02
Determine the Vertex
The vertex of a parabola in vertex form \( y = a(x-h)^2 + k \) is \((h, k)\). For the equation \( y = -2(x+3)^2 + 2 \), the vertex is \((-3, 2)\).
03
Find the Axis of Symmetry
The axis of symmetry for a parabola in the form \( y = a(x-h)^2 + k \) is the vertical line \( x = h \). Hence, for our equation, the axis of symmetry is \( x = -3 \).
04
Determine the Domain
The domain of any quadratic function is all real numbers, \( x \in \mathbb{R} \). Thus, the domain is \( (-\infty, \infty) \).
05
Determine the Range
Since the parabola opens downward (as \( a = -2 < 0 \)), the maximum value occurs at the vertex, \( y = 2 \). Thus, the range of the function is \( (-\infty, 2] \).
06
Graph the Parabola by Hand
Plot the vertex \((-3, 2)\) on the coordinate plane. Because \( a = -2 \), the parabola is oriented downwards. Sketch a symmetrical U-shape around the axis of symmetry \( x = -3 \). Check the graph for accuracy using a graphing calculator.
07
Verify with a Graphing Calculator
Enter the equation \( y = -2(x+3)^2 + 2 \) into a graphing calculator. Ensure that the graph corresponds to the sketched graph: a downward-opening parabola with the vertex at \((-3, 2)\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex Form
The vertex form of a quadratic function is a special way to express the equation of a parabola. It is written as: \[ y = a(x-h)^2 + k \]where
- \(a\) determines the width and direction of the parabola. If \(a\) is positive, the parabola opens upwards, if negative, it opens downwards.
- \(h\) and \(k\) are the coordinates of the vertex of the parabola.
Axis of Symmetry
The axis of symmetry is an imaginary vertical line that divides the parabola into two mirror-image halves. Every point on one side of the axis has a corresponding point on the opposite side. For the vertex form equation \( y = a(x-h)^2 + k \), the axis of symmetry has the equation: \[ x = h \]This means that the axis of symmetry is always a vertical line passing through the vertex's x-coordinate. For our example equation, \( y = -2(x+3)^2 + 2 \), the axis of symmetry is: \[ x = -3 \]This simplifies the graphing process, as you can ensure both sides of the parabola are symmetrical about this line.
Domain and Range
The domain and range of a quadratic function describe the set of possible input (x-values) and output (y-values), respectively. **Domain**For any quadratic function, including our example \( y = -2(x+3)^2 + 2 \), the domain is all real numbers. This is because parabolas extend infinitely in both directions along the x-axis. Thus, we write the domain as: \[ x \in (-\infty, \infty) \]**Range**The range, however, depends on the direction the parabola opens. Since our parabola opens downward (indicated by the negative \( a\)), it has a maximum value at the vertex, which is the y-coordinate of the vertex. Therefore, the range for our parabola is all values less than or equal to 2: \[ y \in (-\infty, 2] \]This means the function produces values from negative infinity up to the vertex height.
Quadratic Function
A quadratic function is a polynomial function of degree 2, characterized by the form: \[ y = ax^2 + bx + c \]However, rearranging into vertex form by completing the square can provide insights that are more intuitive for graphing, as seen in our example problem.
- **Standard Form:** Gives immediate information about the parabola's y-intercept (\( c \)) and can be transformed into vertex form to find the vertex easily.
- **Vertex Form:** Immediately tells us the vertex and can also be used to determine the direction and stretch of the parabola.