Chapter 8: Problem 106
Graph each parabola by hand, and check using a graphing calculator. Give the vertex, axis, domain, and range. $$x=-2(y+3)^{2}$$
Short Answer
Expert verified
Vertex: (0, -3); Axis: y = -3; Domain: (-∞, 0]; Range: (-∞, ∞).
Step by step solution
01
Identify the form of the parabola
The given equation is \( x = -2(y + 3)^2 \). This is in the form \( x = a(y - k)^2 + h \), which represents a parabola that opens sideways. In this case, the parabola opens left because the coefficient \( a = -2 \) is negative.
02
Find the vertex
The vertex \((h, k)\) of a parabola in the form \( x = a(y - k)^2 + h \) is \((h, k) = (0, -3)\). Therefore, the vertex of this parabola is the point \((0, -3)\).
03
Determine the axis of symmetry
For a sideways opening parabola, the axis of symmetry is a horizontal line through the vertex. Since our vertex is \((0, -3)\), the axis of symmetry is \( y = -3 \).
04
Determine the domain and range
Since the parabola opens to the left and is not bounded on the negative x-direction, the domain is \( (-fty, 0] \). The range of a sideways parabola is all real numbers, so the range is \((-fty, fty)\).
05
Graph the parabola
Plot the vertex at \((0, -3)\) on graph paper. Since the parabola opens left with the axis of symmetry \( y = -3 \), plot additional points by choosing y-values and calculating the corresponding x-values from the equation \( x = -2(y + 3)^2 \). Draw a smooth curve through these points to represent the parabola.
06
Verify using a graphing calculator
Input the equation \( x = -2(y + 3)^2 \) into a graphing calculator. Confirm that the generated graph aligns with the hand-drawn parabola, ensuring the vertex, direction, and axis of symmetry are correctly represented.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex
The vertex of a parabola is a critical point that indicates the position of the parabola's minimum or maximum value. In our specific problem, the parabola's equation is given as \( x = -2(y + 3)^2 \). This equation is structured in the standard form \( x = a(y - k)^2 + h \), where the vertex is represented by \((h, k)\).
For the given equation \( x = -2(y + 3)^2 \), by comparing it to the standard form, we can see that the vertex is located at the point \((0, -3)\).
This point tells us where the parabola turns and starts opening to one side. Because the coefficient \(a\) is negative in this case \((a = -2)\), this parabola opens to the left, with the vertex sitting on the boundary.
For the given equation \( x = -2(y + 3)^2 \), by comparing it to the standard form, we can see that the vertex is located at the point \((0, -3)\).
This point tells us where the parabola turns and starts opening to one side. Because the coefficient \(a\) is negative in this case \((a = -2)\), this parabola opens to the left, with the vertex sitting on the boundary.
Axis of Symmetry
The axis of symmetry is a line that runs through the vertex and divides the parabola into two mirror-image halves. For vertically opening parabolas, this line is vertical, while for horizontal parabolas like ours, it's horizontal.
Our equation \( x = -2(y + 3)^2 \) uncovers the axis of symmetry as being \( y = -3 \), which is aligned horizontally through the vertex \((0, -3)\).
It's helpful to think of the axis of symmetry as a balanced centerline, ensuring the shape is symmetrical.
Our equation \( x = -2(y + 3)^2 \) uncovers the axis of symmetry as being \( y = -3 \), which is aligned horizontally through the vertex \((0, -3)\).
It's helpful to think of the axis of symmetry as a balanced centerline, ensuring the shape is symmetrical.
Domain and Range
Understanding the domain and range of a parabola can help in sketching the graph accurately. The domain specifies all the possible x-values the parabola can have, whereas the range specifies all the possible y-values.
In the given parabola \( x = -2(y + 3)^2 \), the sideways opening implies that the domain is restricted on one end.
In the given parabola \( x = -2(y + 3)^2 \), the sideways opening implies that the domain is restricted on one end.
- **Domain:** For our equation, the parabola opens left. The domain is \((-ty, 0]\). This means x-values range from negative infinity to 0.
- **Range:** Our sideways parabola accepts all possible y-values. Thus, the range is \((-ty, ty)\).
Graphing Techniques
Graphing a parabola by hand can be simplified through understanding the relations and equations involved. With our equation \( x = -2(y + 3)^2 \), follow these easy steps to make the graphing process practical:
- **Plot the Vertex:** Begin by marking the vertex at \((0, -3)\) on a graph.
- **Mark the Axis of Symmetry:** Draw the horizontal line \( y = -3 \) to visualize symmetry.
- **Choose Additional Points:** Select a few convenient y-values, substitute them into the equation, and calculate corresponding x-values.
- **Draw the Curve:** Connect your points with a smooth curve. Note the opening direction is left due to the negative coefficient.