Chapter 7: Problem 28
Solve each determinant equation for \(x\). $$\operatorname{det}\left[\begin{array}{ll}x & 3 \\\x & x\end{array}\right]=4$$
Short Answer
Expert verified
The solutions are \( x = 4 \) and \( x = -1 \).
Step by step solution
01
Understand the Determinant Formula for a 2x2 Matrix
The determinant of a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \) is calculated as \( ad - bc \). First, apply this formula to the given matrix: \( \begin{bmatrix} x & 3 \ x & x \end{bmatrix} \).
02
Express the Determinant Using Elements
For the matrix \( \begin{bmatrix} x & 3 \ x & x \end{bmatrix} \), we use the formula from Step 1. Here, \( a = x \), \( b = 3 \), \( c = x \), and \( d = x \). Therefore, the determinant is: \( (x)(x) - (3)(x) \). Simplifying, we get: \( x^2 - 3x \).
03
Set the Determinant Equal to the Given Value
The problem states that the determinant of the matrix equals 4. So, we have the equation: \( x^2 - 3x = 4 \).
04
Rearrange the Equation Into Standard Quadratic Form
To solve this quadratic equation, rearrange it to the standard form \( ax^2 + bx + c = 0 \). This gives us \( x^2 - 3x - 4 = 0 \).
05
Solve the Quadratic Equation
To solve \( x^2 - 3x - 4 = 0 \), we can factor it. We look for two numbers whose product is \(-4\) and sum is \(-3\). These numbers are \(-4\) and \(1\). So, the equation factors to: \((x - 4)(x + 1) = 0 \).
06
Find the Solutions for \(x\)
Solve each factor equal to zero: \( x - 4 = 0 \) gives \( x = 4 \), and \( x + 1 = 0 \) gives \( x = -1 \). Thus, the solutions are \( x = 4 \) and \( x = -1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a type of polynomial equation that has the highest variable exponent of 2, meaning it can be written in the form \( ax^2 + bx + c = 0 \). Here, \( a \), \( b \), and \( c \) are constants, and \( x \) is the variable. Quadratic equations have many practical applications in physics, engineering, and more. By turning a problem into a quadratic equation, we can find solutions using different methods.
Some common methods for solving quadratic equations include:
Some common methods for solving quadratic equations include:
- Factoring: Expressing the equation as a product of its linear factors. If it works, it's usually the simplest method.
- Completing the square: Rewriting the equation as a perfect square trinomial, which allows for easier solving.
- Quadratic formula: This formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) works for any quadratic equation.
2x2 Matrix
A 2x2 matrix is a simple mathematical structure consisting of four elements arranged in two rows and two columns. Matrices are widely used in many areas like physics, computer science, and economics. A matrix can represent a variety of things such as transformations in space, a system of equations, or even just data.
For a 2x2 matrix written as \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), each element can have practical significance depending on the context it is used in. For example:
For a 2x2 matrix written as \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), each element can have practical significance depending on the context it is used in. For example:
- Matrix transformations: A 2x2 matrix might represent linear transformations in a 2D space.
- Systems of equations: They can represent and solve systems with two linear equations.
Determinant Calculation
Calculating a determinant is an essential operation in linear algebra, used to evaluate certain properties of matrices, such as invertibility. For a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the determinant is calculated using the formula \( ad - bc \).
This determinant calculation is crucial because:
This determinant calculation is crucial because:
- Matrix Invertibility: If a matrix has a non-zero determinant, it is invertible, meaning it has an inverse matrix.
- Volume and area calculations: In geometry, determinants can reflect scale changes in linear transformations.