/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Explain why a \(2 \times 2\) mat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why a \(2 \times 2\) matrix will not have an inverse if either a column or a row contains all 0 s.

Short Answer

Expert verified
A \(2 \times 2\) matrix cannot have an inverse if it has an all-zero row or column because its determinant is zero.

Step by step solution

01

Understanding Matrix Non-Invertibility

A matrix is non-invertible (or singular) if its determinant is zero. It's crucial to analyze how specific properties of a matrix lead to a zero determinant.
02

Evaluate Determinant Formula for a 2x2 Matrix

For a general \(2 \times 2\) matrix: \(\begin{pmatrix} a & b \ c & d \end{pmatrix}\), the determinant is calculated as \(ad - bc\). A non-zero determinant implies the matrix is invertible.
03

Assess Impact of All-Zero Row or Column

If one row or column of a \(2 \times 2\) matrix is all zeros, substitute zero values into the determinant formula. For an all-zero row: \(\begin{pmatrix} 0 & 0 \ c & d \end{pmatrix}\) yields a determinant of \(0 \times d - 0 \times c = 0\). For an all-zero column: \(\begin{pmatrix} a & b \ 0 & 0 \end{pmatrix}\) yields a determinant of \(a \times 0 - b \times 0 = 0\).
04

Conclusion on Non-Invertibility

The determinant is zero in both cases, confirming that having a row or a column of all zeros makes the matrix singular, meaning it does not have an inverse.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

2x2 matrices
A 2x2 matrix is a simple yet fundamental concept in linear algebra. This type of matrix has two rows and two columns, making it easy to visualize and work with. As such, it is represented as:
  • \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \)
Each element in the matrix corresponds to a specific row and column, with the first entry \(a\) being in the first row and first column, and so on. Understanding how these elements interact is key to grasping the matrix's properties. In practical terms, 2x2 matrices are used in various applications, from simple transformations to systems of linear equations. Such matrices offer a straightforward way to model and solve problems, provided their properties are well understood. Regular breakpoints in text can help keep learners engaged.
determinant calculation
Calculating the determinant of a 2x2 matrix is a fundamental skill in matrix algebra. The determinant, essentially a special scalar, provides insights into the matrix's properties. For a general 2x2 matrix:
  • \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \)
The determinant is given by \(ad - bc\). This formula reveals a lot about the matrix. If the determinant is zero, the matrix is singular and cannot be inverted. Conversely, a non-zero determinant indicates that the matrix is invertible and unique solutions to related linear systems exist. The determinant plays a crucial role in applications such as calculating the area of parallelograms formed by matrix rows or columns, making it a versatile mathematical tool.
singular matrix
A matrix is described as singular when it does not have an inverse. For a 2x2 matrix, this occurs when its determinant equals zero. A singular matrix usually arises when the matrix has been improperly defined—such as having a row or a column consisting entirely of zeros:
  • \( \begin{pmatrix} 0 & 0 \ c & d \end{pmatrix} \) or \( \begin{pmatrix} a & b \ 0 & 0 \end{pmatrix} \)
The determinants in both cases are \(0\), leading to singular matrices. This lack of invertibility is significant because it implies that any matrix transformation described by the singular matrix cannot be reversed or undone. In practical terms, matrices often become singular when certain conditions lead to the loss of information, such as identical rows or columns, rendering them ineffective as a tool for encoding transformations. Understanding this concept is key to avoiding potential pitfalls in higher mathematics and computational applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Given a square matrix \(A^{-1}\), find matrix \(A\). $$A^{-1}=\left[\begin{array}{ll} \frac{3}{20} & \frac{1}{4} \\ -\frac{1}{20} & \frac{1}{4} \end{array}\right]$$

A shop manufactures two types of bolts on three groups of machines. The time required on each group differs, as shown in the following table.\begin{array}{|c|c|c|c|}\hline\hline & \text { Machine Group } \\ \hline \text { Bolt } & \mathbf{I} & \mathbf{I I} & \mathbf{I I I} \\\\\hline \text { Type A } & 0.1 \mathrm{min} & 0.1 \mathrm{min} & 0.1 \mathrm{min} \\\\\text { Type B } & 0.1 \mathrm{min} & 0.4 \mathrm{min} & 0.5 \mathrm{min}\end{array}.In a day, there are \(240,720,\) and 160 minutes available, respectively, on these machines. Type A bolts sell for S0.10 and Type B bolts for S0.12. How many of each type of bolt should be manufactured per day to maximize revenue? What is the maximum revenue?

Use Cramer's rule to solve each system of equations. If \(D=0,\) use another method to complete the solution. $$\begin{aligned}3 x+2 y-w &=0 \\\2 x+z+2 w &=5 \\\x+2 y-z &=-2 \\\2 x-y+z+w &=2\end{aligned}$$

Theo requires two food supplements:I and II. He can get these supplements from two different products \(A\) and \(B,\) as shown in the following table.$$\begin{array}{l|c|c}\hline \text { Supplement (grams/serving) } & \text { I } & \text { II } \\\\\hline \text { Product } A & 3 & 2 \\\\\text { Product } B & 2 & 4\end{array}$$.Theo's physician recommends at least 15 grams of each supplement in Theo's daily diet. If product \(A\) costs \(25 \phi\) per serving and product \(B\) costs \(40 \notin\) per serving, how can he satisfy his requirements most economically?

For each matrix, find \(A^{-1}\) if it exists. $$A=\left[\begin{array}{lll} \frac{1}{2} & \frac{1}{4} & \frac{1}{3} \\ 0 & \frac{1}{4} & \frac{1}{3} \\ \frac{1}{2} & \frac{1}{2} & \frac{1}{3} \end{array}\right]$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.