Chapter 6: Problem 76
Use the properties of logarithms to rewrite each logarithm if possible. Assume that all variables represent positive real numbers. $$\log _{p} \sqrt[3]{\frac{m^{5}}{k t^{2}}}$$
Short Answer
Expert verified
\( \frac{5}{3} \cdot \log_{p}(m) - \frac{1}{3} \cdot \log_{p}(k) - \frac{2}{3} \cdot \log_{p}(t) \)
Step by step solution
01
Rewrite the Radical Using Exponents
The expression inside the logarithm is \( \sqrt[3]{\frac{m^{5}}{kt^{2}}} \), which can be rewritten using exponents as \( \left( \frac{m^{5}}{kt^{2}} \right)^{\frac{1}{3}} \). This step helps in simplifying the expression using properties of exponents.
02
Use the Power Rule of Logarithms
Apply the power rule, which states \( \log_{b}(x^a) = a \cdot \log_{b}(x) \). So, \( \log_{p} \left( \frac{m^{5}}{kt^{2}} \right)^{\frac{1}{3}} = \frac{1}{3} \cdot \log_{p} \left( \frac{m^{5}}{kt^{2}} \right) \).
03
Apply the Quotient Rule of Logarithms
The quotient rule for logarithms states \( \log_{b} \left( \frac{x}{y} \right) = \log_{b}(x) - \log_{b}(y) \). Apply this to get \( \log_{p}(m^{5}) - \log_{p}(kt^{2}) \).
04
Apply the Power Rule Again
Use the power rule on each term: \( \log_{p}(m^{5}) = 5 \cdot \log_{p}(m) \) and \( \log_{p}(kt^{2}) = \log_{p}(k) + \log_{p}(t^{2}) = \log_{p}(k) + 2 \cdot \log_{p}(t) \).
05
Combine All Parts Together
Substitute back into the original expression: \( \frac{1}{3} \cdot \left( 5 \cdot \log_{p}(m) - (\log_{p}(k) + 2 \cdot \log_{p}(t)) \right) \). Simplify further to get \( \frac{1}{3} \left( 5 \cdot \log_{p}(m) - \log_{p}(k) - 2 \cdot \log_{p}(t) \right) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule
The Power Rule is a significant property of logarithms that makes simplifying expressions a breeze. It states that if you have a logarithm of the form \( \log_{b}(x^a) \), it can be rewritten as \( a \cdot \log_{b}(x) \). This rule simplifies the process of managing exponents within a logarithm.
For example, in the expression \( \log_{p} \left( \frac{m^{5}}{kt^{2}} \right)^{\frac{1}{3}} \), the \( \frac{1}{3} \) suggests that the entire fraction is raised to the power of \( \frac{1}{3}\).
**Benefits of the Power Rule**
For example, in the expression \( \log_{p} \left( \frac{m^{5}}{kt^{2}} \right)^{\frac{1}{3}} \), the \( \frac{1}{3} \) suggests that the entire fraction is raised to the power of \( \frac{1}{3}\).
**Benefits of the Power Rule**
- Simplification: It breaks down complex expressions, making them easier to handle.
- Efficiency: Calculations can be performed more swiftly, especially when dealing with high powers.
Quotient Rule
The Quotient Rule of logarithms is invaluable when dealing with fractions inside a logarithmic expression. It posits that \( \log_{b} \left( \frac{x}{y} \right) = \log_{b}(x) - \log_{b}(y) \). This rule helps break down the fraction into manageable parts.
Continuing with the example \( \log_{p} \left( \frac{m^{5}}{kt^{2}} \right) \), using the quotient rule simplifies it to \( \log_{p}(m^{5}) - \log_{p}(kt^{2}) \).
**Key Points about the Quotient Rule**
Continuing with the example \( \log_{p} \left( \frac{m^{5}}{kt^{2}} \right) \), using the quotient rule simplifies it to \( \log_{p}(m^{5}) - \log_{p}(kt^{2}) \).
**Key Points about the Quotient Rule**
- Decomposition: Convert complex expressions into simpler components.
- Problem Solving: Makes finding solutions more accessible and less daunting.
Exponents
Exponents are an essential part of mathematics and are often intertwined with logarithms. They represent the power to which a number or expression is raised. For instance, \( m^{5} \) means that \( m \) is multiplied by itself five times.
In the context of our example, exponents play a vital role when expressing roots as fractional exponents. The expression \( \sqrt[3]{\frac{m^{5}}{kt^{2}}} \) is first converted to \( \left( \frac{m^{5}}{kt^{2}} \right)^{\frac{1}{3}} \) using the properties of exponents.
**Features of Exponents**
In the context of our example, exponents play a vital role when expressing roots as fractional exponents. The expression \( \sqrt[3]{\frac{m^{5}}{kt^{2}}} \) is first converted to \( \left( \frac{m^{5}}{kt^{2}} \right)^{\frac{1}{3}} \) using the properties of exponents.
**Features of Exponents**
- Simplifying Roots: Transforms root expressions into fractional powers, easing calculations.
- Foundational for Logarithms: Often simplified further using the Power Rule.