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For each function that is one-to-one, write an equation for the inverse function of \(y=f(x)\) in the form \(y=f^{-1}(x),\) and then graph \(f\) and \(f^{-1}\) on the same axes. Give the domain and range of \(f\) and \(f^{-1} .\) If the function is not one-to-one, say so. $$y=\frac{4}{x}$$

Short Answer

Expert verified
The function is one-to-one; its inverse is \( y = \frac{4}{x} \). Domain and range are \( x \neq 0 \) and \( y \neq 0 \), respectively.

Step by step solution

01

Identify if the function is one-to-one

The function is defined as \( y = \frac{4}{x} \). A function is one-to-one if each input \( x \) in the domain corresponds to a unique output \( y \), and each \( y \) comes from a unique \( x \). For this rational function, each \( y \) value has exactly one \( x \) value associated with it due to the inverse nature of division, thus making the function one-to-one.
02

Find the inverse of the function

To find the inverse function \( y = f^{-1}(x) \), start by replacing \( y \) with \( x \) in the equation: \( x = \frac{4}{y} \). Then, solve for \( y \): multiply both sides by \( y \) to get \( xy = 4 \). Divide both sides by \( x \) to find \( y = \frac{4}{x} \). Therefore, the inverse function \( y = f^{-1}(x) \) is the same as the original: \( y = \frac{4}{x} \).
03

Graph the functions

Graph both \( f(x) = \frac{4}{x} \) and its inverse \( f^{-1}(x) = \frac{4}{x} \). These functions will appear as the same graph because the function is its own inverse. The graph is a hyperbola with two branches, approaching the axes but never crossing them.
04

Determine the domain and range

For the original function \( y = \frac{4}{x} \), the domain is all real numbers except \( x = 0 \) (i.e., \( x \in \mathbb{R}, x eq 0 \)) because division by zero is undefined. The range is all real numbers except \( y = 0 \) (i.e., \( y \in \mathbb{R}, y eq 0 \)). For the inverse function, the domain and range are identical to those of the original function: all real numbers except zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

One-to-One Function
Understanding the concept of a one-to-one function is crucial in mathematical analysis, particularly when dealing with inverse functions. A function is classified as one-to-one if for every different input value, there is a unique output value, ensuring that no two distinct inputs produce the same output.This characteristic allows the function to pass the horizontal line test, which means that no horizontal line intersects the graph of the function more than once. If a function is one-to-one, it guarantees an inverse function exists and that this inverse is also a function.
In the example given, the function \(y = \frac{4}{x}\) is considered one-to-one because each output \(y\) is uniquely associated with exactly one input \(x\). This means that there is a direct correlation between each \(x\) and its corresponding \(y\), ensuring the invertibility of the function.
Domain and Range
The domain and range are fundamental concepts when analyzing functions. The domain of a function is the complete set of possible input values (or \(x\) values), while the range is the complete set of all possible output values (or \(y\) values).
For the function \(y = \frac{4}{x}\), determining the domain involves identifying all the real numbers that \(x\) can be without causing mathematical issues, such as division by zero. Thus, the domain of this rational function is all real numbers except for zero: \(x \in \mathbb{R}, x eq 0\).
Correspondingly, the range consists of all real numbers that the function can produce. For \(y = \frac{4}{x}\), the range is also all real numbers except zero, \(y \in \mathbb{R}, y eq 0\). This symmetry in domain and range arises because \(y = \frac{4}{x}\) is its own inverse, leading to identical domain and range for the function and its inverse.
Rational Function
Rational functions are quotients of polynomials and are expressed in the form \(\frac{p(x)}{q(x)}\), where both \(p(x)\) and \(q(x)\) are polynomials, and \(q(x)\) is not the zero polynomial.
The function \(y = \frac{4}{x}\) is a simple rational function where the numerator is a constant polynomial, and the denominator is a linear polynomial \(x\). These types of functions often appear as hyperbolas when graphed.Moreover, rational functions can exhibit vertical asymptotes, which occur at values of \(x\) that cause the denominator to be zero, leading \(y\) to become undefined. For \(y = \frac{4}{x}\), this asymptote is at \(x = 0\).
Additionally, there may be horizontal or oblique asymptotes, which describe the behavior of the function as \(x\) tends to positive or negative infinity. In our function, the behavior at infinity reflects the horizontal asymptote of \(y = 0\). Understanding these characteristics helps in graphing and analyzing the behavior of rational functions.

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Most popular questions from this chapter

For each function that is one-to-one, write an equation for the inverse function of \(y=f(x)\) in the form \(y=f^{-1}(x),\) and then graph \(f\) and \(f^{-1}\) on the same axes. Give the domain and range of \(f\) and \(f^{-1} .\) If the function is not one-to-one, say so. $$y=\frac{3}{x-4}$$

Although a function may not be one-to-one when defined over its "natural" domain, it may be possible to restrict the domain in such a way that it is one-to-one and the range of the function is unchanged. For example, if we nestrict the domain of the function \(f(x)=x^{2}\) (which is not one-to-one over \((-\infty, \infty)\) to \([0, \infty)\), we obtain a one-to-one function whose range is still \([0, \infty)\) See the figure to the right. Notice that we could choose to restrict the domain of \(f(x)=x^{2}\) to \((-\infty, 0]\) and also obtain the graph of a one-to-one function, except that it would be the left half of the parabola. For each function in Exercises \(117-122\), restrict the domain so that the function is one-to-one and the range is not changed. You may wish to use a graph to help decide. Answers may vary. (GRAPHS CANNOT COPY) $$f(x)=-x^{2}+4$$

Use a graphing calculator to solve each equation. Give solutions to the nearest hundredth. $$2^{-x}=\log x$$

Explain how the graph of \(y=-3^{x}+7\) can be obtained from the graph of \(y=3^{x}\).

In general, it is not possible to find exact solutions analytically for equations that involve exponential or logarithmic functions together with polynomial, radical, and rational functions. Solve each equation using a graphical method, and express solutions to the nearest thousandth if an approximation is appropriate. $$e^{x}=\frac{1}{x+2}$$

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