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Use the definition of inverse functions to show analytically that \(f\) and \(g\) are inverses. $$f(x)=-x^{7}, \quad g(x)=-\sqrt[7]{x}$$

Short Answer

Expert verified
The functions \( f(x) = -x^7 \) and \( g(x) = -\sqrt[7]{x} \) are inverses.

Step by step solution

01

Understanding the Definition of Inverse Functions

Two functions, \( f \) and \( g \), are inverses if \( f(g(x)) = x \) and \( g(f(x)) = x \) for every \( x \) in the domains of \( g \) and \( f \) respectively. Our task is to show that these two conditions hold true for the given functions \( f(x) = -x^7 \) and \( g(x) = -\sqrt[7]{x} \).
02

Checking \( f(g(x)) = x \)

Substitute \( g(x) = -\sqrt[7]{x} \) into \( f(x) = -x^7 \). \[f(g(x)) = f(-\sqrt[7]{x}) = -(-\sqrt[7]{x})^7 = -(\sqrt[7]{x})^7 = -x\]This simplifies to \( x \) because \( -(\sqrt[7]{x})^7 \) results in \( -x \). Therefore, \( f(g(x)) = x \) is satisfied.
03

Checking \( g(f(x)) = x \)

Substitute \( f(x) = -x^7 \) into \( g(x) = -\sqrt[7]{x} \).\[g(f(x)) = g(-x^7) = -\sqrt[7]{-x^7} = -(-x)^7^{(1/7)} = x\]This simplifies to \( x \) because taking the 7th root and then negating brings us back to \( x \). Thus, \( g(f(x)) = x \) is satisfied.
04

Conclusion

Since both conditions \( f(g(x)) = x \) and \( g(f(x)) = x \) are satisfied, the functions \( f(x) = -x^7 \) and \( g(x) = -\sqrt[7]{x} \) are inverses of each other.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Composition
Function composition is a process by which you combine two functions to form a new one. This usually involves substituting one function into another. In the context of inverse functions, composition is essential. It helps us verify that two functions are indeed inverses of each other. The key idea here is that if two functions, say \( f \) and \( g \), are inverses, then composing them will return the original input value. This happens twice: once in one order (\( f(g(x)) = x \)) and in the reverse (\( g(f(x)) = x \)). This verifies that applying one function undoes the operation of the other.
Remember, in the function \( f(g(x)) \), you take the function \( g \), apply it to \( x \), and then use \( f \) on the result from \( g \). To visualize: it's like layering actions where each action perfectly undoes what the other does, returning to the start. This is the heart of confirming two functions are inverses via composition.
Algebraic Simplification
When working with inverse functions, algebraic simplification is the process you use to express functions in their simplest form. It is indispensable for verifying the equality in function compositions. In our example, we confirm \( f(g(x)) = x \) and \( g(f(x)) = x \) through simplification.
  • For \( f(g(x)) = -(-\sqrt[7]{x})^7 \): Here, we simplify expontential terms and sign flips to arrive at \( -x \), which further simplifies to just \( x \).
  • For \( g(f(x)) = -\sqrt[7]{-x^7} \): Properly managing signs and applying roots, we find \( (-x)^{1/7} \) simplifies to just \( x \) after negation and root extraction.
These simplifications help ensure that the operations on the functions effectively lead back to the starting value \( x \), confirming the inverse relationship.
Domain and Range
Domain and range are fundamental aspects to understanding function relationships and their inverse qualities. The domain refers to all possible input values for a function. The range, meanwhile, is all possible output values.
When evaluating inverses like \( f \) and \( g \), attention to domain and range is crucial.
  • The domain of \( f(x) = -x^7 \) is all real numbers, since any real number can be raised to the 7th power and multiplied by -1. Its range is also all real numbers because power and negation cover any real values.
  • For \( g(x) = -\sqrt[7]{x} \), however, the domain is all real numbers as only real numbers have real 7th roots. The range, again, covers all real numbers thanks to the 7th root followed by negation.
The perfect symmetry here—each function's range matching the other's domain—enables the functions to perfectly undo each other’s operations, confirming their inverse nature.

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Most popular questions from this chapter

Although a function may not be one-to-one when defined over its "natural" domain, it may be possible to restrict the domain in such a way that it is one-to-one and the range of the function is unchanged. For example, if we nestrict the domain of the function \(f(x)=x^{2}\) (which is not one-to-one over \((-\infty, \infty)\) to \([0, \infty)\), we obtain a one-to-one function whose range is still \([0, \infty)\) See the figure to the right. Notice that we could choose to restrict the domain of \(f(x)=x^{2}\) to \((-\infty, 0]\) and also obtain the graph of a one-to-one function, except that it would be the left half of the parabola. For each function in Exercises \(117-122\), restrict the domain so that the function is one-to-one and the range is not changed. You may wish to use a graph to help decide. Answers may vary. (GRAPHS CANNOT COPY) $$f(x)=-x^{2}+4$$

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