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Chapter 6: Problem 105

In general, it is not possible to find exact solutions analytically for equations that involve exponential or logarithmic functions together with polynomial, radical, and rational functions. Solve each equation using a graphical method, and express solutions to the nearest thousandth if an approximation is appropriate. $$x^{2}=2^{x}$$

Short Answer

Expert verified
The solutions to the equation \(x^2 = 2^x\) are approximately \(x \approx 0.766\) and \(x \approx 2\).

Step by step solution

01

Understanding the Equation

The given equation is \(x^2 = 2^x\). It involves both an exponential function, \(2^x\), and a polynomial function, \(x^2\). These types of equations are generally solved by numerical or graphical methods due to their complexity.
02

Setting Up the Graph

To solve the equation graphically, we consider two functions: \(f(x) = x^2\) and \(g(x) = 2^x\). We need to find the points where these two graphs intersect, because these points represent the solutions to the equation \(x^2 = 2^x\).
03

Drawing the Graphs

Plot the graph of \(f(x) = x^2\), which is a parabola opening upwards, and \(g(x) = 2^x\), which is an exponential function, on the same set of axes. Use a graphing calculator or software like Desmos or GeoGebra to draw these graphs accurately.
04

Finding the Intersection Points

Use the graph to identify the x-coordinates of the intersection points of the two functions. These points are where the value of \(f(x)\) equals the value of \(g(x)\). Check the graph around the visible intersections to note the coordinates.
05

Expressing the Solutions

From the graph, identify the precise or approximate coordinates of the intersection points. Typically, there may be two intersection points to consider. If needed, zoom in on the graph for a more accurate reading and round the x-values to the nearest thousandth.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. The general form is written as \(a^x\), where \(a\) is a positive constant, and \(x\) is the exponent. These functions grow rapidly as \(x\) increases. An important aspect of exponential functions is their continuous growth or decay.
  • - **Rapid Growth:** As \(x\) increases, \(2^x\) rises sharply, illustrating exponential growth. This makes plotting important for understanding behavior at larger \(x\) values.
  • - **Horizontal Asymptote:** Exponential functions like \(2^x\) don't touch the x-axis and approach it as \(x\) becomes very negative, showing a horizontal asymptote at \(y = 0\).
  • - **Applications:** These functions model growth processes in finance, populations, and natural sciences.
Visual representation via graphs can make these concepts clearer, especially when comparing them with polynomial functions like \(x^2\).
Polynomial Functions
Polynomial functions are sums of terms with non-negative integer exponents of the variable, like \(x^2\), \(x^3\), and more. The degree of the polynomial determines its shape and the number of turns.
  • - **Parabolic Shape:** For \(x^2\), the graph is a parabola opening upwards, demonstrating simplicity in depiction and complexity in intersections with other curves.
  • - **Endpoints and Turns:** Degree \(n\) of a polynomial indicates \(n-1\) potential turns in the graph. With \(x^2\), it turns once at its vertex, forming a U-shape.
  • - **Roots and Intersections:** The x-intercepts of polynomials are their roots, which are crucial while solving equations graphically.
Understanding polynomials' forms through their graphs helps in solving equations involving them together with exponential functions by visualizing points of intersection.
Intersection Points
The concept of intersection points is crucial in finding the solution to equations involving different types of functions, such as exponential and polynomial ones. Graphically solving equations like \(x^2 = 2^x\) involves plotting:
  • - **Intersection as Solution:** The solutions to the equation correspond to the x-values where the graphs of \(x^2\) and \(2^x\) meet. These are calculated as intersection points.
  • - **Graphical Approach:** Using software tools or calculators simplifies this by visually identifying the intersections. This method gives approximate solutions when exact analytical solutions are difficult to find.
  • - **Precision:** Zooming into the graph around intersections allows for more accurate readings, which are typically rounded to the nearest thousandth for precision.
Thus, intersection points not only solve equations graphically but also provide insights into the behavior of the functions involved over given domains.

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Most popular questions from this chapter

Salinity The salinity of the oceans changes with latitude and depth. In the tropics, the salinity increases on the surface of the ocean due to rapid evaporation. In the higher latitudes, there is less evaporation, and rainfall causes the salinity to be less on the surface than at lower depths. The function given by $$f(x)=31.5+1.1 \log (x+1)$$ models salinity to depths of 1000 meters at a latitude of 57.5". The variable x is the depth in meters, and \(f(x)\) is in grams of salt per kilogram of seawater. (Source: Hartman, \(D .\) Global Physical Climatology, Academic Press.) Estimate the salinity at a depth of 500 meters.

Although a function may not be one-to-one when defined over its "natural" domain, it may be possible to restrict the domain in such a way that it is one-to-one and the range of the function is unchanged. For example, if we nestrict the domain of the function \(f(x)=x^{2}\) (which is not one-to-one over \((-\infty, \infty)\) to \([0, \infty)\), we obtain a one-to-one function whose range is still \([0, \infty)\) See the figure to the right. Notice that we could choose to restrict the domain of \(f(x)=x^{2}\) to \((-\infty, 0]\) and also obtain the graph of a one-to-one function, except that it would be the left half of the parabola. For each function in Exercises \(117-122\), restrict the domain so that the function is one-to-one and the range is not changed. You may wish to use a graph to help decide. Answers may vary. (GRAPHS CANNOT COPY) $$f(x)=-x^{2}+4$$

The given function \(f\) is one-to-one. Find \(f^{-1}(x)\). $$f(x)=\frac{x}{4+3 x}$$

During the 100 -meter dash, the elapsed time \(T\) for a sprinter to reach a speed of \(x\) meters per second is given by the following function. $$T(x)=-1.2 \ln \left(1-\frac{x}{11}\right)$$ (a) How much time had elapsed when the sprinter was running 0 meters per second? Interpret your answer. (b) At the end of the race, the sprinter was moving at 10.998 meters per second. What was the sprinter's time for this 100 -meter dash? (c) Find \(T^{-1}(x)\) and interpret its meaning.

For each function that is one-to-one, write an equation for the inverse function of \(y=f(x)\) in the form \(y=f^{-1}(x),\) and then graph \(f\) and \(f^{-1}\) on the same axes. Give the domain and range of \(f\) and \(f^{-1} .\) If the function is not one-to-one, say so. $$y=4 x-5$$
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