Chapter 5: Problem 98
Graph by hand the equation of the circle or the parabola with a horizontal axis. $$x^{2}+y^{2}=25$$
Short Answer
Expert verified
The circle has a center at (0,0) and a radius of 5.
Step by step solution
01
Identify the Shape
The given equation is \(x^2 + y^2 = 25\). This is the standard form of a circle equation, \(x^2 + y^2 = r^2\), where \(r\) is the radius. Hence, this equation represents a circle.
02
Determine the Circle's Properties
From the equation \(x^2 + y^2 = 25\), we see that \(r^2 = 25\). Therefore, the radius \(r\) of the circle is \(\sqrt{25} = 5\). The center of the circle is at the origin \((0, 0)\).
03
Drawing the Circle on a Graph
To graph the circle, start by plotting the center at the origin \((0,0)\). Then, using the radius of 5, mark points 5 units away from the center in the positive and negative directions of both the x-axis and y-axis, at \((5,0), (-5,0), (0,5), (0,-5)\). Connect these points with a smooth curve to form the circle.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equation of a Circle
The equation of a circle in standard form is written as \(x^2 + y^2 = r^2\). This general equation describes a circle centered at the origin \((0, 0)\) with "r" being the radius of the circle. For instance, consider the equation \(x^2 + y^2 = 25\). Here, you can immediately recognize it as a circle because it fits the standard form \(x^2 + y^2 = r^2\). The value 25 represents \(r^2\), which is the squared radius of the circle. To find the radius \(r\), simply determine the square root of 25, giving \(r = \sqrt{25} = 5\). Thus, this circle has a radius of 5.
The equation of a circle can also be expressed in another form when not centered at the origin: \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle. In such a case, move the origin to this point \((h, k)\) to properly graph the circle. But for our case with the origin as the center, the simpler form suffices.
The equation of a circle can also be expressed in another form when not centered at the origin: \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle. In such a case, move the origin to this point \((h, k)\) to properly graph the circle. But for our case with the origin as the center, the simpler form suffices.
Graphing Techniques
Graphing a circle by hand might seem challenging, but it becomes simple when approached step by step. Start by identifying the center of the circle, which, when the equation is \(x^2 + y^2 = r^2\), is at point \((0, 0)\).
Follow these steps to graph the circle:
Follow these steps to graph the circle:
- First, plot the center point. For our example, this is the origin \((0, 0)\).
- Next, calculate the radius. As previously discussed, when given \(x^2 + y^2 = 25\), the radius is 5.
- Now use this radius to mark distinctive points. Measure 5 units in all four cardinal directions starting from the center: to the right \((5, 0)\), to the left \((-5, 0)\), upwards \((0, 5)\), and downwards \((0, -5)\).
- Finally, connect these points using a smooth curve, making sure the shape remains even and circular.
Radius and Center of a Circle
Understanding the radius and the center is key to mastering circles in coordinate geometry.
- The Radius: The radius of a circle is the distance from its center to any point on the circle. In our example equation \(x^2 + y^2 = 25\), we determined the radius to be 5 units by calculating the square root of 25. This consistent measurement ensures the circle maintains its shape, as every point on the circumference is equidistant from the center.
- The Center: For the equation \(x^2 + y^2 = r^2\), the center is naturally at \((0, 0)\). When expressed in an alternative form such as \((x-h)^2 + (y-k)^2 = r^2\), the center shifts to the point \((h, k)\). Knowing the center helps in orienting the circle correctly on the graph.