/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Evaluate each expression. $$(-... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Evaluate each expression. $$(-1000)^{2 / 3}$$

Short Answer

Expert verified
The expression \((-1000)^{2/3}\) evaluates to 100.

Step by step solution

01

Understand the Expression

The given expression is \((-1000)^{2/3}\). This means we need to take the cube root of -1000 first, then square the result.
02

Evaluate the Cube Root

The expression inside the exponent indicates that we first find the cube root of the number. The cube root of -1000 is \(-10\), because \((-10) \times (-10) \times (-10) = -1000\).
03

Square the Result

Next, we take the result from Step 2 and square it. So we calculate \((-10)^2\). This equals \(100\) because multiplying \(-10\) by itself gives a positive value.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cube Roots
When working with cube roots, you're essentially trying to find a number that, when multiplied by itself three times, gives you the original value. In mathematical terms, if you have a number \(a\), the cube root of \(a\) is a number \(b\) such that \(b \times b \times b = a\).

For example, in the expression \((-1000)^{2/3}\), the cube root of \(-1000\) is \(-10\) because \(-10 \times -10 \times -10 = -1000\). Notice that the cube root of a negative number is still negative, as you need three identical factors to result in a negative product.

To find a cube root easily:
  • Break down the original number into prime factors.
  • Re-group the factors into sets of three.
  • Extract one factor from each group, allowing you to simplify the cube root.
Exponentiation
Exponentiation is a math operation that involves raising a number, called the base, to the power of an exponent to express how many times the base is multiplied by itself. It's written as \(b^n\), where \(b\) is the base and \(n\) is the exponent.

For example, in the expression \((-10)^2\), \(-10\) serves as the base raised to the power of 2. This means you multiply \(-10\) by itself:
  • \(-10 \times -10 = 100\)
This result is positive because multiplying two negative numbers yields a positive product. Exponentiation is crucial in simplifying expressions with rational exponents, such as when solving \((-1000)^{2/3}\).

Understanding exponentiation helps in handling complex problems as it allows for the evaluation of non-integer xponent values, breaking them into understandable steps.
Negative Bases
Working with negative bases in mathematics can be tricky, especially under exponentiation. The key is to understand how the sign behaves under different scenarios.

When you raise a negative base to an integer exponent:
  • Even exponent: The result is positive, because a negative number times itself an even number of times (such as in \((-10)^2\)) results in a positive number.
  • Odd exponent: The result remains negative, because multiplying a negative number an odd number of times retains the negative sign.

These rules help when dealing with rational exponents, like in \((-1000)^{2/3}\). First, the cube root makes the base manageable, and then squaring the negative result makes it positive. Understanding how exponent rules apply to negative bases simplifies problem-solving with expressions involving rational exponents.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Rational function has an oblique asymptote. Determine the equation of this asymptote. Then use a graphing calculator to graph both the function and the asymptote in the window indicated. $$f(x)=\frac{x^{2}+2 x}{1-2 x} ;[-6.6,6.6] \text { by }[-4.1,4.1]$$

Find all complex solutions for each equation by hand. $$\frac{1}{x+3}+\frac{4}{x+5}=\frac{2}{x^{2}+8 x+15}$$

\(f(x)=\frac{x^{5}+x^{4}+x^{2}+1}{x^{4}+1}\) becomes \(f(x)=x+1+\frac{x^{2}-x}{x^{4}+1}\) after the numerator is divided by the denominator. (a) What is the equation of the oblique asymptote of the graph of the function? (b) For what \(x\) -value(s) does the graph of the function intersect its asymptote? (c) As \(x \rightarrow \infty,\) does the graph of the function approach its asymptote from above or below?

Solve each problem involving rate of work. A couple is laying a tile floor. Working alone, one can do the job in 20 hours. If the two of them work together, they can complete the job in 12 hours. How long would it take the other one to lay the floor working alone?

CONCEPT CHECK In some cases, it is possible to solve a rational inequality simply by deciding what sign the numerator and the denominator must have and then using the rules for quotients of positive and negative numbers to determine the solution set. For example, consider the rational inequality $$ \frac{1}{x^{2}+1}>0 $$ The numerator of the rational expression, 1, is positive, and the denominator, \(x^{2}+1,\) must always be positive because it is the sum of a nonnegative number, \(x^{2},\) and a positive number, 1. Therefore, the rational expression is the quotient of two positive numbers, which is positive. Because the inequality requires that the rational expression be greater than \(0,\) and this will always be true, the solution set is \((-\infty, \infty)\) Use similar reasoning to solve each inequality. $$\frac{(x-1)^{2}}{x^{2}+4}>0$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.