/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 Sketch a graph of rational funct... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sketch a graph of rational function. Your graph should include all asymptotes. Do not use a calculator. $$f(x)=\frac{-4}{3 x+9}$$

Short Answer

Expert verified
Vertical asymptote at \(x = -3\); horizontal asymptote at \(y = 0\); y-intercept at \((0, -\frac{4}{9})\). Sketch includes all these parts.

Step by step solution

01

Identify the Vertical Asymptote

The vertical asymptote occurs where the denominator of the rational function is zero. For the function \( f(x) = \frac{-4}{3x + 9} \), set the denominator equal to zero to find the vertical asymptote: \[ 3x + 9 = 0 \]Solve for \( x \):\[ 3x = -9 \]Divide by 3:\[ x = -3 \]Therefore, there is a vertical asymptote at \( x = -3 \).
02

Determine the Horizontal Asymptote

The horizontal asymptote can be determined by the degrees of the polynomial in the numerator and the denominator. Since the degree of the numerator is 0 and the degree of the denominator is 1, the horizontal asymptote is at \( y = 0 \), because \(-4\) is constant and does not depend on \( x \), it approaches 0 as \( x \) increases or decreases.
03

Identify Intercepts

To find the y-intercept, substitute \( x = 0 \) into the function: \[ f(0) = \frac{-4}{3(0) + 9} = \frac{-4}{9} \]So, the y-intercept is \( (0, -\frac{4}{9}) \).There are no x-intercepts since the numerator, \(-4\), is not zero.
04

Sketch the Graph

Start by drawing the vertical asymptote as a dashed line at \( x = -3 \).Then draw the horizontal asymptote as a dashed line at \( y = 0 \).Plot the y-intercept point \( (0, -\frac{4}{9}) \) on the graph.The function \( f(x) \) will approach the asymptotes but never touch or cross them.Draw the curve approaching the asymptotes, making sure that as \( x \to \pm \infty \), \( y \to 0 \), and around the asymptote at \( x = -3 \), the curve should go to \( -\infty \) and \( +\infty \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Asymptote
In mathematics, a vertical asymptote of a rational function is a vertical line that the graph of the function approaches but never actually touches. Imagine walking on a path that becomes almost unreachable as you move farther away but never truly disappears. In the rational function \( f(x) = \frac{-4}{3x + 9} \), to find the vertical asymptote, we identify where the denominator becomes zero. This is crucial because division by zero is undefined in mathematics.
The formula requires solving the equation \( 3x + 9 = 0 \). By isolating \( x \), we solve
  • Subtract 9 from both sides: \( 3x = -9 \)
  • Divide by 3 on both sides: \( x = -3 \)
Thus, the vertical line \( x = -3 \) is our vertical asymptote. This line indicates where the graph will shoot upwards to infinity or drop down to negative infinity depending on the direction you're approaching from.
Horizontal Asymptote
The horizontal asymptote in a rational function indicates the behavior of the graph as it extends indefinitely in the x-direction. For \( f(x) = \frac{-4}{3x + 9} \), we decide the horizontal asymptote by analyzing the function's numerator and denominator degrees. The degree of a polynomial is the highest exponent of the variable in the expression.
  • Here, the degree of the numerator is 0 (constant \(-4\)).
  • The degree of the denominator is 1 (term \( 3x \)).
If the degree of the numerator is less than the denominator, the horizontal asymptote is the x-axis: \( y = 0 \). As \( x \) becomes very large or very small in either direction, \( f(x) \) approaches zero, reflecting that the function becomes nearly flat and hugs the x-axis over long stretches. This doesn't mean it will touch or cross the x-axis when displayed graphically. It's like aiming for the horizon; you get closer but never reach it.
Intercepts
Intercepts are points where the graph touches the x-axis or y-axis. These are like intersections of roads where two paths meet and are critical in graph plotting because they provide anchor points.

Y-Intercept:

The y-intercept occurs where the graph crosses the y-axis, which is when \( x = 0 \). To find it for our function \( f(x) = \frac{-4}{3x + 9} \), substitute \( x = 0 \) into the function:
\( f(0) = \frac{-4}{9} \)
Thus, the y-intercept is \( (0, -\frac{4}{9}) \), a vital point showing where the graph intersects the y-axis.

X-Intercept:

The x-intercepts occur where the function equals zero, or where the graph crosses the x-axis. It's where the numerator is zero. In our example, \(-4\) is constant and never equals zero; therefore, this function has no x-intercepts.
These intercept points help determine the shape of the graph and ensure that it's plotted accurately. The y-intercept gives us a starting tick mark along the y-axis, while potential x-intercepts (if existent) help define where the graph would meet the ground if it extended that way.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve each problem involving rate of work. One person can groom a dog in 6 hours, but it takes his business partner only 4 hours to groom the same dog. How long will it take them to groom the dog if they work together?

Assume that the constant of variation is positive. Suppose \(y\) is directly proportional to the second power of x. If \(x\) is halved, what happens to \(y ?\)

Time Spent in Line Suppose the average number of vehicles arriving at the main gate of an amusement park is equal to 10 per minute, while the average number of vehicles being admitted through the gate per minute is equal to \(x .\) Then the average waiting time in minutes for each vehicle at the gate is given by $$ f(x)=\frac{x-5}{x^{2}-10 x} $$ where \(x>10\). (Source: Mannering, F. and W. Kilareski, Principles of Highway Engineering and Traffic Analysis, 2d. ed., John Wiley and Sons.) (a) Estimate the admittance rate \(x\) that results in an average wait of 15 seconds. (b) If one attendant can serve 5 vehicles per minute, how many attendants are needed to keep the average wait to 15 seconds or less?

Solve the equation in part (a) graphically, expressing solutions to the nearest hundredth. Then use the graph to solve the associated inequalities in parts (b) and (c), expressing endpoints to the nearest hundredth. (a) \(\frac{\sqrt[3]{7} x^{3}-1}{x^{2}+2}=0\) (b) \(\frac{\sqrt[3]{7} x^{3}-1}{x^{2}+2}>0\) (c) \(\frac{\sqrt[3]{7} x^{3}-1}{x^{2}+2}<0\)

Solve each rational inequality by hand. $$\frac{3-2 x}{1+x}<0$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.