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Sketch a graph of rational function. Your graph should include all asymptotes. Do not use a calculator. $$f(x)=\frac{3 x^{2}+3 x-6}{x^{2}-x-12}$$

Short Answer

Expert verified
Vertical asymptotes at \(x = 4\) and \(x = -3\); horizontal asymptote at \(y = 3\).

Step by step solution

01

Factor the Numerator and Denominator

First, let's factor the polynomial functions in the numerator and denominator of the function. Factor the numerator: \(3x^2 + 3x - 6 = 3(x^2 + x - 2)\). Let's factor further: \(x^2 + x - 2 = (x - 1)(x + 2)\). So, the numerator is factored as: \(3(x - 1)(x + 2)\). Now, factor the denominator: \(x^2 - x - 12 = (x - 4)(x + 3)\).
02

Identify the Vertical Asymptotes

Vertical asymptotes occur where the denominator is zero, provided that the numerator isn’t zero at these points. From the factored denominator \((x - 4)(x + 3) = 0\), the vertical asymptotes are at \(x = 4\) and \(x = -3\).
03

Determine Holes in the Graph

Check if any cancelling occurs between the numerator and the denominator. Since no terms are common between the factored numerator and denominator, there are no holes in this graph.
04

Find the Horizontal Asymptote

To determine the horizontal asymptote, compare the degrees of the polynomials in the numerator and denominator. Both have degree 2. So, the horizontal asymptote is at the ratio of their leading coefficients: \(\frac{3}{1} = 3\), hence the horizontal asymptote is \(y = 3\).
05

Sketch the Graph

Using the vertical asymptotes \(x = 4\) and \(x = -3\), and the horizontal asymptote \(y = 3\), plot the function approaching these lines. Indicate that the graph never crosses these asymptotes, but the horizontal asymptote may be crossed depending on behavior as \(x\) approaches infinity. There are no removable discontinuities (holes) in this graph.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Asymptotes
A rational function may have vertical asymptotes, which are crucial for understanding its graph's behavior. Vertical asymptotes occur where the denominator of the rational function equals zero, but the numerator does not, making the function undefined at that particular value of \( x \).

For the function \( f(x) = \frac{3x^2 + 3x - 6}{x^2 - x - 12} \), the vertical asymptotes are found by setting the denominator \( (x^2 - x - 12) \) equal to zero and solving for \( x \). We factored it as \( (x - 4)(x + 3) = 0 \). This leads to two vertical asymptotes at \( x = 4 \) and \( x = -3 \).

  • When approaching a vertical asymptote from either direction, the function tends to \( \pm \infty \), which means it rises or falls abruptly.
  • The graph will have a break at these points, giving it a distinctive look near each asymptote.
Understanding vertical asymptotes is vital for accurately sketching the shape of a rational function's graph.
Horizontal Asymptotes
Horizontal asymptotes differ from vertical asymptotes since they tell us about the behavior of the graph as \( x \) approaches positive or negative infinity. These lines suggest how the function behaves at extreme values of \( x \).

To find the horizontal asymptote for the function \( f(x) = \frac{3x^2 + 3x - 6}{x^2 - x - 12} \), we compare the degrees of the polynomials in both the numerator and denominator. Since both polynomials are of degree 2, the horizontal asymptote can be determined by dividing the leading coefficients: \( \frac{3}{1} = 3 \). This means the horizontal asymptote is \( y = 3 \).

  • Horizontal asymptotes show the end behavior of a graph.
  • The graph may cross the horizontal asymptote within the graph's window, but as it stretches towards infinity, it approaches \( y = 3 \).
Having this information helps in sketching the graph and understanding where the function stabilizes as its input grows large.
Polynomial Functions
Polynomial functions are fundamental mathematical components used in constructing rational functions. In this context, they form the numerator and denominator of our given rational function.

For \( f(x) = \frac{3x^2 + 3x - 6}{x^2 - x - 12} \), both the numerator and the denominator are polynomial expressions. Here, the numerator is \( 3x^2 + 3x - 6 \), which we can factor into \( 3(x - 1)(x + 2) \). Similarly, the denominator \( x^2 - x - 12 \) factors into \( (x - 4)(x + 3) \).

  • Polynomial functions in the numerator and denominator provide critical points, zeros, and intercepts for the rational function.
  • The degree of these polynomials is instrumental in determining asymptotes, particularly horizontal ones.
Mastery of polynomial functions is the cornerstone of analyzing and understanding more complex rational expressions.
Graph Sketching
Sketching the graph of a rational function involves combining all the ideas of asymptotes and polynomial behavior. It helps visualize the function's overall behavior and critical points.

When sketching \( f(x) = \frac{3x^2 + 3x - 6}{x^2 - x - 12} \), we rely on the vertical asymptotes at \( x = 4 \) and \( x = -3 \), and the horizontal asymptote at \( y = 3 \). The lack of cancelation between numerator and denominator terms indicates no removable discontinuities are present, meaning there are no holes to plot.

  • The graph should start by sketching the asymptotes: draw dotted lines for vertical and horizontal asymptotes.
  • Next, plot key points such as intercepts, if easily identifiable.
  • Draw the curves, ensuring they approach the asymptotes correctly.
Sketching graphs by hand encourages a deeper understanding of function dynamics, symmetry, and continuity, giving you practical insight beyond simple calculations.

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Most popular questions from this chapter

Solve each rational inequality by hand. $$\frac{(x+1)^{2}}{x-2} \leq 0$$

CONCEPT CHECK In some cases, it is possible to solve a rational inequality simply by deciding what sign the numerator and the denominator must have and then using the rules for quotients of positive and negative numbers to determine the solution set. For example, consider the rational inequality $$ \frac{1}{x^{2}+1}>0 $$ The numerator of the rational expression, 1, is positive, and the denominator, \(x^{2}+1,\) must always be positive because it is the sum of a nonnegative number, \(x^{2},\) and a positive number, 1. Therefore, the rational expression is the quotient of two positive numbers, which is positive. Because the inequality requires that the rational expression be greater than \(0,\) and this will always be true, the solution set is \((-\infty, \infty)\) Use similar reasoning to solve each inequality. $$\frac{(x-1)^{2}}{x^{2}+4} \leq 0$$

Train Curves When curves are designed for trains, sometimes the outer rail is elevated or banked so that a locomotive can safely negotiate the curve at a higher speed. Suppose a circular curve is being designed for a speed of 60 mph. The rational function \(f(x)=\frac{2540}{x}\) computes the elevation \(y\) in inches of the outer track for a curve with a radius of \(x\) feet, where \(y=f(x) .\) (Image can't copy) (a) Evaluate \(f(400)\) and interpret its meaning. (b) Graph \(f\) in the window \([0,600]\) by \([0,50] .\) Discuss how the elevation of the outer rail changes with the radius \(x\) (c) Interpret the horizontal asymptote. (d) What radius is associated with an elevation of 12.7 inches?

Solve each equation and inequality. (These types of equations and inequalities occur in calculus.) (a) \(\frac{\left(x^{2}-1\right)(3)-(3 x-1)(2 x)}{\left(x^{2}-1\right)^{2}}=0\) (b) \(\frac{\left(x^{2}-1\right)(3)-(3 x-1)(2 x)}{\left(x^{2}-1\right)^{2}} \leq 0\)

Consider the rational function $$f(x)=\frac{x^{3}-4 x^{2}+x+6}{x^{2}+x-2}$$ Divide the numerator by the denominator and use the method of Example 3 to determine the equation of the oblique asymptote. Then determine the coordinates of the point where the graph of \(f\) intersects its oblique asymptote. Use a calculator to support your answer.

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