Chapter 5: Problem 19
Solve each equation by hand. Do not use a calculator. $$\sqrt[4]{x-2}+4=6$$
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Chapter 5: Problem 19
Solve each equation by hand. Do not use a calculator. $$\sqrt[4]{x-2}+4=6$$
These are the key concepts you need to understand to accurately answer the question.
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Recycling A cost-benefit function \(C\) computes the cost in millions of dollars of implementing a city recycling project when \(x\) percent of the citizens participate, where $$ C(x)=\frac{1.2 x}{100-x} $$ (a) Graph \(C\) in the window \([0,100]\) by \([0,10]\). Interpret the graph as \(x\) approaches 100 (b) If \(75 \%\) participation is expected, determine the cost for the city. (c) The city plans to spend \(\$ 5\) million on this recycling project. Estimate graphically the percentage of participation that they are expecting. (d) Solve part (c) analytically.
CONCEPT CHECK In some cases, it is possible to solve a rational inequality simply by deciding what sign the numerator and the denominator must have and then using the rules for quotients of positive and negative numbers to determine the solution set. For example, consider the rational inequality $$ \frac{1}{x^{2}+1}>0 $$ The numerator of the rational expression, 1, is positive, and the denominator, \(x^{2}+1,\) must always be positive because it is the sum of a nonnegative number, \(x^{2},\) and a positive number, 1. Therefore, the rational expression is the quotient of two positive numbers, which is positive. Because the inequality requires that the rational expression be greater than \(0,\) and this will always be true, the solution set is \((-\infty, \infty)\) Use similar reasoning to solve each inequality. $$\frac{-5}{x^{2}+2}>0$$
Solve each rational inequality by hand. $$\frac{5-x}{x^{2}-x-2}<0$$
Solve each rational inequality by hand. $$\frac{(x+1)^{2}}{x-2} \leq 0$$
Solve each problem. Hubble Telescope The brightness or intensity of starlight varies inversely with the square of its distance from Earth. The Hubble Telescope can see stars whose intensities are \(\frac{1}{50}\) of the faintest star now seen by ground. based telescopes. Determine how much farther the Hubble Telescope can see into space than ground-based telescopes.
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