Chapter 4: Problem 74
Factor \(P(x)\) into linear factors given that \(k\) is a zero of \(P\). $$P(x)=8 x^{3}+50 x^{2}+47 x-15 ; \quad k=-5$$
Short Answer
Expert verified
Factorization is \((x + 5)(x - \frac{1}{2})(x + 1.5)\).
Step by step solution
01
Understand the problem
We need to factor the cubic polynomial \(P(x) = 8x^3 + 50x^2 + 47x - 15\) into linear factors, knowing that \(x = -5\) is one of its zeros. This means \(x + 5\) is a factor of \(P(x)\).
02
Use Synthetic Division
First, divide \(P(x)\) by \(x + 5\) using synthetic division. This will help us find the quotient, which is a quadratic polynomial that, together with \(x + 5\), forms the complete factorization of \(P(x)\).
03
Set up Synthetic Division
Write the coefficients of \(P(x)\), which are 8, 50, 47, and -15. Using synthetic division, write -5 on the left and draw a line. Follow the synthetic division process, adding and multiplying as appropriate.
04
Perform Synthetic Division
Start the synthetic division. Bring down 8, then multiply it by -5 to get -40. Add -40 to 50 to get 10. Multiply 10 by -5 to get -50, then add -50 to 47 to get -3. Multiply -3 by -5 to get 15, and finally, add 15 to -15 to get 0. This confirms \(x + 5\) is a factor of \(P(x)\), as the remainder is 0. The result is a new polynomial: \(8x^2 + 10x - 3\).
05
Factor the Quadratic Polynomial
Next, factor the quadratic polynomial \(8x^2 + 10x - 3\). Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) where \(a = 8\), \(b = 10\), and \(c = -3\). Calculate the discriminant \(b^2 - 4ac = 100 + 96 = 196\).
06
Solve for the Roots Using the Quadratic Formula
Solve \(x = \frac{-10 \pm \sqrt{196}}{16}\). \(\sqrt{196} = 14\), so the roots are \(x = \frac{-10 + 14}{16} = \frac{1}{2}\) and \(x = \frac{-10 - 14}{16} = -1.5\). Thus, the polynomial factors are \(x - \frac{1}{2}\) and \(x + 1.5\).
07
Write Final Factorization
Combine all the linear factors to express \(P(x)\) as \(P(x) = (x + 5)(x - \frac{1}{2})(x + 1.5)\). Since these adjustments maintain equivalence, this is the factorization of the original polynomial.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Synthetic Division
Synthetic Division is a simplified method used to divide polynomials. It is especially handy when dividing by a linear binomial of the form \(x - c\). In this method, you only work with the coefficients of the polynomial, making the process less cumbersome than long division. Here's how it works:
- Write down the coefficients of the polynomial you want to divide, in this case: 8, 50, 47, and -15.
- On the left side, write the zero you're using, here it's -5 because \(x + 5\) is a factor, so the opposite sign is used.
- Draw a horizontal line below the coefficients and another parallel line to the side of the zero.
Quadratic Formula
The Quadratic Formula is a reliable method for finding the roots of a quadratic equation of the form \(ax^2 + bx + c = 0\). This formula is your go-to tool when factoring a quadratic is not straightforward. The formula is:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Here's how it applies to our example:
- Identify coefficients: \(a = 8\), \(b = 10\), \(c = -3\).
- Calculate the discriminant: \(b^2 - 4ac = 100 + 96 = 196\).
- Take the square root: \(\sqrt{196} = 14\).
- Use the formula to find roots: \(x = \frac{-10 \pm 14}{16}\).
Cubic Polynomial
A Cubic Polynomial is a polynomial of degree three, typically in the form \(ax^3 + bx^2 + cx + d\). The highest exponent, which is three, dictates the shape of the graph and can have up to three real roots. In our example, the cubic polynomial given is:\(8x^3 + 50x^2 + 47x - 15\).Cubic polynomials can be challenging to tackle, especially when factoring. Finding one root (in our case, \(x = -5\)) simplifies the process significantly, because you can use it to perform synthetic division and reduce the polynomial to a quadratic one, which is much easier to manage.
Zeros of Polynomial
Zeros of a polynomial are the values of \(x\) that make the polynomial equal to zero. In simpler terms, they are the solutions to the polynomial equation \(P(x) = 0\). These zeros are crucial because they correspond to the x-intercepts of the polynomial graph. In our exercise, we are initially given one zero \(k = -5\). This information directly helps us identify one of the factors of the polynomial as \(x + 5\). Once one zero is known, the remaining zeros (if any) can be found by factoring the reduced polynomial. After using synthetic division with \(x + 5\) and applying the quadratic formula, we determined the complete set of zeros:\[-5, \frac{1}{2}, \text{and } -1.5.\]Understanding zeros is vital for polynomial factorization, as they provide a complete picture of how the polynomial behaves and are essential for creating a fully factored form.