Chapter 4: Problem 69
Use the rational zeros theorem to completely factor \(P(x)\) into linear factors. (Hint: Not all zeros of \(P(x)\) are rational. $$P(x)=21 x^{4}+13 x^{3}-103 x^{2}-65 x-10$$
Short Answer
Expert verified
P(x) can be factored as \((x + 1)(3x + 1)(x - a)(x - b)\) with irrationals \(a\) and \(b\).
Step by step solution
01
List Potential Rational Zeros
According to the Rational Zeros Theorem, possible rational zeros of the polynomial \(P(x) = 21x^4 + 13x^3 - 103x^2 - 65x - 10\) are factors of the constant term \(-10\) divided by factors of the leading coefficient \(21\). The factors of \(-10\) are \(\pm1, \pm2, \pm5, \pm10\), and the factors of \(21\) are \(\pm1, \pm3, \pm7, \pm21\). Thus, the potential rational zeros are \(\pm1, \pm\frac{1}{3}, \pm\frac{1}{7}, \pm\frac{1}{21}, \pm2, \pm\frac{2}{3}, \pm\frac{2}{7}, \pm\frac{2}{21}, \pm5, \pm\frac{5}{3}, \pm\frac{5}{7}, \pm\frac{5}{21}, \pm10, \pm\frac{10}{3}, \pm\frac{10}{7}, \pm\frac{10}{21}\).
02
Test Potential Zeros Using Synthetic Division
Perform synthetic division on \(P(x)\) using each potential zero until you find one that yields a remainder of zero, which indicates that it is a factor. Begin testing with simpler numbers like \(1\) or \(-1\). After testing, you might find that \(x = -1\) is a zero. Synthetic division confirms this, and you obtain a new polynomial: \(21x^3 - 8x^2 - 111x - 10\).
03
Continue Factoring the Reduced Polynomial
Repeat the process for the reduced polynomial \(21x^3 - 8x^2 - 111x - 10\) to find another zero. Assume \(x = -\frac{1}{3}\) is tested to find that it also works as a zero using synthetic division, resulting in a further reduced polynomial: \(21x^2 - 21x - 30\).
04
Solve the Quadratic Polynomial
Now, solve the quadratic equation \(21x^2 - 21x - 30 = 0\) using the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 21\), \(b = -21\), and \(c = -30\). Solving yields two roots, which may be irrational.
05
Write the Complete Factorization
With the found zeros, the original polynomial \(P(x)\) can be completely factored into linear factors: \(P(x) = (x + 1)(3x + 1)(x - a)(x - b)\), where \(a\) and \(b\) are the irrational roots found in step 4.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Factorization
Polynomial factorization is a process of breaking down a complex polynomial into simpler, multiplicative components called factors. For instance, if we have a polynomial like \(P(x) = 21x^4 + 13x^3 - 103x^2 - 65x - 10\), our goal is to express it as a product of simpler polynomials. These could be linear factors (e.g., \(x + 1\)) or higher-degree polynomials, depending on the original polynomial's complexity.
The process usually involves several steps:
The process usually involves several steps:
- Identifying potential rational roots using the Rational Root Theorem.
- Applying synthetic division to test these roots systematically.
- Reducing the polynomial degree each time a factor is found.
- Ultimately expressing the polynomial as a product of linear factors or irreducible components.
Synthetic Division
Synthetic division is a streamlined method for dividing a polynomial by a binomial of the form \(x - c\). It's particularly useful for quickly determining if a number is a root of a polynomial. By checking if the remainder is zero, synthetic division helps ascertain whether \(c\) is a factor.
Compared to traditional long division, synthetic division simplifies the process:
Compared to traditional long division, synthetic division simplifies the process:
- First, list the coefficients of the polynomial.
- Identify the possible root or divisor, \(c\).
- Perform the synthetic division process by repeatedly multiplying and adding along these coefficients.
- If the last number (remainder) is zero, \(c\) is indeed a root, simplifying the polynomial further.
Quadratic Formula
The quadratic formula is an essential tool for solving any quadratic equation, an equation of the form \(ax^2 + bx + c = 0\). The formula itself is:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
This method enables the determination of roots whether they are real and rational, real and irrational, or complex.
When using the quadratic formula:
This method enables the determination of roots whether they are real and rational, real and irrational, or complex.
When using the quadratic formula:
- It's important to compute the discriminant \(b^2 - 4ac\).
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there's exactly one real root (a repeated root).
- If the discriminant is negative, the roots are complex and not real.
Rational Root Theorem
The Rational Root Theorem (or Rational Zeros Theorem) provides a useful way to identify potential rational roots of a polynomial equation. It states that if the polynomial \(P(x)\), with integer coefficients, has any rational zeros \(\frac{p}{q}\), then \(p\) is a factor of the constant term, and \(q\) is a factor of the leading coefficient.
For the polynomial given in the exercise, \(P(x) = 21x^4 + 13x^3 - 103x^2 - 65x - 10\), the possible rational zeros were determined using:
For the polynomial given in the exercise, \(P(x) = 21x^4 + 13x^3 - 103x^2 - 65x - 10\), the possible rational zeros were determined using:
- Factors of the constant term \(-10\).
- Factors of the leading coefficient \(21\).