Chapter 3: Problem 37
Solve each equation. For equations with real solutions, support your answers graphically. $$x^{2}-2 x-4=0$$
Short Answer
Expert verified
The solutions are \( x = 1 + \sqrt{5} \) and \( x = 1 - \sqrt{5} \).
Step by step solution
01
Identify the Type of Equation
The given equation is a quadratic equation of the form \( ax^2 + bx + c = 0 \). In this case, \( a = 1 \), \( b = -2 \), and \( c = -4 \).
02
Apply the Quadratic Formula
To find the solutions, we use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Substituting the given values, we have:\[ x = \frac{-(-2) \pm \sqrt{(-2)^2 - 4 \cdot 1 \cdot (-4)}}{2 \cdot 1} \]Which simplifies to:\[ x = \frac{2 \pm \sqrt{4 + 16}}{2} \] \[ x = \frac{2 \pm \sqrt{20}}{2} \]
03
Simplify the Solutions
Further simplify the expression:\[ x = \frac{2 \pm \sqrt{4 \cdot 5}}{2} \]\[ x = \frac{2 \pm 2\sqrt{5}}{2} \]Simplifying gives:\[ x = 1 \pm \sqrt{5} \] Therefore, the solutions are \( x = 1 + \sqrt{5} \) and \( x = 1 - \sqrt{5} \).
04
Graphical Representation
To graphically represent these solutions, graph the function \( f(x) = x^2 - 2x - 4 \). The x-intercepts of this graph, where the curve crosses the x-axis, are the solutions \( x = 1 + \sqrt{5} \) and \( x = 1 - \sqrt{5} \). These approximate to approximately 3.24 and -1.24 respectively.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to find the solutions of quadratic equations of the form \( ax^2 + bx + c = 0 \). This formula is versatile and universally applicable to any quadratic equation, making it an essential part of solving these expressions. The formula is given by:
To use the quadratic formula, you'll need to identify the values of \( a \), \( b \), and \( c \) from your equation. In our example, these values are: \( a = 1 \), \( b = -2 \), and \( c = -4 \). Substituting these into the formula will yield the solution.
Understanding each component is crucial:
- \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
To use the quadratic formula, you'll need to identify the values of \( a \), \( b \), and \( c \) from your equation. In our example, these values are: \( a = 1 \), \( b = -2 \), and \( c = -4 \). Substituting these into the formula will yield the solution.
Understanding each component is crucial:
- \( b^2 - 4ac \) is known as the discriminant. It determines the nature of the roots (real or complex).
- The \( \pm \) symbol indicates that there are potentially two solutions: one by addition, the other by subtraction.
Graphical Solutions
Graphical solutions provide a visual way to understand the roots of an equation, specifically where they intersect the x-axis on a graph. For the quadratic equation \( x^2 - 2x - 4 = 0 \), plotting the corresponding function \( f(x) = x^2 - 2x - 4 \) gives us a parabola. This curve showcases the solutions or 'roots' of the equation, visually confirming what we've computed algebraically.
When graphed, the x-intercepts are the points where the function equals zero—this results from substituting the solutions back into the equation. Observing these intercepts can be informative:
When graphed, the x-intercepts are the points where the function equals zero—this results from substituting the solutions back into the equation. Observing these intercepts can be informative:
- The parabola's direction—whether it opens upwards or downwards—can help verify that the solutions are correct.
- The x-intercepts here match the solutions from the quadratic formula, which is \( x = 1 + \sqrt{5} \) and \( x = 1 - \sqrt{5} \).
Roots of Equations
The roots of a quadratic equation are essentially the solutions to the equation \( ax^2 + bx + c = 0 \). They represent the values of \( x \) where the equation holds true, meaning the output is zero. Calculating these roots is a fundamental skill in algebra.
These roots can be real or complex and are determined by the discriminant \( b^2 - 4ac \):
These roots can be real or complex and are determined by the discriminant \( b^2 - 4ac \):
- If the discriminant is positive, the roots are real and distinct.
- If the discriminant is zero, the equation has one real, repeated root.
- If the discriminant is negative, the roots are complex or imaginary, which means they do not intersect the x-axis on a graph.