Chapter 3: Problem 32
For quadratic function, (a) use the vertex formula to find the coordinates of the vertex and (b) graph the function. Do not use a calculator. $$P(x)=-2 x^{2}-6 x-5$$
Short Answer
Expert verified
The vertex is \(\left(\frac{3}{2}, -\frac{37}{2}\right)\). The graph is a downward-opening parabola.
Step by step solution
01
Identify the coefficients of the quadratic function
The given quadratic function is \(P(x) = -2x^2 - 6x - 5\). Identify the coefficients \(a\), \(b\), and \(c\) from the standard form of a quadratic function \(ax^2 + bx + c\).Here, \(a = -2\), \(b = -6\), and \(c = -5\).
02
Use the vertex formula to find x-coordinate
The x-coordinate of the vertex of a quadratic function \(ax^2 + bx + c\) is given by the formula \(x = -\frac{b}{2a}\).Substitute \(b = -6\) and \(a = -2\) into the formula:\[x = -\frac{-6}{2 \times -2} = -\frac{-6}{-4} = \frac{6}{4} = \frac{3}{2}.\]
03
Find y-coordinate of the vertex
Substitute \(x = \frac{3}{2}\) back into the function \(P(x) = -2x^2 - 6x - 5\) to find \(P(\frac{3}{2})\) which gives the y-coordinate of the vertex.Calculate \[-2\left(\frac{3}{2}\right)^2 - 6\left(\frac{3}{2}\right) - 5 = -2\left(\frac{9}{4}\right) - 9 - 5.\]Simplify further: \(-\frac{18}{4} - 9 - 5 = -\frac{9}{2} - 9 - 5 = -\frac{9}{2} - \frac{18}{2} - \frac{10}{2} = -\frac{37}{2}.\) Thus, the vertex is \(\left(\frac{3}{2}, -\frac{37}{2}\right)\).
04
Graph the function
To graph the function, plot the vertex calculated in step 3 as a starting point: \(\left(\frac{3}{2}, -\frac{37}{2}\right)\).Since \(P(x) = -2x^2 - 6x - 5\) is a downward-opening parabola (because \(a = -2 < 0\)), sketch the parabola accordingly.The vertex is the highest point on the graph, with the parabola extending downwards.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a crucial point that helps to determine its shape and direction. It is either the highest or lowest point on a parabola, depending on whether it opens upwards or downwards. For instance, in the given quadratic function \( P(x) = -2x^2 - 6x - 5 \), the parabola opens downward, and thus, the vertex is its highest point.
To find the vertex, we use the vertex formula: the x-coordinate of the vertex is given by \( x = -\frac{b}{2a} \). This formula arises from the properties of the quadratic function. By using this formula, we can accurately determine where the vertex lies on the x-axis.
Once the x-coordinate is found, substitute it back into the original equation to find the y-coordinate. This will give you the complete vertex as a coordinate pair, \( \left( x, y \right) \). For this exercise, using \( a = -2 \) and \( b = -6 \), we calculated the vertex as \( \left( \frac{3}{2}, -\frac{37}{2} \right) \). This point represents the apex of the parabola and is fundamental in understanding the graph's layout.
To find the vertex, we use the vertex formula: the x-coordinate of the vertex is given by \( x = -\frac{b}{2a} \). This formula arises from the properties of the quadratic function. By using this formula, we can accurately determine where the vertex lies on the x-axis.
Once the x-coordinate is found, substitute it back into the original equation to find the y-coordinate. This will give you the complete vertex as a coordinate pair, \( \left( x, y \right) \). For this exercise, using \( a = -2 \) and \( b = -6 \), we calculated the vertex as \( \left( \frac{3}{2}, -\frac{37}{2} \right) \). This point represents the apex of the parabola and is fundamental in understanding the graph's layout.
Graphing Quadratic Functions
Graphing quadratic functions helps visualize the parabola described by an equation. A quadratic function in the form \( ax^2 + bx + c \) depicts a parabola, which may open upwards or downwards based on the coefficient \( a \).
If \( a > 0 \), the parabola opens upwards, resembling a U-shape and having the vertex as the lowest point. Conversely, if \( a < 0 \), as in our function \( P(x) = -2x^2 - 6x - 5 \), the parabola opens downwards, and the vertex represents the highest point.
To graph the function:
If \( a > 0 \), the parabola opens upwards, resembling a U-shape and having the vertex as the lowest point. Conversely, if \( a < 0 \), as in our function \( P(x) = -2x^2 - 6x - 5 \), the parabola opens downwards, and the vertex represents the highest point.
To graph the function:
- Start by plotting the vertex \( \left( \frac{3}{2}, -\frac{37}{2} \right) \).
- Identify the symmetry line, which vertically passes through the vertex.
- Select additional points on either side of the vertex to mark the curve of the parabola accurately.
- Connect the points with a smooth curve to depict the parabola.
Parabolic Equations
Parabolic equations describe curves known as parabolas that can model various natural phenomena and practical problems.
In mathematics, a standard form of a quadratic equation is \( ax^2 + bx + c \). This can represent the path of projectiles, light reflections in mirrors, and much more. The example function \( P(x) = -2x^2 - 6x - 5 \) forms a downward-facing parabola, representative of a negative quadratic coefficient \( a \).
The characteristics of a parabolic equation include:
In mathematics, a standard form of a quadratic equation is \( ax^2 + bx + c \). This can represent the path of projectiles, light reflections in mirrors, and much more. The example function \( P(x) = -2x^2 - 6x - 5 \) forms a downward-facing parabola, representative of a negative quadratic coefficient \( a \).
The characteristics of a parabolic equation include:
- A symmetrical bell shape called a parabola that is consistent throughout its domain.
- A vertex that indicates the peak or trough of the parabola.
- An axis of symmetry that the parabola mirrors across, which always passes through the vertex.