Chapter 3: Problem 14
For each quadratic function, (a) write the function in the form \(P(x)=a(x-h)^{2}+k,\) (b) give the vertex of the parabola, and (c) graph the function. Do not use a calculator. $$P(x)=-4 x^{2}+4 x$$
Short Answer
Expert verified
The vertex form is \(P(x) = -4(x-\frac{1}{2})^2 + 1\), with a vertex at \(\left( \frac{1}{2}, 1 \right)\).
Step by step solution
01
Identify Coefficients
For the quadratic function given as \(P(x) = -4x^2 + 4x\), identify the coefficients: \(a = -4\), \(b = 4\), and \(c = 0\) (since there is no constant term).
02
Complete the Square
Rewrite the function by completing the square. Start by factoring \(-4\) from the first two terms: \(P(x) = -4(x^2 - x)\). To complete the square inside the parenthesis, take half of the linear term coefficient \(b = -1\), square it to get \(\left(-\frac{1}{2}\right)^2 = \frac{1}{4}\). Add and subtract \(\frac{1}{4}\) inside the parenthesis: \(P(x) = -4(x^2 - x + \frac{1}{4} - \frac{1}{4})\). This simplifies to: \(P(x) = -4((x - \frac{1}{2})^2 - \frac{1}{4})\).
03
Simplify Completed Square
Distribute the \(-4\) across the terms adjusted for the square: \(P(x) = -4(x - \frac{1}{2})^2 + 1\). This is the function in vertex form, where \(a = -4\), \(h = \frac{1}{2}\), and \(k = 1\).
04
Identify the Vertex
The vertex form \(P(x) = a(x-h)^2+k\) gives the vertex of the parabola at \((h, k)\). Thus, the vertex of our function is \(\left( \frac{1}{2}, 1 \right)\).
05
Graph the Function
Sketch the graph using the vertex. The vertex is \(\left( \frac{1}{2}, 1 \right)\). Since \(a = -4\), the parabola opens downwards and is narrower than the standard parabola \(x^2\) due to the larger magnitude of \(a\). Plot additional points by choosing values of \(x\) nearby to show more curvature. For example, use \(x = 0\) and \(x = 1\) to check more points on the curve.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Completing the Square
Completing the square is a method used to transform a quadratic equation into a form that reveals key characteristics about its graph, like its vertex. To complete the square for a quadratic in the form of \( ax^2 + bx + c \), we mainly focus on the terms \( ax^2 + bx \). Here's how:
- Factor out any coefficients from the \( x^2 \) and \( x \) terms.
- Next, take half of the coefficient of \( x \), square it, and add or subtract this square inside the equation to balance it.
Vertex Form of a Parabola
The vertex form of a quadratic equation is given by \( P(x) = a(x - h)^2 + k \). This form is incredibly useful because it allows us to easily identify the vertex of the parabola, a crucial part of graphing quadratics.In this form:
- \( a \) determines the opening direction and width of the parabola.
- \( (h, k) \) represents the vertex, or the "tip" of the parabola.
Graphing Parabolas
Graphing parabolas involves understanding the orientation and shape of the parabola based on its quadratic equation. The graph of a quadratic function is always a parabola.To graph a quadratic function effectively:
- Identify the vertex, which acts as a central point.
- Determine the direction it opens: upward if \( a > 0 \) or downward if \( a < 0 \).
- Calculate and plot a few additional points on either side of the vertex for accuracy.
- Consider the width, influenced by the absolute value of \( a \); a larger \(|a|\) makes the parabola narrower.
Vertex of a Parabola
The vertex of a parabola is crucial because it represents the maximum or minimum point, depending on the parabola's orientation. In the vertex form \( P(x) = a(x-h)^2+k \), the vertex is simply \( (h, k) \).For practical purposes:
- The vertex tells us the "peak" where the parabola changes direction.
- If \( a > 0 \), the vertex is the minimum point; if \( a < 0 \), it's the maximum.
- This point helps in understanding the overall shift and graphing the parabola accurately.