Chapter 3: Problem 128
Solve each formula for the indicated variable. Leave \(\pm\) in answers when applicable. Assume that no denominators are 0 $$S=2 \pi r h+2 \pi r^{2} \quad \text { for } r$$
Short Answer
Expert verified
The formula for \( r \) is \( r = \frac{-h \pm \sqrt{h^2 + \frac{2S}{\pi}}}{2} \).
Step by step solution
01
Identify the Formula Structure
Analyze the given formula \( S = 2\pi rh + 2\pi r^2 \). It represents the surface area \( S \) of a cylinder, where \( r \) is the radius, \( h \) is the height, and \( 2\pi r^2 \) is the area of the two bases. Your task is to isolate \( r \).
02
Factor Out Common Terms
Factor \( 2\pi r \) from the right-hand side of the equation: \( S = 2\pi r (h + r) \). This simplifies the equation and prepares it for solving for \( r \).
03
Rearrange the Equation
Rearrange the factored equation to isolate \( r \):\[ 2\pi r(h + r) = S \] Divide both sides by \( 2\pi \) to get: \[ r(h + r) = \frac{S}{2\pi} \]
04
Solve Quadratic Equation for r
This becomes a quadratic equation in the form \( r^2 + hr - \frac{S}{2\pi} = 0 \). Use the quadratic formula \( r = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1 \), \( b = h \), and \( c = -\frac{S}{2\pi} \).
05
Apply the Quadratic Formula
Substitute \( a = 1 \), \( b = h \), and \( c = -\frac{S}{2\pi} \) into the quadratic formula: \[ r = \frac{-h \pm \sqrt{h^2 - 4 \cdot 1 \cdot \left(-\frac{S}{2\pi}\right)}}{2 \cdot 1} \] Simplify under the square root: \[ r = \frac{-h \pm \sqrt{h^2 + 2S/\pi}}{2} \].
06
Simplify the Expression
The solution \( r = \frac{-h \pm \sqrt{h^2 + \frac{2S}{\pi}}}{2} \) is simplified to show \( r \) in terms of \( S \) and \( h \). This reflects the possible positive and negative roots, but practically only the positive value is needed for a physical radius.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Surface Area of Cylinder
The surface area of a cylinder is a crucial concept in geometry and physics, as it defines the total area that covers the cylindrical surface. A cylinder is composed of two circular bases (top and bottom) and a curved surface that connects them. To calculate its surface area, we use the formula: \[ S = 2\pi rh + 2\pi r^2 \] where:
- \( S \) is the surface area.
- \( r \) represents the radius of the circular base.
- \( h \) stands for the height of the cylinder.
- \( 2\pi rh \) corresponds to the lateral or curved surface area.
- \( 2\pi r^2 \) is the combined area of the two bases.
Isolating Variables
When working with equations, isolating variables is a key mathematical skill. It involves rearranging the equation to express one specific variable in terms of others. This step is crucial for problem-solving and understanding relationships between variables. For the given equation of a cylinder's surface area:\[ S = 2\pi rh + 2\pi r^2 \]we need to solve for the radius \( r \). The process involves:
- Factoring common terms, such as \( 2\pi r \), to simplify the equation.
- Rearranging terms to isolate the variable \( r \) on one side of the equation.
- Dividing and simplifying expressions to further clarify the isolated variable.
Quadratic Formula
The quadratic formula is a tool used to find the solutions of quadratic equations, which are equations of the form \( ax^2 + bx + c = 0 \). It is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] This formula is essential for problems where the equation cannot be factored easily. In the context of our cylinder's surface area equation, when isolated for the radius, it transforms into a quadratic equation: \[ r^2 + hr - \frac{S}{2\pi} = 0 \] Here, \( a = 1 \), \( b = h \), and \( c = -\frac{S}{2\pi} \). Using the quadratic formula allows us to find the value of \( r \), which would satisfy the equation given known values of surface area \( S \) and height \( h \). Remember, practically, we are interested in the positive value of \( r \), as it represents a physical dimension in this context.
Mathematical Problem Solving
Mathematical problem solving is a process where we use logic and reasoning to navigate through a problem. It involves understanding the problem, developing a strategy, carrying out the plan, and then evaluating the solution. In solving the problem of a cylinder's surface area for the radius \( r \), we:
- Identified the initial problem and variable to solve for.
- Utilized strategies such as factoring and rearranging formulas to simplify our approach.
- Applied the quadratic formula to handle the complexity of the quadratic equation.
- Interpreted the solution in the context of a real-world scenario, ensuring the physical meaning makes sense.