Chapter 2: Problem 71
Each function is either even or odd Evaluate \(f(-x)\) to determine which situation applies. $$f(x)=\frac{x^{3}+3 x}{x}$$
Short Answer
Expert verified
The function is even.
Step by step solution
01
Calculate \(f(x)\)
First, simplify the given function. We have \(f(x) = \frac{x^3 + 3x}{x}\). Simplify by dividing each term in the numerator by \(x\). This gives us \(f(x) = x^2 + 3\).
02
Evaluate \(f(-x)\)
Now, substitute \(-x\) into the simplified function. If \(f(x) = x^2 + 3\), then \(f(-x) = (-x)^2 + 3 = x^2 + 3\).
03
Compare \(f(-x)\) with \(f(x)\)
Check whether \(f(-x)\) matches \(f(x)\) to determine if it is even or odd. We find that \(f(-x) = x^2 + 3\) is the same as \(f(x) = x^2 + 3\).
04
Determine if \(f(x)\) is even, odd, or neither
Since \(f(-x) = f(x)\), the function \(f(x)\) is even according to the definition of even functions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Function Evaluation
Function evaluation is a fundamental skill in algebra and calculus, allowing us to determine the output of a function for any given input. In our example, we have the function \(f(x) = \frac{x^3 + 3x}{x}\). To evaluate this, first simplify the function: divide each term in the numerator by \(x\), reducing it to \(f(x) = x^2 + 3\). This makes it easier to substitute values for \(x\) and understand how different inputs affect the output.
When we evaluate \(f\) at specific inputs like \(-x\), we're checking for patterns or properties such as symmetry. For this exercise, substituting \(-x\) into the function results in \((-x)^2 + 3\), which simplifies back to \(x^2 + 3\). Evaluating functions in this way helps to establish whether certain properties, like symmetry, apply to a given function.
When we evaluate \(f\) at specific inputs like \(-x\), we're checking for patterns or properties such as symmetry. For this exercise, substituting \(-x\) into the function results in \((-x)^2 + 3\), which simplifies back to \(x^2 + 3\). Evaluating functions in this way helps to establish whether certain properties, like symmetry, apply to a given function.
Simplifying Expressions for Clarity
Simplifying expressions is crucial for understanding and working with functions effectively. In our function \(f(x) = \frac{x^3 + 3x}{x}\), simplifying involves breaking down the expression to its most basic form, \(x^2 + 3\).
This simplifies future calculations and evaluations, making it easier to substitute variables and to see any inherent properties of the function.
Here are some tips for simplifying functions effectively:
This simplifies future calculations and evaluations, making it easier to substitute variables and to see any inherent properties of the function.
Here are some tips for simplifying functions effectively:
- Identify common factors in the numerator and denominator that allow for simplification.
- Break down each term separately if possible before simplifying.
- Reevaluate the expression to ensure that simplification has not changed the function's characteristics.
Exploring Symmetry in Functions
Symmetry in functions can reveal whether a function is even, odd, or neither. These characteristics can often simplify the process of understanding the behaviour of complex functions.
A function is even if substituting \(-x\) results in the same value as \(f(x)\). In our example, both \(f(x) = x^2 + 3\) and \(f(-x)\) evaluate to the same expression, indicating that \(f(x)\) is even.
Understanding symmetry:
A function is even if substituting \(-x\) results in the same value as \(f(x)\). In our example, both \(f(x) = x^2 + 3\) and \(f(-x)\) evaluate to the same expression, indicating that \(f(x)\) is even.
Understanding symmetry:
- Even functions: These have symmetry about the y-axis. Graphically, this means that the left and right sides of the graph are mirror images.
- Odd functions: These have rotational symmetry about the origin. If \(f(-x) = -f(x)\), then the function is odd.
- Neither: If \(f(x)\) doesn't meet the criteria for either even or odd, it is neither.