Chapter 2: Problem 67
If \((r, 0)\) is an \(x\) -intercept of the graph of \(y=f(x),\) what statement can be made about an \(x\) -intercept of the graph of each function? (Hint: Make a sketch.) (a) \(y=-f(x)\) (b) \(y=f(-x)\) (c) \(y=-f(-x)\)
Short Answer
Expert verified
(a) (r, 0), (b) (-r, 0), (c) (-r, 0).
Step by step solution
01
Understanding x-intercepts
Recall that an x-intercept of a function is a point where the graph of the function crosses the x-axis. This means that for a point \((x, y)\) to be an x-intercept, the y-coordinate must be zero, i.e., if \((r, 0)\) is the x-intercept of \(y=f(x)\), then \(f(r) = 0\).
02
Evaluate y = -f(x)
For the function \(y = -f(x)\), we can substitute the x-intercept \((r, 0)\) from \(y=f(x)\). Since \(f(r) = 0\), we have \(-f(r) = -0 = 0\). Thus, \((r, 0)\) remains an x-intercept.
03
Evaluate y = f(-x)
For the function \(y = f(-x)\), we consider what happens to x-intercepts. If \(f(r) = 0\), the point \((r, 0)\) is an x-intercept of \(y=f(x)\). We need \(f(-r) = 0\) for \((r, 0)\) to be an x-intercept of \(y=f(-x)\), giving us \((-r, 0)\) as the x-intercept.
04
Evaluate y = -f(-x)
For the function \(y = -f(-x)\), we observe that it combines the transformations from steps 2 and 3. Substitute \(f(-r) = 0\) for \((r, 0)\) to be an x-intercept of \(y=-f(-x)\). This results in \(f(-r) = 0 = 0\), and hence \((-r, 0)\) is the x-intercept.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graph Transformations
Graph transformations can significantly change the appearance and position of a function's graph. Transformations help us understand how the graph behaves when we apply various operations like reflection or translation to a function.
- Reflection: One of the most common transformations, reflection, occurs when we apply a negative sign to a function, resulting in the graph flipping over a particular axis.
- Translation: Involves shifting the graph up, down, left, or right. For example, adding a constant to the function shifts the graph vertically.
- Stretching and Compressing: Changing the scale of the graph by multiplying the function by a constant. This adjusts the width or height of the graph.
- For \( y = -f(x) \), the graph reflects over the x-axis.
- For \( y = f(-x) \), the graph reflects over the y-axis, flipping any x-intercepts to its opposite coordinate.
- For \( y = -f(-x) \), both x and y reflections occur, creating a vertical and horizontal flip.
Precalculus Functions
Precalculus functions serve as the building blocks for more complex mathematical concepts, preparing students for calculus. These functions form a significant foundation, focusing on properties and their transformations. Key precalculus functions encompass:
- Polynomial Functions: Such as quadratic and cubic functions appearing often in transformations.
- Exponential and Logarithmic Functions: Explain growth patterns and log-based calculations.
- Trigonometric Functions: Define periodic phenomena and include sine, cosine, etc.
Function Evaluation
Function evaluation involves determining the output of a function for a given input, usually presented as \( f(x) \). It's a crucial part of analyzing how functions transform and predict changes in graph properties, like x-intercepts.Evaluating a function steps include:
- Substitute the input value into the function, such as placing \( x = r \).
- Solve the function equation to obtain the output, i.e., \( y = f(x) \).
- For \( y = -f(x) \), ensuring \( f(r) = 0 \) results in the same x-intercept \( (r, 0) \).
- For \( y = f(-x) \), check if \( f(-r) = 0 \) for \( (-r, 0) \) to be an x-intercept.
- For \( y = -f(-x) \), combine steps to achieve \( (-r, 0) \) as the x-intercept.