Chapter 13: Problem 52
Find the equation of the tangent line to the function \(f\) at the given point. Then graph the function and the tangent line together. $$f(x)=\frac{1}{2} x^{2}-2 \text { at }(2,0)$$
Short Answer
Expert verified
The tangent line equation is \( y = 2x - 4 \).
Step by step solution
01
Find the derivative of the function
The equation of the tangent line requires the slope at a certain point, which is given by the derivative of the function. The function given is \( f(x) = \frac{1}{2}x^2 - 2 \). The derivative of this function is obtained by applying the power rule: \( f'(x) = x \).
02
Evaluate the derivative at the given point
The slope of the tangent line at the point \((2, 0)\) is given by \( f'(2) \).Substituting \( x = 2 \) into the derivative gives us \( f'(2) = 2 \).Thus, the slope of the tangent line is 2.
03
Find the equation of the tangent line using point-slope form
The point-slope form of a line is \( y - y_1 = m(x - x_1) \) where \((x_1, y_1)\) is a point on the line and \( m \) is the slope.Using the point \((2, 0)\) and the slope \( m = 2 \), the equation becomes:\[ y - 0 = 2(x - 2) \]Simplifying gives \[ y = 2x - 4 \].This is the equation of the tangent line.
04
Graph the function and the tangent line
Plot the function \( f(x) = \frac{1}{2}x^2 - 2 \) and the tangent line \( y = 2x - 4 \) together on the same coordinate grid.The function is a parabola opening upwards, and the line is a straight line that intersects the parabola at the point \((2, 0)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
The derivative of a function represents the rate of change or the slope of the function at any given point. You can think of it as the function's "speed" at a particular moment. This is extremely useful because it allows us to find the slope of the tangent line to the curve. For the function \[ f(x) = \frac{1}{2}x^2 - 2, \]to find the derivative, we apply the power rule. The power rule states that if you have a term like \[ ax^n, \]then its derivative is \[ nax^{n-1}. \]Using this rule, we differentiate each term of our function separately.
- The derivative of \( \frac{1}{2}x^2 \) is \( x \), because the power 2 multiplies by \( \frac{1}{2} \) to make 1, and the power of \( x \) drops from 2 to 1.
- The derivative of a constant like \(-2\) is 0, since constants do not change.
Point-Slope Form
Point-slope form is an essential tool to find the equation of a tangent line to a curve at a specific point. It is especially useful when you already know a point on the line and the slope, which in our scenario is the derivative evaluated at that point. The point-slope formula is:\[ y - y_1 = m(x - x_1) \]where:
- \((x_1, y_1)\) is a known point on the line.
- \( m \) is the slope of the line, obtained from the derivative.
Graphing Functions
Graphing functions is a powerful way to visualize the relationship described by a function and to see the behavior of its tangent line. To graph the function \[ f(x) = \frac{1}{2}x^2 - 2 \],recognize it is a parabola, which is a common shape for a quadratic function. This specific parabola opens upwards because the coefficient of \(x^2\) (\(\frac{1}{2}\)) is positive. The \(-2\) term shifts the whole graph down.
- The vertex of the parabola is at the point of minimum value since it opens upwards, which happens at \((0, -2)\).
- The line of symmetry of the parabola is the y-axis.