Chapter 13: Problem 3
Determine each limit. Refer to the accompanying graph of \(y=f(x)\) when it is given. Do not use a calculator. (a) \(\lim _{x \rightarrow 3^{+}} f(x)\) (b) \(\lim _{x \rightarrow 3^{-}} f(x)\) where \(f(x)=\frac{x}{5(3-x)^{3}}\) (GRAPH CANNOT COPY).
Short Answer
Expert verified
(a) \(-\infty\), (b) \(\infty\)
Step by step solution
01
Understand the limit notation
The limit notation \( \lim_{x \to 3^{+}} f(x) \) refers to the right-hand limit at \( x = 3 \), which means approaching 3 from values greater than 3. Conversely, \( \lim_{x \to 3^{-}} f(x) \) refers to the left-hand limit at \( x = 3 \), approaching 3 from values less than 3. We will examine the behavior of the function as \( x \to 3 \) from these two sides.
02
Analyze \(f(x)\) as \(x \to 3^{+}\)
For \( x \to 3^{+} \), the term \((3-x)\) becomes a small negative number (since \( x > 3 \)). Therefore, \((3-x)^3 = (3-x)(3-x)(3-x)\) is negative and approaches zero. The function \( f(x) = \frac{x}{5(3-x)^{3}} \) thus becomes extremely large in the negative direction as \((3-x)^3\) approaches zero. Therefore, \( \lim_{x \to 3^{+}} f(x) = -\infty \).
03
Analyze \(f(x)\) as \(x \to 3^{-}\)
For \( x \to 3^{-} \), the term \((3-x)\) becomes a small positive number (since \( x < 3 \)). Therefore, \((3-x)^3\) is a positive value, decreasing towards zero. The function \( f(x) = \frac{x}{5(3-x)^{3}} \) will tend towards infinity as \((3-x)^3\) approaches zero. Therefore, \( \lim_{x \to 3^{-}} f(x) = \infty \).
04
Conclusion
The two limits show that as \( x \) approaches 3 from the right, \( f(x) \) goes to \(-\infty \), and as \( x \) approaches from the left, \( f(x) \) goes to \( \infty \). These directional behaviors indicate a vertical asymptote at \( x = 3 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Right-Hand Limit
The right-hand limit, often notated as \( \lim_{x \to a^{+}} f(x) \), represents the behavior of a function \( f(x) \) when approaching a certain point \( a \) from values greater than \( a \). Think of it as creeping down towards \( a \) from the right side. This concept is crucial because it helps us understand how a function behaves just over a certain point.
When examining the right-hand limit of the function \( f(x) = \frac{x}{5(3-x)^3} \) as \( x \) approaches 3 from the right (\( x \to 3^{+} \)), the key part to focus on is \( (3-x)^3 \). As \( x \) exceeds 3, \( (3 - x) \) becomes a small negative number, resulting in a negative cubic value. Since this term approaches zero, \( f(x) \) increases to large negative numbers, leading \( \lim_{x \to 3^{+}} f(x) = -\infty \).
When examining the right-hand limit of the function \( f(x) = \frac{x}{5(3-x)^3} \) as \( x \) approaches 3 from the right (\( x \to 3^{+} \)), the key part to focus on is \( (3-x)^3 \). As \( x \) exceeds 3, \( (3 - x) \) becomes a small negative number, resulting in a negative cubic value. Since this term approaches zero, \( f(x) \) increases to large negative numbers, leading \( \lim_{x \to 3^{+}} f(x) = -\infty \).
- Approach from the right means starting with values greater than 3.
- \((3-x)^3\) becomes negative and tiny, driving \( f(x) \) to negative infinity.
Left-Hand Limit
Contrary to the right-hand limit, the left-hand limit, denoted as \( \lim_{x \to a^{-}} f(x) \), tells us what happens to \( f(x) \) when \( x \) approaches \( a \) from values less than \( a \). Picture approaching the point from the left side, or smaller numbers.
In the same function \( f(x) = \frac{x}{5(3-x)^3} \), examining the left-hand limit as \( x \to 3^{-} \), means \( x \) is creeping towards 3 but from the left side (values less than 3). Here, \((3-x)\) is a positive number but tiny, thus \((3-x)^3\) remains positive and decreases towards zero. This makes \( f(x) \) explode to positive infinity, which means \( \lim_{x \to 3^{-}} f(x) = \infty \).
In the same function \( f(x) = \frac{x}{5(3-x)^3} \), examining the left-hand limit as \( x \to 3^{-} \), means \( x \) is creeping towards 3 but from the left side (values less than 3). Here, \((3-x)\) is a positive number but tiny, thus \((3-x)^3\) remains positive and decreases towards zero. This makes \( f(x) \) explode to positive infinity, which means \( \lim_{x \to 3^{-}} f(x) = \infty \).
- Approach from the left means starting with values smaller than 3.
- \((3-x)^3\) remains positive and small, causing \( f(x) \) to rise to positive infinity.
Vertical Asymptote
A vertical asymptote is a line \( x = a \) where a function's value blows up to infinity or dives to negative infinity. It signifies a boundary in the graph where the function doesn't touch or cross, serving as a wall.
In the case of \( f(x) = \frac{x}{5(3-x)^3} \), examining the limits as \( x \to 3^{+} \) and \( x \to 3^{-} \) reveals that the function approaches \( -\infty \) from the right and \( \infty \) from the left. This dramatic change shows that \( x = 3 \) is a vertical asymptote.
In the case of \( f(x) = \frac{x}{5(3-x)^3} \), examining the limits as \( x \to 3^{+} \) and \( x \to 3^{-} \) reveals that the function approaches \( -\infty \) from the right and \( \infty \) from the left. This dramatic change shows that \( x = 3 \) is a vertical asymptote.
- Indicates a break in the graph where the function does not touch or intersect.
- Shows a direction change in the function behavior at \( x = 3 \).