/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 55 Evaluate the terms of \(\sum_{i=... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the terms of \(\sum_{i=1}^{4} f\left(x_{i}\right) \Delta x,\) with \(x_{1}=0, x_{2}=2, x_{3}=4, x_{4}=6,\) and \(\Delta x=0.5,\) for each function. $$f(x)=4 x-7$$

Short Answer

Expert verified
The evaluated sum is 10.

Step by step solution

01

Understand the Task

We need to evaluate the sum \(\sum_{i=1}^{4} f\left(x_{i}\right) \Delta x\), which means calculating \(f(x_i)\) for each \(x_i\) and then multiplying it by \(\Delta x\), and finally summing all the terms.
02

Evaluate f at x1

Here, apply the function \(f(x) = 4x - 7\) for \(x_1 = 0\): \[ f(x_1) = 4(0) - 7 = -7 \] Then multiply by \(\Delta x = 0.5\): \[ f(x_1) \Delta x = (-7) \times 0.5 = -3.5 \]
03

Evaluate f at x2

Apply the function \(f(x) = 4x - 7\) for \(x_2 = 2\): \[ f(x_2) = 4(2) - 7 = 1 \] Then multiply by \(\Delta x = 0.5\): \[ f(x_2) \Delta x = 1 \times 0.5 = 0.5 \]
04

Evaluate f at x3

Apply the function \(f(x) = 4x - 7\) for \(x_3 = 4\): \[ f(x_3) = 4(4) - 7 = 9 \] Then multiply by \(\Delta x = 0.5\): \[ f(x_3) \Delta x = 9 \times 0.5 = 4.5 \]
05

Evaluate f at x4

Apply the function \(f(x) = 4x - 7\) for \(x_4 = 6\): \[ f(x_4) = 4(6) - 7 = 17 \] Then multiply by \(\Delta x = 0.5\): \[ f(x_4) \Delta x = 17 \times 0.5 = 8.5 \]
06

Evaluate the Sum

Now sum all the terms: \[ \sum_{i=1}^{4} f(x_i) \Delta x = (-3.5) + 0.5 + 4.5 + 8.5 = 10 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Evaluation
In this exercise, we are tasked with evaluating a function at specific points. The function given is a linear one, defined as \( f(x) = 4x - 7 \). Evaluating a function means substituting the variable \( x \) with given values (denoted as \( x_i \)) to find an output. This output gives us a numerical result specific to each input.
  • First, identify all \( x_i \) values where the function needs to be evaluated. Here, \( x_1 = 0, x_2 = 2, x_3 = 4, x_4 = 6 \).
  • For each \( x_i \), plug it into the function \( f(x) \).
  • Calculate to find \( f(x_1), f(x_2), f(x_3), \) and \( f(x_4) \).
For instance, for \( x_1 = 0 \), the calculation is straightforward: \[f(x_1) = 4(0) - 7 = -7\]Repeat this process for each provided \( x_i \). This allows us to understand how the function behaves at these key points.
Definite Integral Approximation
Riemann Sums are a concept used to approximate the area under a curve between two points, leading us to the concept of a definite integral. In this exercise, the sum \[\sum_{i=1}^{4} f(x_i) \Delta x\]is a simple example of such an approximation. Here, \( \Delta x = 0.5 \) signifies the width of each sub-interval over the integration range.
  • The width \( \Delta x \) is constant, reflecting equal partitioning of the range.
  • The function values \( f(x_i) \) approximate the height of rectangles, representing slices of the area under the curve.
This approach helps understand integral calculus by breaking down the complex curve into manageable and calculable steps. By multiplying each function value \( f(x_i) \) by \( \Delta x \), and then summing them up, we approximate the area under the curve from \( x_1 \) to \( x_4 \). It is like calculating the total shaded region using rectangle areas where:\[sum = (f(x_1) \times \Delta x) + (f(x_2) \times \Delta x) + (f(x_3) \times \Delta x) + (f(x_4) \times \Delta x)\] This sum gives a numerical approximation equivalent to using rectangles to mimic the true shape of the curve.
Step-by-Step Solution
Following a methodical, step-by-step process ensures clarity and understanding. This exercise unravels the approximation through a sequence of evaluations and multiplications:1. **Calculate Function Values:**
Evaluate \( f(x) \) at each specified \( x_i \): - For \( x_1 = 0 \), \( f(x_1) = -7 \) - For \( x_2 = 2 \), \( f(x_2) = 1 \) - For \( x_3 = 4 \), \( f(x_3) = 9 \) - For \( x_4 = 6 \), \( f(x_4) = 17 \)2. **Multiply by \( \Delta x \):**
Multiply each function output by \( \Delta x = 0.5 \): - \( f(x_1) \times \Delta x = -3.5 \) - \( f(x_2) \times \Delta x = 0.5 \) - \( f(x_3) \times \Delta x = 4.5 \) - \( f(x_4) \times \Delta x = 8.5 \)3. **Add All Results:**
Finally, sum up these products: \[ (-3.5) + 0.5 + 4.5 + 8.5 = 10 \]This step-by-step process transforms theoretical principles into practical calculations. It not only supports function evaluation but also unfolds the logic of Riemann sums for approximating definite integrals.

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Most popular questions from this chapter

MODELING Disease Infection What will happen when an infectious disease is introduced into a family? Suppose a family has \(I\) infected members and \(S\) members who are not infected, but are susceptible to contracting the disease. The probability \(P\) of \(k\) people not contracting the disease during a l-week period can be calculated by the formula $$P=\left(\begin{array}{l} S \\ k \end{array}\right) q^{k}(1-q)^{s-k}$$ where \(q=(1-p)^{l}\) and \(p\) is the probability that a susceptible person contracts the disease from an infected person. For example, if \(p=0.5,\) then there is a \(50 \%\) chance that a susceptible person exposed to one infected person for 1 week will contract the disease. (Source: Hoppensteadt, F. and C. Peskin, Mathematics in Medicine and the Life Sciences, Springer-Verlag.) A. Approximate the probability \(P\) of 3 family members not becoming infected within 1 week if there are currently 2 infected and 4 susceptible members. Assume that \(p=0.1\) B. A highly infectious disease can have \(p=0.5 .\) Repeat part (a) with this value of \(p\) C. Approximate the probability that everyone would become sick in a large family if initially \(I=1, S=9\) and \(p=0.5\)

Prove each statement for positive integers \(n\) and \(r\), with \(r \leq n\). (Hint: Use the definitions of permutations and combinations.) $$P(n, 1)=n$$

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