/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Write the binomial expansion for... [FREE SOLUTION] | 91Ó°ÊÓ

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Write the binomial expansion for each expression. $$(3 x-2 y)^{6}$$

Short Answer

Expert verified
The binomial expansion is: \(729x^6 - 2916x^5y + 2916x^4y^2 - 3888x^3y^3 + 2592x^2y^4 - 864xy^5 + 64y^6\).

Step by step solution

01

Understanding Binomial Theorem

The Binomial Theorem gives us a way to expand expressions of the form \((a+b)^n\). According to the theorem, \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\). In this exercise, we identify \(a = 3x\), \(b = -2y\), and \(n = 6\).
02

Set Up the General Term of the Expansion

For each term in the expansion, we use the formula \( \binom{n}{k} a^{n-k}b^k \). So, the \(k\)-th term of \((3x - 2y)^6\) is \(\binom{6}{k} (3x)^{6-k} (-2y)^k\).
03

Calculate Each Term

We will calculate each term from \(k=0\) to \(k=6\) using the formula. Let's do the first few steps to illustrate the process:- When \(k=0\): \(\binom{6}{0} (3x)^6 (-2y)^0 = 1 \times (729x^6) \times 1 = 729x^6\).- When \(k=1\): \(\binom{6}{1} (3x)^5 (-2y)^1 = 6 \times 243x^5 \times -2y = -2916x^5y\).Continue this for \(k=2, ..., 6\).
04

Sum Up All Terms

Calculate all the remaining terms and add them up to get the full binomial expansion:- When \(k=2\): \(2916x^4y^2\).- When \(k=3\): \(-3888x^3y^3\).- When \(k=4\): \(2592x^2y^4\).- When \(k=5\): \(-864xy^5\).- When \(k=6\): \(64y^6\).Combine all the terms:\[ 729x^6 - 2916x^5y + 2916x^4y^2 - 3888x^3y^3 + 2592x^2y^4 - 864xy^5 + 64y^6 \]
05

Write Final Expansion

The final expansion of \((3x - 2y)^6\) is:\[ 729x^6 - 2916x^5y + 2916x^4y^2 - 3888x^3y^3 + 2592x^2y^4 - 864xy^5 + 64y^6 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Theorem
The Binomial Theorem is a powerful tool in algebra that allows us to expand an expression raised to a power. When we have a binomial expression like \((a+b)^n\), it means we want to express this as a sum of terms. The formula for this is \((a+b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\).
This theorem helps not just in expanding expressions but also in finding specific coefficients in these expansions. Each term in the expansion is determined by the binomial coefficient \(\binom{n}{k}\), which is a part of combinatorics. Knowing how to use the Binomial Theorem can simplify lots of algebraic tasks.
In our case, expanding \((3x - 2y)^6\) using the Binomial Theorem requires identifying \(a\) as \(3x\), \(b\) as \(-2y\), and \(n\) as 6. This helps simplify the expansion into manageable terms.
Combinatorics
Combinatorics is a key mathematical field that deals with counting, arrangement, and combination of elements within sets. In the context of the Binomial Theorem, combinatorics appears in the form of binomial coefficients. These coefficients are written as \(\binom{n}{k}\) and are calculated using the formula \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\).
They tell us the number of ways we can choose \(k\) objects from \(n\) objects without regard to order.
This becomes particularly useful in polynomial expansions, as it helps in determining the coefficient for each specific term. For example, in our binomial expansion task, calculating \(\binom{6}{k}\) for each term tells us how many times a term should be considered in the final expanded expression.
Thus, mastering combinatorics allows one to efficiently manage and compute expansions using the Binomial Theorem.
Polynomial Expansion
Polynomial expansion involves spreading out or developing an expression into a series of simpler terms. In this context, we're transforming a binomial expression, \((3x - 2y)^6\), into a series of terms. Each term is calculated as \( \binom{n}{k} (3x)^{n-k} (-2y)^k \), which lets us see how the coefficients and variables distribute.
This process results in a polynomial, which is a sum of multiple terms rather than a product of terms. The beauty of polynomial expansion is that it allows us to simplify complex multiplication tasks by breaking them down into smaller, more manageable pieces.
  • Individual terms like \(729x^6\), \(-2916x^5y\), are computed and summed up to get the full expression.
  • This method helps not just in algebra but in calculus and physics as well, where polynomial functions are often used to model behavior or trends.
Recognizing patterns and using tactical expansion methods is a vital skill in algebra.
Algebra
Algebra is the branch of mathematics dealing with symbols and the rules for manipulating these symbols. It is a foundational tool for finding unknown values and expressing complex relationships simply. In the context of the Binomial Theorem, algebra is about structuring and forming equations that can be solved through expansion.
The task of expanding \((3x - 2y)^6\) is a classic algebra problem. It uses the relationships defined by the Binomial Theorem and combinatorics to convert a single binomial expression into a series of terms. In algebra, such manipulations are essential because:
  • They enable solving equations systematically.
  • They clarify relationships between variables.
  • They provide ways to simplify and solve real-world problems.
Mastering algebraic techniques ensures that students can confidently tackle broader mathematical challenges with ease and precision.

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Most popular questions from this chapter

The table gives the results of a survey of \(14,000\) college students who were cigarette smokers in a recent year. $$\begin{array}{|l|c|} \hline \begin{array}{l} \text { Number of Cigarettes } \\\ \text { per Day } \end{array} & \begin{array}{c} \text { Percent } \\\ \text { (as a decimal) } \end{array} \\ \hline \text { Less than } 1 & 0.45 \\\ 1 \text { to } 9 & 0.24 \\ 10 \text { to } 19 & 0.20 \\ \text { A pack of } 20 \text { or more } & 0.11 \end{array}$$ Using the percents as probabilinies, approximate the probability that, out of 10 of these shudent smokers selected at random, the following were true. Five smoked a pack or more per day.

Determine the positive integer values of \(n\) for which the given statement is not true. $$3^{n}>6 n$$

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MODELING Disease Infection What will happen when an infectious disease is introduced into a family? Suppose a family has \(I\) infected members and \(S\) members who are not infected, but are susceptible to contracting the disease. The probability \(P\) of \(k\) people not contracting the disease during a l-week period can be calculated by the formula $$P=\left(\begin{array}{l} S \\ k \end{array}\right) q^{k}(1-q)^{s-k}$$ where \(q=(1-p)^{l}\) and \(p\) is the probability that a susceptible person contracts the disease from an infected person. For example, if \(p=0.5,\) then there is a \(50 \%\) chance that a susceptible person exposed to one infected person for 1 week will contract the disease. (Source: Hoppensteadt, F. and C. Peskin, Mathematics in Medicine and the Life Sciences, Springer-Verlag.) A. Approximate the probability \(P\) of 3 family members not becoming infected within 1 week if there are currently 2 infected and 4 susceptible members. Assume that \(p=0.1\) B. A highly infectious disease can have \(p=0.5 .\) Repeat part (a) with this value of \(p\) C. Approximate the probability that everyone would become sick in a large family if initially \(I=1, S=9\) and \(p=0.5\)

Prove each statement by mathematical induction. If \(a>1,\) then \(a^{n}>a^{n-1}\)

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