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Find each quotient and express it in rectangular form by first converting the numerator and the denominator to trigonometric form. $$\frac{8}{\sqrt{3}+i}$$

Short Answer

Expert verified
The quotient in rectangular form is \(2\sqrt{3} - 2i\).

Step by step solution

01

Convert the Denominator to Trigonometric Form

Start by identifying the real and imaginary parts of the denominator, which are \( \sqrt{3} \) and \( 1 \) respectively. Calculate the modulus: \( r = \sqrt{(\sqrt{3})^2 + 1^2} = \sqrt{3 + 1} = 2 \). The angle \( \theta \) is given by \( \tan^{-1}(\frac{1}{\sqrt{3}}) = \frac{\pi}{6} \). Therefore, in trigonometric form, the denominator is \( 2 \left( \cos\frac{\pi}{6} + i\sin\frac{\pi}{6} \right) \).
02

Convert the Numerator to Trigonometric Form

The numerator is \( 8 \), a real number with no imaginary part. The modulus is \( 8 \), and the angle \( \theta = \tan^{-1}(0) = 0 \). Therefore, in trigonometric form, the numerator is: \( 8 \left( \cos(0) + i\sin(0) \right) \).
03

Divide the Numerator by the Denominator in Trigonometric Form

Use the formula for the division of complex numbers in trigonometric form: \( \frac{r_1 (\cos \theta_1 + i \sin \theta_1)}{r_2 (\cos \theta_2 + i \sin \theta_2)} = \frac{r_1}{r_2} \left( \cos(\theta_1 - \theta_2) + i\sin(\theta_1 - \theta_2) \right) \). Here, \( r_1 = 8 \), \( \theta_1 = 0 \), \( r_2 = 2 \), and \( \theta_2 = \frac{\pi}{6} \). The division gives \( \frac{8}{2} \left( \cos(0 - \frac{\pi}{6}) + i\sin(0 - \frac{\pi}{6}) \right) = 4 \left( \cos(-\frac{\pi}{6}) + i\sin(-\frac{\pi}{6}) \right) \).
04

Convert the Result Back to Rectangular Form

Since \( \cos(-\frac{\pi}{6}) = \cos(\frac{\pi}{6}) = \frac{\sqrt{3}}{2} \) and \( \sin(-\frac{\pi}{6}) = -\sin(\frac{\pi}{6}) = -\frac{1}{2} \), the expression becomes \( 4 \left( \frac{\sqrt{3}}{2} - i\frac{1}{2} \right) = 4 \times \frac{\sqrt{3}}{2} + 4 \times -i\frac{1}{2} = 2\sqrt{3} - 2i \).
05

Final Result

Express the quotient in rectangular form as \( 2\sqrt{3} - 2i \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rectangular Form
When dealing with complex numbers, it's often essential to express them in different forms depending on the operation we want to perform. One of the most common forms is the rectangular form. This form writes a complex number as a combination of its real and imaginary parts, such as \( a + bi \). Here, \( a \) is the real part, and \( bi \) is the imaginary part with \( i \) representing the square root of \(-1\).

For example, if we have a complex number \( 3 + 4i \), \( 3 \) is the real part, and \( 4i \) is the imaginary part.
  • The rectangular form is intuitive when adding or subtracting complex numbers.
  • It's also useful when plotting on a complex plane, where the x-axis represents the real part, and the y-axis represents the imaginary part.
Understanding how to manipulate numbers in rectangular form is key as it serves as a foundation for more complex operations, such as conversion to other forms and division.
Trigonometric Form
Expressing complex numbers in trigonometric form can be quite powerful, especially for multiplication and division operations. This form represents a complex number using its modulus and angle, also called the argument.

A complex number \( z = a + bi \) can be expressed in trigonometric form as \( r (\cos \theta + i \sin \theta) \), where:
  • \( r = \sqrt{a^2 + b^2} \), which is the modulus, representing the distance from the origin in the complex plane.
  • \( \theta = \tan^{-1}(\frac{b}{a}) \), which is the argument or angle, showing the direction of the vector in the complex plane.
For example, if we have \( z = \sqrt{3} + i \), the modulus \( r \) is calculated as 2, and the argument \( \theta \) is \( \frac{\pi}{6} \), making its trigonometric form \( 2(\cos \frac{\pi}{6} + i \sin \frac{\pi}{6}) \).

This form is invaluable when performing operations like multiplication and division, as it simplifies angular manipulation by using angle addition and subtraction properties.
Complex Division
Dividing complex numbers directly in rectangular form can be tricky, but converting them to trigonometric form first makes the process simpler. The division of two complex numbers in trigonometric form follows straightforward rules, making use of both the modulus and argument:

To divide \( \frac{a+bi}{c+di} \), it's helpful to convert first to polar form: if \( z_1 = r_1 (\cos \theta_1 + i \sin \theta_1) \) and \( z_2 = r_2 (\cos \theta_2 + i \sin \theta_2) \), then the division is:
\[ \frac{z_1}{z_2} = \frac{r_1}{r_2} (\cos(\theta_1 - \theta_2) + i \sin(\theta_1 - \theta_2)) \]

This rule states that you divide the moduli and subtract the angles. In our exercise, we noticed the complex division of 8 divided by \( \sqrt{3} + i \) involved these steps:
  • Divide the modulus of the numerator by the modulus of the denominator.
  • Subtract the angle of the numerator from the angle of the denominator.
After calculation, it's essential to express the result back into rectangular form, where it becomes more intuitive to interpret or use for further calculations. This involves evaluating the trigonometric functions for the resulting angle and combining them into components \( a + bi \).

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