Chapter 11: Problem 55
We examine how the three complex cube roots of \(-8\) can be found in two different ways. All complex roots of the equation \(x^{3}+8=0\) are cube roots of \(-8 .\) Factor \(x^{3}+8\) as the sum of two cubes.
Short Answer
Expert verified
The cube roots of \(-8\) are \(-2, 1 + i\sqrt{3},\) and \(1 - i\sqrt{3}.\)
Step by step solution
01
Recognize the form of the expression
The given equation is \(x^3 + 8 = 0\). This can be rewritten as \(x^3 + 2^3\). Recognizing this as a sum of cubes is crucial for factoring.
02
Use the sum of cubes formula
The formula for factoring a sum of cubes is \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\). Here, \(a = x\) and \(b = 2\).
03
Apply the formula to factor
Substitute \(a = x\) and \(b = 2\) into the sum of cubes formula: \(x^3 + 8 = (x + 2)(x^2 - 2x + 4)\). This gives us the factors of the original cubic equation.
04
Solve the linear factor
Set the linear factor equal to zero: \(x + 2 = 0\). Solving for \(x\) gives \(x = -2\), which is one root of the equation.
05
Solve the quadratic factor
Set the quadratic factor equal to zero: \(x^2 - 2x + 4 = 0\). Use the quadratic formula \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\) with \(a = 1\), \(b = -2\), and \(c = 4\).
06
Calculate the discriminant
Calculate the discriminant of the quadratic: \((-2)^2 - 4(1)(4) = 4 - 16 = -12\). The negative discriminant indicates complex roots.
07
Use the quadratic formula
Plug the values into the quadratic formula: \(x = \frac{-(-2) \pm \sqrt{-12}}{2(1)} = \frac{2 \pm \sqrt{12}i}{2}\). Simplifying further gives \(x = 1 \pm i\sqrt{3}\).
08
List all roots
The three roots of \(x^3 + 8 = 0\) are \(x = -2\), \(x = 1 + i\sqrt{3}\), and \(x = 1 - i\sqrt{3}\). These are the cube roots of \(-8\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sum of Cubes
The sum of cubes is a process of factoring an expression that is structured in the form of two perfect cubes being added together, written as \(a^3 + b^3\). This form allows us to use a specific formula to break the expression into a product of two simpler expressions. The key formula is:
- \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\)
Quadratic Formula
The quadratic formula is a powerful tool used to find the roots of any quadratic equation of the form \(ax^2 + bx + c = 0\). The solution involves plugging the coefficients of the quadratic equation into the formula:
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
Complex Roots
Complex roots arise when solving equations yields a negative discriminant, indicating numbers that cannot be plotted on the traditional number line. Essentially, a negative discriminant from the quadratic formula, like our previous example where \(b^2 - 4ac = -12\), signals complex roots. Complex numbers usually take the form \(a + bi\), where \(a\) and \(b\) are real numbers and \(i\) is the imaginary unit, fulfilling \(i^2 = -1\).
For the quadratic \(x^2 - 2x + 4 = 0\), solving it using the quadratic formula yields the complex roots \(x = 1 \pm i\sqrt{3}\). These roots are not only mathematically interesting but also necessary for fully describing the behavior of functions related to the equation \(x^3 + 8 = 0\). Understanding complex roots expands our view of traditional number sets, enabling powerful solutions across various mathematical problems.
For the quadratic \(x^2 - 2x + 4 = 0\), solving it using the quadratic formula yields the complex roots \(x = 1 \pm i\sqrt{3}\). These roots are not only mathematically interesting but also necessary for fully describing the behavior of functions related to the equation \(x^3 + 8 = 0\). Understanding complex roots expands our view of traditional number sets, enabling powerful solutions across various mathematical problems.