Chapter 11: Problem 34
Solve each triangle. \(B=168.2^{\circ}, a=15.1\) centimeters, \(c=19.2\) centimeters
Short Answer
Expert verified
The angles are \(A \approx 9.2^{\circ}\), \(B = 168.2^{\circ}\), \(C = 11.8^{\circ}\) and the sides are \(a = 15.1\) cm, \(b \approx 0.58\) cm, \(c = 19.2\) cm.
Step by step solution
01
Identify the known values
We are given that angle \(B = 168.2^{\circ}\), side \(a = 15.1\) cm, and side \(c = 19.2\) cm. We need to find angle \(A\), angle \(C\), and side \(b\).
02
Use the Law of Sines
The Law of Sines states: \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\). First, calculate \(\sin B\) using the given angle \(B = 168.2^{\circ}\).
03
Calculate \(\sin B\)
Calculate \(\sin B = \sin(168.2^{\circ})\). Use a calculator to find this value: \(\sin 168.2^{\circ} \approx 0.1736\).
04
Find angle \(A\) using the Law of Sines
Using the Law of Sines, \(\frac{a}{\sin A} = \frac{c}{\sin C}\), we rearrange it to find \(\sin A = \frac{a \cdot \sin C}{c}\). However, first we must find \(C\) before \(A\).
05
Find angle \(C\) using angles in a triangle
The sum of angles in any triangle is \(180^{\circ}\). Therefore, \(C = 180^{\circ} - B = 180^{\circ} - 168.2^{\circ} = 11.8^{\circ}\).
06
Use the Law of Sines to find \(A\)
With \(C = 11.8^{\circ}\), use \(\frac{a}{\sin A} = \frac{c}{\sin C}\) to find \(\sin A = \frac{15.1 \cdot \sin 11.8^{\circ}}{19.2}\). Calculate \(\sin 11.8^{\circ} \approx 0.2041\). Thus, \(\sin A \approx 0.1602\).
07
Solve for angle \(A\)
Use \(\sin^{-1}\) to find \(A = \sin^{-1}(0.1602)\). Use a calculator to find \(A \approx 9.2^{\circ}\).
08
Use the Law of Sines to find side \(b\)
Now, using \(\frac{b}{\sin B} = \frac{a}{\sin A}\), solve for \(b\): \(b = \frac{15.1 \cdot \sin 168.2^{\circ}}{\sin 9.2^{\circ}}\). Substitute in the values and find \(b \approx 0.58\) cm.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Law of Sines
The **Law of Sines** is a fundamental principle in trigonometry to solve triangles, especially non-right triangles. It establishes a relationship between the sides of a triangle and their opposite angles. This law is expressed as:
The **Law of Sines** is used when we know:
- \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\)
The **Law of Sines** is used when we know:
- Two angles and one side (AAS or ASA case)
- Two sides and a non-included angle (SSA case)
Triangle Angles
Understanding the **Triangle Angles** principle is crucial for solving any triangle problem. In any triangle, the sum of all interior angles is always \(180^{\circ}\). This is known as the Triangle Sum Theorem and can be a handy way to find unknown angles.
Given that angle \(B = 168.2^{\circ}\) in the problem, the formula is applied as:
Knowing two of the angles directly allows us to find the third angle \(A\) by subtraction when needed, reinforcing the interconnected nature of triangle angles.
Given that angle \(B = 168.2^{\circ}\) in the problem, the formula is applied as:
- \(C = 180^{\circ} - B = 180^{\circ} - 168.2^{\circ}\)
Knowing two of the angles directly allows us to find the third angle \(A\) by subtraction when needed, reinforcing the interconnected nature of triangle angles.
Trigonometric Functions
**Trigonometric Functions** are essential mathematical tools that establish connections between angles and ratios of sides in a triangle. The three primary trigonometric functions are sine (\(\sin\)), cosine (\(\cos\)), and tangent (\(\tan\)). For our problem, knowing sine was particularly useful.
Sine helps relate the angle of a triangle to its opposite side length. For angle \(B\) given in our problem:
Moreover, the inverse sine function, or \(\sin^{-1}\), allows us to retrieve angle values from known sine ratios, such as when we calculated \(A = \sin^{-1}(0.1602) \approx 9.2^{\circ}\). These trigonometric functions help bridge the operations required to solve any triangle effectively.
Sine helps relate the angle of a triangle to its opposite side length. For angle \(B\) given in our problem:
- \(\sin B = \sin(168.2^{\circ}) \approx 0.1736\)
Moreover, the inverse sine function, or \(\sin^{-1}\), allows us to retrieve angle values from known sine ratios, such as when we calculated \(A = \sin^{-1}(0.1602) \approx 9.2^{\circ}\). These trigonometric functions help bridge the operations required to solve any triangle effectively.