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Find all indicated roots and express them in rectangular form. Check your results with a calculator. The cube roots of \(\cos 180^{\circ}+i \sin 180^{\circ}\).

Short Answer

Expert verified
The cube roots are \( \frac{1}{2} + i \frac{\sqrt{3}}{2}, \frac{1}{2} - i \frac{\sqrt{3}}{2}, \text{and } -1.\)

Step by step solution

01

Convert to Exponential Form

First, recognize that the number given is in polar form as \( e^{i\theta} \).Given \( \cos 180^{\circ} + i \sin 180^{\circ} \), we can rewrite this as \( e^{i \pi} \).
02

Find the Principal Cube Root

The principal cube root is found by raising \( e^{i \pi} \) to the power \( \frac{1}{3} \):\[(e^{i \pi})^{\frac{1}{3}} = e^{i \frac{\pi}{3}}\]This simplifies to \( \cos \left( \frac{\pi}{3} \right) + i \sin \left( \frac{\pi}{3} \right) \).
03

Calculate Principal Cube Root

Calculate the cosine and sine values:\[\cos \left( \frac{\pi}{3} \right) = \frac{1}{2}, \quad \sin \left( \frac{\pi}{3} \right) = \frac{\sqrt{3}}{2}\]So, the principal cube root is \( \frac{1}{2} + i \frac{\sqrt{3}}{2} \).
04

Calculate Subsequent Roots

For the nth roots, use the formula for roots of a complex number:\[e^{i(\frac{\theta}{n} + 2k\frac{\pi}{n})} \quad \text{for } k=0, 1, 2\]Calculate for \( k=1 \) and \( k=2 \):- \( k=1 \): \( \cos \left( \frac{5\pi}{3} \right) + i \sin \left( \frac{5\pi}{3} \right) = \frac{1}{2} - i \frac{\sqrt{3}}{2} \)- \( k=2 \): \( \cos \left( \pi \right) + i \sin \left( \pi \right) = -1 \)
05

Verify Roots Using a Calculator

Use a scientific calculator to check that:- \( \frac{1}{2} + i \frac{\sqrt{3}}{2} \)- \( \frac{1}{2} - i \frac{\sqrt{3}}{2} \)- \( -1 \)are indeed the cube roots of \( -1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Form
The exponential form of a complex number provides a powerful and concise way of expressing complex numbers, especially when dealing with powers and roots. It is derived from Euler’s formula, where any complex number with magnitude 1 can be expressed as \( e^{i\theta} \), with \( \theta \) representing the angle in radians.
This form is particularly useful when performing operations like root finding, as it bypasses the need for extensive trigonometric calculations.
In our exercise, the complex number originally in trigonometric form \( \cos 180^{\circ} + i \sin 180^{\circ} \) is converted to exponential form \( e^{i \pi} \).
  • Simplifies calculations by transforming complex multiplication into addition of exponents.
  • Makes finding roots straightforward using De Moivre's theorem, which allows you to handle fractional exponents easily.
This conversion to exponential form is essential in simplifying our work when dealing with complex number operations.
Complex Number
Complex numbers consist of a real part and an imaginary part and are written in the form \( a + bi \), where \( a \) represents the real part, and \( bi \) represents the imaginary part (with \( i \) being the square root of -1).
The unique presence of an imaginary unit allows for the representation of quantities that can't be described using only real numbers, such as the solutions of certain algebraic equations. Complex numbers find applications in diverse fields ranging from engineering to physics.
  • The imaginary unit \( i \) satisfies \( i^2 = -1 \).
  • They can be represented in rectangular form (\( a + bi \)) or polar/exponential form (\( re^{i\theta} \)).
Understanding these numbers is crucial when exploring concepts like cube roots, as it involves turning complex angles into tangible solutions.
Rectangular Form
In the rectangular form, you represent complex numbers using their real and imaginary parts as \( a + bi \). This method is often intuitive, similar to coordinates on a graph where \( a \) is the x-coordinate, and \( bi \) is the y-coordinate.
This form is particularly useful for addition and subtraction of complex numbers, where each component is simply combined arithmetically. However, multiplying and dividing in this form can be cumbersome, which is why conversions to other forms (like exponential or polar) are often used for such operations.
For our example of finding cube roots, after calculations in exponential or polar forms, the result is finally expressed back in rectangular form for clarity:
  • The principal cube root: \( \frac{1}{2} + i \frac{\sqrt{3}}{2} \).
  • Second cube root: \( \frac{1}{2} - i \frac{\sqrt{3}}{2} \).
  • Third cube root: \( -1 \).
This form gives a clear picture of the complex number in terms of its coordinates in the complex plane.
Polar Form
Polar form of a complex number expresses the number in terms of its magnitude and angle, often denoted as \( re^{i\theta} \) where \( r \) is the magnitude and \( \theta \) is the angle in radians.
This representation is ideal for multiplicative operations, as it reduces complex multiplication to simple arithmetic with angles.
The conversion process from rectangular to polar form involves:
  • Calculating the magnitude: \( r = \sqrt{a^2 + b^2} \).
  • Determining the angle: \( \theta = \tan^{-1}(\frac{b}{a}) \) (Adjust angle based on quadrant).
In the context of cube roots, polar representation simplifies the process through the use of De Moivre's Theorem, allowing powers and roots to be handled effortlessly by manipulating angles. The initial complex expression is given in polar form as \( \cos 180^{\circ} + i \sin 180^{\circ} \), which converts directly into \( e^{i\pi} \), setting a straightforward stage for finding its roots.

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