/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 Given vectors u and v, find (a) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Given vectors u and v, find (a) \(2 u\) (b) \(2 u+3 v\) (c) \(v-3 u\) Do not use a calculator. $$\mathbf{u}=-\mathbf{i}+2 \mathbf{j}, \mathbf{v}=\mathbf{i}-\mathbf{j}$$

Short Answer

Expert verified
(a) \(-2\mathbf{i} + 4\mathbf{j}\), (b) \(\mathbf{i} + \mathbf{j}\), (c) \(4\mathbf{i} - 7\mathbf{j}\)."}

Step by step solution

01

Find the Expression for 2u

The vector \(\mathbf{u}\) is given as \(-\mathbf{i} + 2\mathbf{j}\). To find \(2\mathbf{u}\), we multiply each component of \(\mathbf{u}\) by 2:\[2\mathbf{u} = 2(-\mathbf{i}) + 2(2\mathbf{j}) = -2\mathbf{i} + 4\mathbf{j}\]
02

Calculate the Sum 2u + 3v

First, find \(3\mathbf{v}\) by multiplying each component of \(\mathbf{v}\) by 3. Given \(\mathbf{v} = \mathbf{i} - \mathbf{j}\), we have:\[3\mathbf{v} = 3(\mathbf{i} - \mathbf{j}) = 3\mathbf{i} - 3\mathbf{j}\]Next, add \(2\mathbf{u}\) from Step 1 to \(3\mathbf{v}\) to get \(2\mathbf{u} + 3\mathbf{v}\):\[2\mathbf{u} + 3\mathbf{v} = (-2\mathbf{i} + 4\mathbf{j}) + (3\mathbf{i} - 3\mathbf{j}) = (-2\mathbf{i} + 3\mathbf{i}) + (4\mathbf{j} - 3\mathbf{j}) = \mathbf{i} + \mathbf{j}\]
03

Solve the Expression v - 3u

First, compute \(3\mathbf{u}\) by multiplying each component of \(\mathbf{u}\) by 3. Given \(\mathbf{u} = -\mathbf{i} + 2\mathbf{j}\), we get:\[3\mathbf{u} = 3(-\mathbf{i} + 2\mathbf{j}) = -3\mathbf{i} + 6\mathbf{j}\]Now, subtract \(3\mathbf{u}\) from \(\mathbf{v}\) to find \(\mathbf{v} - 3\mathbf{u}\):\[\mathbf{v} - 3\mathbf{u} = (\mathbf{i} - \mathbf{j}) - (-3\mathbf{i} + 6\mathbf{j}) = (\mathbf{i} + 3\mathbf{i}) + (-\mathbf{j} - 6\mathbf{j}) = 4\mathbf{i} - 7\mathbf{j}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Multiplication
Vector multiplication, particularly scalar multiplication, involves multiplying each component of a vector by a scalar (a single number). This operation stretches or shrinks the vector while retaining its direction, unless multiplied by a negative, which reverses it.
Consider the vector \( \mathbf{u} = -\mathbf{i} + 2\mathbf{j} \). To find \( 2\mathbf{u} \), each term in the vector is multiplied by 2:
  • Multiply the \( \mathbf{i} \)-component: \( 2(-\mathbf{i}) = -2\mathbf{i} \).
  • Multiply the \( \mathbf{j} \)-component: \( 2(2\mathbf{j}) = 4\mathbf{j} \).
After performing these operations, the result is \( 2\mathbf{u} = -2\mathbf{i} + 4\mathbf{j} \). This demonstrates how scalar multiplication can modify a vector's magnitude while maintaining its inherent properties.
Vector Addition
Vector addition combines two vectors to produce a third vector, called the resultant. Each corresponding component of the vectors is added together. This operation can be visualized as placing the tail of the second vector at the head of the first and drawing a vector from the tail of the first to the head of the second.
For example, with vectors \( 2\mathbf{u} = -2\mathbf{i} + 4\mathbf{j} \) and \( 3\mathbf{v} = 3\mathbf{i} - 3\mathbf{j} \), the addition is performed on the components:
  • Add the \( \mathbf{i} \)-components: \( -2\mathbf{i} + 3\mathbf{i} = \mathbf{i} \).
  • Add the \( \mathbf{j} \)-components: \( 4\mathbf{j} - 3\mathbf{j} = \mathbf{j} \).
Hence, \( 2\mathbf{u} + 3\mathbf{v} = \mathbf{i} + \mathbf{j} \), creating a new vector with components derived from the sums of respective parts of \( \mathbf{u} \) and \( \mathbf{v} \).
Vector Subtraction
Vector subtraction finds the difference between two vectors by reversing the direction of the vector being subtracted and then performing vector addition. Seen another way, it involves subtracting each component of the second vector from the corresponding component of the first.
To illustrate this, consider \( \mathbf{v} - 3\mathbf{u} \). Start with \( \mathbf{v} = \mathbf{i} - \mathbf{j} \) and \( 3\mathbf{u} = -3\mathbf{i} + 6\mathbf{j} \). The subtraction goes as follows:
  • Subtract the \( \mathbf{i} \)-components: \( \mathbf{i} - (-3\mathbf{i}) = \mathbf{i} + 3\mathbf{i} = 4\mathbf{i} \).
  • Subtract the \( \mathbf{j} \)-components: \( -\mathbf{j} - 6\mathbf{j} = -7\mathbf{j} \).
After calculation, we arrive at \( 4\mathbf{i} - 7\mathbf{j} \). This operation effectively determines the resultant vector by offsetting the influence of one vector on another.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find a rectangular equation for each curve and graph the curve. $$x=2+\sin t, y=1+\cos t ; \text { for } t \text { in }[0,2 \pi]$$

Find each quotient and express it in rectangular form by first converting the numerator and the denominator to trigonometric form. $$\frac{1}{2-2 i}$$

For each plane curve, (a) graph the curve, and (b) find a rectangular equation for the curve. $$x=t^{2}, y=\sqrt{t} ; \text { for } t \text { in }[0,4]$$

For each equation, find an equivalent equation in rectangular coordinates. Then graph the result. $$r=\frac{2}{2 \cos \theta+\sin \theta}$$

Radio stations sometimes do not broadcast in all directions with the same intensity. To avoid interference with an existing station to the north, a new station may be licensed to broadcast only east and west. To create an east- west signal, two radio towers are used, as illustrated in the figure. (IMAGE CAN'T COPY). Locations where the radio signal is received correspond to the interior of the lemniscate..$$r^{2}=40,000 \cos 2 \theta$$.Where the polar axis (or positive \(x\) -axis) points east. (A) Graph $$r^{2}=40.000 \cos 2 \theta$$. For \(0^{\circ} \leq \theta \leq 180^{\circ},\) with units in miles. Assuming that the radio towers are located near the pole, use the graph to describe the regions where the signal can be received and where the signal cannot be received. (B) Suppose a radio signal pattern is given by $$r^{2}=22,500 \sin 2 \theta$$ for \(0^{\circ} \leq \theta \leq 180^{\circ} .\) Graph this pattem and interpret the results.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.